Prototype chain in Javascript

Introduction

The prototype chain helps JavaScript objects share features like properties and functions. It works like a family tree where objects can borrow things from their parents.

When you want many objects to share the same behavior without copying code.

When you want to find a property or method that an object does not have directly.

When you want to create new objects based on existing ones and add or change features.

When debugging to understand where a property or method is coming from.

When using built-in objects like arrays or strings and want to know how their methods work.

Syntax

Javascript

object.__proto__
// or
Object.getPrototypeOf(object)

__proto__ is a way to access an object's prototype, but it's better to use Object.getPrototypeOf() for clarity.

The prototype chain ends when an object has null as its prototype.

Examples

The child object does not have greet itself, so JavaScript looks up the prototype chain to parent and finds it.

Javascript

const parent = { greet() { return 'Hello'; } };
const child = Object.create(parent);
console.log(child.greet());

Arrays inherit methods like toString from Array.prototype through the prototype chain.

Javascript

const arr = [];
console.log(arr.toString());

This shows that parent is the prototype of child.

Javascript

console.log(Object.getPrototypeOf(child) === parent);

Sample Program

Here, dog does not have its own speak method, so it uses the one from animal via the prototype chain.

Javascript

const animal = {
  speak() {
    return `${this.name} makes a sound.`;
  }
};

const dog = Object.create(animal);
dog.name = 'Buddy';
console.log(dog.speak());

Important Notes

Every object in JavaScript has a prototype except the base object which has null as its prototype.

Changing the prototype of an object after creation is possible but can slow down your code, so it's best to set it when creating the object.

Use Object.create() to create a new object with a specific prototype easily.

Summary

The prototype chain lets objects share properties and methods.

JavaScript looks up the chain to find missing properties or methods.

Use Object.create() and Object.getPrototypeOf() to work with prototypes clearly.

Practice

1. What does the prototype chain in JavaScript help with?

easy

A. Sharing properties and methods between objects

B. Creating new variables automatically

C. Running code faster

D. Stopping code execution

Solution

1. Step 1: Understand prototype chain purpose

   The prototype chain allows objects to share properties and methods by linking them.

2. Step 2: Identify correct description

   Sharing properties and methods matches the prototype chain's role, unlike other options.

3. Final Answer:

   Sharing properties and methods between objects -> Option A

4. Quick Check:

   Prototype chain = Sharing properties and methods [OK]

Hint: Prototype chain shares properties/methods between objects [OK]

Common Mistakes:

• Thinking it creates variables
• Assuming it speeds up code
• Believing it stops code

2. Which of the following is the correct way to create an object with a specific prototype in JavaScript?

easy

A. let obj = prototypeObj.create();

B. let obj = Object.create(prototypeObj);

C. let obj = new Object(prototypeObj);

D. let obj = Object.prototype(prototypeObj);

Solution

1. Step 1: Recall Object.create syntax

   Object.create(prototypeObj) creates a new object with prototypeObj as its prototype.

2. Step 2: Check other options

   Other options use incorrect syntax or methods that don't exist.

3. Final Answer:

   let obj = Object.create(prototypeObj); -> Option B

4. Quick Check:

   Object.create() creates object with prototype [OK]

Hint: Use Object.create(prototype) to set prototype correctly [OK]

Common Mistakes:

• Using new Object() with prototype argument
• Calling create() on prototype object
• Trying to call Object.prototype as a function

3. What will be the output of this code?

const parent = { greet() { return 'Hello'; } };
const child = Object.create(parent);
console.log(child.greet());

medium

A. undefined

B. null

C. TypeError

D. 'Hello'

Solution

1. Step 1: Understand prototype lookup

   child has no greet method, so JavaScript looks up to parent where greet exists.

2. Step 2: Call greet method from parent

   Calling child.greet() runs parent.greet(), returning 'Hello'.

3. Final Answer:

   'Hello' -> Option D

4. Quick Check:

   Prototype lookup finds greet() = 'Hello' [OK]

Hint: If property missing, JS checks prototype chain [OK]

Common Mistakes:

• Expecting undefined because child lacks greet
• Thinking it causes error
• Assuming null is returned

4. Find the error in this code snippet:

const animal = { eats: true };
const rabbit = Object.create(animal);
rabbit.eats = false;
console.log(rabbit.eats);
console.log(animal.eats);

medium

A. No error; output is as expected

B. Object.create should not be used here

C. rabbit.eats does not override animal.eats

D. animal.eats is changed to false

Solution

1. Step 1: Understand property shadowing

   Setting rabbit.eats creates a new property on rabbit, shadowing animal.eats.

2. Step 2: Check outputs

   rabbit.eats logs false; animal.eats remains true. This is expected behavior.

3. Final Answer:

   No error; output is as expected -> Option A

4. Quick Check:

   Property shadowing works correctly [OK]

Hint: Setting property on child shadows parent's property [OK]

Common Mistakes:

• Thinking parent's property changes
• Believing Object.create is wrong here
• Expecting error from property override

5. You want to create a chain where child inherits from parent, and parent inherits from grandparent. Which code correctly sets this prototype chain?

hard

A. const grandparent = {};
const parent = Object.create(child);
const child = Object.create(parent);

B. const grandparent = {};
const parent = {};
const child = Object.create(parent);
child.__proto__ = grandparent;

C. const grandparent = {};
const parent = Object.create(grandparent);
const child = Object.create(parent);

D. const grandparent = {};
const parent = Object.create(grandparent);
const child = Object.create(grandparent);

Solution

1. Step 1: Set parent prototype to grandparent

   Using Object.create(grandparent) for parent sets grandparent as prototype.

2. Step 2: Set child prototype to parent

   Using Object.create(parent) for child sets parent as prototype, completing chain.

3. Step 3: Check other options

   B incorrectly overrides child's prototype to grandparent using __proto__, skipping parent; C creates a circular reference (child not defined when creating parent); D sets child directly to grandparent, skipping parent.

4. Final Answer:

   const grandparent = {}; const parent = Object.create(grandparent); const child = Object.create(parent); -> Option C

5. Quick Check:

   Prototype chain: child -> parent -> grandparent [OK]

Hint: Use Object.create in order from top to bottom [OK]

Common Mistakes:

• Setting child prototype to grandparent directly
• Reversing prototype chain order
• Using __proto__ instead of Object.create