Why Async and await for concurrent results in Kotlin? - Purpose & Use Cases

The Big Idea

What if your program could do many things at once and finish faster without extra effort?

The Scenario

Imagine you need to fetch data from three different websites one after another. You write code that waits for the first website to respond before moving to the second, then the third. This makes your program slow and boring, like waiting in three long lines one by one.

The Problem

Doing tasks one by one wastes time because your program sits idle waiting for each task to finish. It's like standing in line at a coffee shop three times instead of ordering all drinks at once. Also, it's easy to make mistakes managing all these waiting steps manually.

The Solution

Using async and await lets your program start all tasks at the same time and then wait for all results together. It's like ordering all your drinks at once and picking them up when ready. This saves time and keeps your code clean and easy to understand.

Before vs After

✗ Before

val result1 = fetchData1()
val result2 = fetchData2()
val result3 = fetchData3()

✓ After

val deferred1 = async { fetchData1() }
val deferred2 = async { fetchData2() }
val deferred3 = async { fetchData3() }
val result1 = deferred1.await()
val result2 = deferred2.await()
val result3 = deferred3.await()

What It Enables

You can run many tasks at the same time and get all results faster, making your apps quicker and more responsive.

Real Life Example

Imagine a weather app that fetches temperature, humidity, and wind speed from different servers. Using async and await, it gets all data together quickly, so you see the full weather report without waiting long.

Key Takeaways

Manual waiting slows down programs and is error-prone.

Async and await let tasks run together, saving time.

This makes code cleaner and apps faster.

Practice

1. What does the async function do in Kotlin coroutines?

easy

A. Starts a background task that runs concurrently

B. Waits for a task to complete and returns its result

C. Blocks the main thread until a task finishes

D. Cancels a running coroutine immediately

Solution

1. Step 1: Understand the role of async

   async starts a coroutine that runs in the background without blocking the main thread.

2. Step 2: Differentiate from await

   await waits for the result of the background task started by async, but async itself only starts the task.

3. Final Answer:

   Starts a background task that runs concurrently -> Option A

4. Quick Check:

   async = starts background task [OK]

Hint: Async starts tasks without waiting, await waits for results [OK]

Common Mistakes:

• Confusing async with await
• Thinking async blocks the main thread
• Assuming async cancels tasks

2. Which of the following is the correct syntax to start two concurrent tasks and wait for both results in Kotlin?

easy

A. val result1 = async { task1() }.await()
val result2 = async { task2() }.await()

B. val result1 = await(async { task1() })
val result2 = await(async { task2() })

C. val deferred1 = async { task1() }
val deferred2 = async { task2() }
val result1 = deferred1.await()
val result2 = deferred2.await()

D. val result1 = task1()
val result2 = task2()

Solution

1. Step 1: Identify correct async-await usage

   In Kotlin, async returns a Deferred object, which you then call await() on to get the result.

2. Step 2: Check syntax correctness

   val deferred1 = async { task1() } val deferred2 = async { task2() } val result1 = deferred1.await() val result2 = deferred2.await() correctly starts two async tasks and awaits their results separately, allowing concurrency.

3. Final Answer:

   val deferred1 = async { task1() } val deferred2 = async { task2() } val result1 = deferred1.await() val result2 = deferred2.await() -> Option C

4. Quick Check:

   async returns Deferred, await gets result [OK]

Hint: Store async in Deferred, then call await separately [OK]

Common Mistakes:

• Calling await immediately after async (no concurrency)
• Using await as a standalone function
• Not storing async result before await

3. What will be the output of the following Kotlin code?

import kotlinx.coroutines.*

fun main() = runBlocking {
    val deferred1 = async {
        delay(100)
        10
    }
    val deferred2 = async {
        delay(50)
        20
    }
    println(deferred1.await() + deferred2.await())
}

medium

A. 10

B. 30

C. 20

D. Compilation error

Solution

1. Step 1: Understand async and delay behavior

   Two async tasks run concurrently: one delays 100ms and returns 10, the other delays 50ms and returns 20.

2. Step 2: Await both results and sum

   Awaiting both deferreds gets 10 and 20, summing to 30, printed as output.

3. Final Answer:

   30 -> Option B

4. Quick Check:

   10 + 20 = 30 [OK]

Hint: Sum awaited results after async tasks complete [OK]

Common Mistakes:

• Assuming sequential execution ignoring concurrency
• Confusing delay times with output values
• Expecting compilation errors due to coroutines

4. Identify the error in this Kotlin coroutine code snippet:

fun main() = runBlocking {
    val result = async {
        delay(100)
        42
    }.await()
    println(result)
}

medium

A. Calling await() immediately after async() blocks concurrency

B. Missing coroutine scope for async

C. delay() cannot be used inside async

D. runBlocking cannot be used in main function

Solution

1. Step 1: Analyze async and await usage

   Calling await() immediately after async waits for the task to finish before continuing, so concurrency is lost.

2. Step 2: Understand concurrency impact

   This pattern runs the async task sequentially, blocking until completion, defeating the purpose of async concurrency.

3. Final Answer:

   Calling await() immediately after async() blocks concurrency -> Option A

4. Quick Check:

   Immediate await blocks concurrency [OK]

Hint: Don't await right after async; store Deferred first [OK]

Common Mistakes:

• Thinking immediate await keeps concurrency
• Believing delay is disallowed inside async
• Assuming runBlocking can't be main

5. You want to fetch data from two APIs concurrently and combine their results in Kotlin. Which approach best uses async and await for this task?

hard

A. Call the first API synchronously, then start async for the second API and await it

B. Run both API calls sequentially inside async blocks without await

C. Use await without async for both API calls to simplify code

D. Start two async coroutines for each API call, then await both results before combining

Solution

1. Step 1: Understand concurrency for API calls

   Starting both API calls concurrently with async allows them to run at the same time, saving time.

2. Step 2: Await both results before combining

   Using await on both deferred results ensures you get both responses before combining them safely.

3. Final Answer:

   Start two async coroutines for each API call, then await both results before combining -> Option D

4. Quick Check:

   Async start + await both = concurrent fetch [OK]

Hint: Async both calls, await both results, then combine [OK]

Common Mistakes:

• Running API calls sequentially losing concurrency
• Using await without async causing errors
• Not awaiting results before combining