Sequence creation methods in Kotlin - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a sequence from a list.

Kotlin

val numbers = listOf(1, 2, 3, 4, 5)
val seq = numbers.[1]()

Drag options to blanks, or click blank then click option'

AasSequence

BtoSequence

CgenerateSequence

DsequenceOf

Attempts:

3 left

💡 Hint

Common Mistakes

Using sequenceOf() which creates a sequence from given elements, not from a list.

Trying to call toSequence() which does not exist.

The asSequence() function converts a collection into a sequence.

2fill in blank

medium

Complete the code to create a sequence of numbers starting from 1.

Kotlin

val seq = [1](1) { it + 1 }

Drag options to blanks, or click blank then click option'

AsequenceOf

BlistOf

CasSequence

DgenerateSequence

Attempts:

3 left

💡 Hint

Common Mistakes

Using sequenceOf() which creates a sequence from fixed elements.

Using asSequence() which converts collections but does not generate sequences.

The generateSequence() function creates a sequence by generating values starting from the initial value.

3fill in blank

hard

Fix the error in the code to create a sequence from given elements.

Kotlin

val seq = [1](1, 2, 3, 4, 5)

Drag options to blanks, or click blank then click option'

AsequenceOf

BgenerateSequence

CasSequence

DlistOf

Attempts:

3 left

💡 Hint

Common Mistakes

Using asSequence() which converts collections but does not accept varargs.

Using listOf() which creates a list, not a sequence.

The sequenceOf() function creates a sequence from the given elements.

4fill in blank

hard

Fill both blanks to create a sequence from a list and filter even numbers.

Kotlin

val numbers = listOf(1, 2, 3, 4, 5)
val evenSeq = numbers.[1]().filter { it [2] 2 == 0 }

Drag options to blanks, or click blank then click option'

AasSequence

BtoSequence

C%

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using toSequence() which does not exist.

Using '==' instead of '%' for checking even numbers.

Use asSequence() to convert the list, then filter numbers where the remainder when divided by 2 is zero.

5fill in blank

hard

Fill all three blanks to create a sequence of squares of numbers from 1 to 5, filtering those greater than 10.

Kotlin

val seq = (1..5).[1]().map { it [2] it }.filter { it [3] 10 }

Drag options to blanks, or click blank then click option'

AasSequence

B*

C>

DsequenceOf

Attempts:

3 left

💡 Hint

Common Mistakes

Using sequenceOf() instead of asSequence() on a range.

Using '+' instead of '*' for squaring.

Using '<' instead of '>' for filtering.

Convert the range to a sequence, map each number to its square using '*', then filter numbers greater than 10.