Switch vs if comparison in Java - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the day name using switch.

Java

int day = 3;
switch(day) {
    case 1:
        System.out.println("Monday");
        break;
    case 2:
        System.out.println("Tuesday");
        break;
    case [1]:
        System.out.println("Wednesday");
        break;
    default:
        System.out.println("Other day");
}

Drag options to blanks, or click blank then click option'

A3

B4

C5

D6

Attempts:

3 left

💡 Hint

Common Mistakes

Using a wrong case number that does not match the day variable.

Forgetting the break statement after the case.

The case for day 3 should print "Wednesday". So, the blank must be filled with 3.

2fill in blank

medium

Complete the if statement to check if the variable 'score' is greater than or equal to 90.

Java

int score = 95;
if (score [1] 90) {
    System.out.println("Excellent");
} else {
    System.out.println("Keep trying");
}

Drag options to blanks, or click blank then click option'

A>=

B<

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>='.

Using '==' which checks for equality only.

To check if score is greater than or equal to 90, use '>=' operator.

3fill in blank

hard

Fix the error in the switch statement to correctly handle the variable 'option'.

Java

char option = 'B';
switch([1]) {
    case 'A':
        System.out.println("Option A selected");
        break;
    case 'B':
        System.out.println("Option B selected");
        break;
    default:
        System.out.println("Invalid option");
}

Drag options to blanks, or click blank then click option'

AOption

Boption

C'option'

Doptions

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name with wrong capitalization.

Putting the variable name in quotes, making it a char literal.

The switch must use the variable 'option' exactly as declared, case sensitive and without quotes.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

Java

Map<String, Integer> wordLengths = words.stream()
    .filter(word -> word.length() [1] 3)
    .collect(Collectors.toMap(word -> word, word -> word.[2]()));

Drag options to blanks, or click blank then click option'

A>

Blength()

CtoUpperCase()

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' in filter.

Using toUpperCase() instead of length() for value mapping.

The filter should keep words with length greater than 3, so use '>'. The value mapper uses word.length() to get length.

5fill in blank

hard

Fill all three blanks to create a switch statement that prints the season name based on the month number.

Java

int month = 4;
switch (month) {
    case [1]:
    case [2]:
    case [3]:
        System.out.println("Spring");
        break;
    default:
        System.out.println("Other season");
}

Drag options to blanks, or click blank then click option'

A3

B4

C5

D6

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong month numbers for Spring.

Not grouping multiple cases before break.

Months 3, 4, and 5 correspond to Spring season, so these cases print "Spring".