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Javaprogramming~5 mins

Reading string input in Java - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What class in Java is commonly used to read string input from the user?
The <strong>Scanner</strong> class is commonly used to read string input from the user in Java.
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beginner
How do you create a Scanner object to read input from the keyboard?
You create it with: Scanner scanner = new Scanner(System.in); This connects the Scanner to the keyboard input.
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beginner
Which Scanner method reads a whole line of text including spaces?
The method nextLine() reads the entire line of input including spaces until the user presses Enter.
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beginner
What happens if you use next() instead of nextLine() to read a string?
next() reads only the next word (up to the first space), not the whole line.
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intermediate
Why should you close the Scanner object after use?
Closing the Scanner with scanner.close(); frees system resources and avoids resource leaks.
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Which method reads a full line of user input including spaces?
Ainput()
Bnext()
CnextLine()
DreadLine()
How do you create a Scanner to read from the keyboard?
AScanner scanner = new Scanner(System.in);
BScanner scanner = new Scanner(System.out);
CScanner scanner = new Scanner(System.err);
DScanner scanner = new Scanner(System.in.read());
What does next() method read from input?
AThe next word (up to space)
BThe entire line
CThe next character
DNothing, it throws error
Why is it important to close a Scanner object?
ATo speed up input reading
BTo free system resources
CTo clear the input buffer
DIt is not important
Which import statement is needed to use Scanner?
Aimport java.util.Input;
Bimport java.io.Scanner;
Cimport java.lang.Scanner;
Dimport java.util.Scanner;
Explain how to read a full line of string input from the user in Java.
Think about connecting Scanner to keyboard and reading the entire line.
You got /3 concepts.
    What is the difference between next() and nextLine() methods in Scanner?
    Consider how spaces affect what each method reads.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is the correct way to read a full line of text input from the user in Java?
      easy
      A. Use Scanner.nextLine() method
      B. Use Scanner.nextInt() method
      C. Use System.out.println() method
      D. Use Scanner.read() method

      Solution

      1. Step 1: Understand Scanner methods

        The Scanner class has different methods to read input. nextLine() reads the entire line as a string.
      2. Step 2: Identify the correct method for full line input

        nextInt() reads only integers, System.out.println() prints output, and Scanner.read() does not exist. So, nextLine() is correct.
      3. Final Answer:

        Use Scanner.nextLine() method -> Option A
      4. Quick Check:

        Read full line = nextLine() [OK]
      Hint: Use nextLine() to read full text line input [OK]
      Common Mistakes:
      • Using nextInt() to read strings
      • Confusing output methods with input
      • Forgetting to import Scanner
      2. Which of the following is the correct syntax to create a Scanner object to read input from the keyboard?
      easy
      A. Scanner input = new Scanner(System.out);
      B. Scanner input = new Scanner(System.file);
      C. Scanner input = new Scanner(System.err);
      D. Scanner input = new Scanner(System.in);

      Solution

      1. Step 1: Understand Scanner constructor

        The Scanner constructor takes an InputStream to read from. System.in is the standard input stream (keyboard).
      2. Step 2: Identify correct stream for keyboard input

        System.out and System.err are output streams, and System.file does not exist. So, new Scanner(System.in) is correct.
      3. Final Answer:

        Scanner input = new Scanner(System.in); -> Option D
      4. Quick Check:

        Keyboard input = System.in [OK]
      Hint: Use System.in to read keyboard input with Scanner [OK]
      Common Mistakes:
      • Using System.out or System.err instead of System.in
      • Trying to read from non-existent System.file
      • Missing parentheses in Scanner constructor
      3. What will be the output of the following Java code if the user inputs: Hello World
      import java.util.Scanner;
      public class Main {
        public static void main(String[] args) {
          Scanner sc = new Scanner(System.in);
          String text = sc.nextLine();
          System.out.println(text);
          sc.close();
        }
      }
      medium
      A. Hello
      B. Hello World
      C. World
      D. Compilation error

      Solution

      1. Step 1: Understand nextLine() behavior

        The nextLine() method reads the entire line including spaces until the user presses Enter.
      2. Step 2: Analyze the input and output

        User inputs "Hello World" and presses Enter. The program reads the full line and prints it exactly.
      3. Final Answer:

        Hello World -> Option B
      4. Quick Check:

        nextLine() reads full line = Hello World [OK]
      Hint: nextLine() reads entire line including spaces [OK]
      Common Mistakes:
      • Assuming nextLine() reads only first word
      • Confusing next() with nextLine()
      • Forgetting to close Scanner
      4. Identify the error in the following code snippet that reads a string input from the user:
      import java.util.Scanner;
      public class Test {
        public static void main(String[] args) {
          Scanner sc = new Scanner(System.in);
          String name = sc.next();
          System.out.println(name);
          sc.close();
        }
      }

      What is the problem if the user inputs "John Doe"?
      medium
      A. The program does not compile
      B. The program throws a runtime exception
      C. The program reads only "John" and ignores "Doe"
      D. The program reads the full line "John Doe" correctly

      Solution

      1. Step 1: Understand difference between next() and nextLine()

        next() reads input only until the first space, so it reads "John" only.
      2. Step 2: Analyze input and output behavior

        User inputs "John Doe" but next() stops at space, so "Doe" is ignored in this read.
      3. Final Answer:

        The program reads only "John" and ignores "Doe" -> Option C
      4. Quick Check:

        next() reads until space = partial input [OK]
      Hint: Use nextLine() to read full input with spaces [OK]
      Common Mistakes:
      • Using next() when full line is needed
      • Expecting next() to read multiple words
      • Not testing with multi-word input
      5. You want to read multiple lines of user input until the user types "exit". Which code snippet correctly implements this using Scanner and nextLine()?
      hard
      A. Scanner sc = new Scanner(System.in); String line; do { line = sc.nextLine(); System.out.println(line); } while (!line.equals("exit")); sc.close();
      B. Scanner sc = new Scanner(System.in); while (sc.nextLine() != "exit") { System.out.println(sc.nextLine()); } sc.close();
      C. Scanner sc = new Scanner(System.in); String line = sc.next(); while (!line.equals("exit")) { System.out.println(line); line = sc.next(); } sc.close();
      D. Scanner sc = new Scanner(System.in); while (true) { String line = sc.nextLine(); if (line == "exit") break; System.out.println(line); } sc.close();

      Solution

      1. Step 1: Understand string comparison in Java

        Use line.equals("exit") to compare strings, not ==.
      2. Step 2: Analyze loop structure and input reading

        Scanner sc = new Scanner(System.in); String line; do { line = sc.nextLine(); System.out.println(line); } while (!line.equals("exit")); sc.close(); uses a do-while loop reading input once per iteration and compares correctly. Scanner sc = new Scanner(System.in); while (sc.nextLine() != "exit") { System.out.println(sc.nextLine()); } sc.close(); reads twice per loop and uses != with strings (wrong). Scanner sc = new Scanner(System.in); String line = sc.next(); while (!line.equals("exit")) { System.out.println(line); line = sc.next(); } sc.close(); uses next() which reads only one word. Scanner sc = new Scanner(System.in); while (true) { String line = sc.nextLine(); if (line == "exit") break; System.out.println(line); } sc.close(); uses == for string comparison (wrong).
      3. Final Answer:

        The do-while loop with equals("exit") -> Option A
      4. Quick Check:

        Use equals() and read once per loop [OK]
      Hint: Use equals() for string compare and read input once per loop [OK]
      Common Mistakes:
      • Using == instead of equals() for strings
      • Reading input multiple times per loop
      • Using next() instead of nextLine() for full lines
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