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Javascriptprogramming~15 mins

Await keyword behavior in Javascript - Mini Project: Build & Apply

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Await Keyword Behavior
📖 Scenario: Imagine you are building a simple web app that fetches user data from a server. You want to learn how to wait for the data to arrive before using it.
🎯 Goal: You will create a function that simulates fetching data asynchronously and use the await keyword to wait for the data before printing it.
📋 What You'll Learn
Create an asynchronous function called fetchUserData that returns a promise resolving to the string 'User data loaded' after 1 second.
Create an asynchronous function called showUserData.
Inside showUserData, use await to wait for fetchUserData to complete and store the result in a variable called data.
Print the value of data using console.log.
💡 Why This Matters
🌍 Real World
Waiting for data from servers or APIs is common in web apps. Using <code>await</code> helps write clear code that waits for data before continuing.
💼 Career
Understanding <code>async</code> and <code>await</code> is essential for frontend and backend developers working with asynchronous data fetching.
Progress0 / 4 steps
1
Create the asynchronous function fetchUserData
Write an asynchronous function called fetchUserData that returns a promise which resolves to the string 'User data loaded' after 1 second using setTimeout.
Javascript
Hint

Use new Promise inside the async function and setTimeout to delay the resolve by 1000 milliseconds.

2
Create the asynchronous function showUserData
Write an asynchronous function called showUserData that will later use await to get data.
Javascript
Hint

Just create the function with the async keyword and empty body for now.

3
Use await inside showUserData to get data
Inside the showUserData function, use await to wait for fetchUserData() and store the result in a variable called data.
Javascript
Hint

Use const data = await fetchUserData(); inside the function body.

4
Print the awaited data using console.log
Add a line inside showUserData to print the variable data using console.log. Then call showUserData() to run the code.
Javascript
Hint

Use console.log(data); inside showUserData and call showUserData(); after the function.

Practice

(1/5)
1. What does the await keyword do in JavaScript?
easy
A. Makes a function synchronous
B. Pauses the execution until a Promise resolves
C. Creates a new Promise
D. Throws an error if used outside a function

Solution

  1. Step 1: Understand the role of await

    The await keyword pauses the execution of an async function until the Promise it waits for settles (resolves or rejects).
  2. Step 2: Differentiate from other options

    await does not make a function synchronous or create a Promise; it only pauses execution inside async functions.
  3. Final Answer:

    Pauses the execution until a Promise resolves -> Option B
  4. Quick Check:

    await pauses execution [OK]
Hint: Remember: await pauses until Promise finishes [OK]
Common Mistakes:
  • Thinking await makes functions synchronous
  • Believing await creates Promises
  • Using await outside async functions without error
2. Which of the following is the correct way to use await in JavaScript?
easy
A. const result = fetchData(); await;
B. await const result = fetchData();
C. const result = fetchData() await;
D. const result = await fetchData();

Solution

  1. Step 1: Check correct syntax for await

    The correct syntax places await before the Promise-returning function call, like await fetchData().
  2. Step 2: Identify invalid syntax

    Options A, B, and C misuse await placement, causing syntax errors.
  3. Final Answer:

    const result = await fetchData(); -> Option D
  4. Quick Check:

    await goes before the Promise call [OK]
Hint: Put await right before the Promise call [OK]
Common Mistakes:
  • Placing await after the function call
  • Trying to declare variables with await keyword
  • Adding await as a separate statement
3. What will be the output of this code?
async function test() {
  const p = new Promise(resolve => setTimeout(() => resolve('Done'), 100));
  const result = await p;
  console.log(result);
}
test();
medium
A. Done
B. Promise { <pending> }
C. undefined
D. Error: await used outside async function

Solution

  1. Step 1: Understand the Promise and await

    The Promise resolves after 100ms with the string 'Done'. The await pauses until this resolution.
  2. Step 2: Check console.log output

    After awaiting, result holds 'Done', so console.log(result) prints 'Done'.
  3. Final Answer:

    Done -> Option A
  4. Quick Check:

    Await waits for Promise result [OK]
Hint: Await unwraps Promise value before logging [OK]
Common Mistakes:
  • Expecting Promise object instead of resolved value
  • Confusing async function call with synchronous
  • Thinking await causes errors outside async
4. Identify the error in this code snippet:
function fetchData() {
  return new Promise(resolve => setTimeout(() => resolve('Data'), 50));
}
const data = await fetchData();
console.log(data);
medium
A. Missing async keyword before function
B. Promise never resolves
C. Cannot use await outside async function
D. Syntax error in Promise constructor

Solution

  1. Step 1: Check where await is used

    await is used at the top level, outside any async function, which is not allowed in standard JavaScript.
  2. Step 2: Identify correct error cause

    This causes a runtime syntax error because await must be inside an async function.
  3. Final Answer:

    Cannot use await outside async function -> Option C
  4. Quick Check:

    Await only inside async functions [OK]
Hint: Use await only inside async functions [OK]
Common Mistakes:
  • Assuming await works globally
  • Thinking async keyword is needed on fetchData only
  • Believing Promise never resolves
5. You want to fetch user data and then fetch posts by that user sequentially using async/await. Which code correctly ensures the posts are fetched only after user data is available?
async function getUserAndPosts() {
  const user = await fetchUser();
  const posts = fetchPosts(user.id);
  return posts;
}
hard
A. Add await before fetchPosts: const posts = await fetchPosts(user.id);
B. Remove await from fetchUser to run both in parallel
C. Return posts without awaiting to speed up
D. Use Promise.all with fetchUser and fetchPosts

Solution

  1. Step 1: Analyze the sequence requirement

    Posts must be fetched only after user data is ready, so fetchPosts must wait for user.
  2. Step 2: Check code for awaiting posts

    Currently, fetchPosts is called without await, so it returns a Promise immediately without waiting.
  3. Step 3: Correct usage

    Adding await before fetchPosts ensures posts are fetched after user data is available.
  4. Final Answer:

    Add await before fetchPosts: const posts = await fetchPosts(user.id); -> Option A
  5. Quick Check:

    Await each dependent async call [OK]
Hint: Await each async call that depends on previous result [OK]
Common Mistakes:
  • Not awaiting dependent async calls
  • Trying to run dependent calls in parallel
  • Using Promise.all incorrectly for sequential tasks
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10 questions~5 mineasy hard