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Javaprogramming~15 mins

Primitive data types in Java - Mini Project: Build & Apply

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Primitive Data Types in Java
📖 Scenario: You are creating a simple Java program to store and display basic information about a product using primitive data types.
🎯 Goal: Build a Java program that declares variables with primitive data types, assigns values, and prints them.
📋 What You'll Learn
Declare variables using Java primitive data types: int, double, char, and boolean
Assign specific values to each variable
Print the values to the console
💡 Why This Matters
🌍 Real World
Primitive data types are used to store simple data like numbers, letters, and true/false values in many programs.
💼 Career
Understanding primitive data types is essential for any Java developer to handle data efficiently and write clear code.
Progress0 / 4 steps
1
Declare primitive variables
Declare a variable called productId of type int and set it to 101.
Java
Hint

Use int for whole numbers like IDs.

2
Add more primitive variables
Declare a variable called price of type double and set it to 29.99. Also declare a variable called inStock of type boolean and set it to true.
Java
Hint

Use double for decimal numbers and boolean for true/false values.

3
Add a character variable
Declare a variable called category of type char and set it to the letter 'E'.
Java
Hint

Use single quotes ' ' for char values.

4
Print all variables
Use System.out.println to print the values of productId, price, inStock, and category each on a new line.
Java
Hint

Use separate System.out.println statements for each variable.

Practice

(1/5)
1. Which of the following is NOT a primitive data type in Java?
easy
A. char
B. boolean
C. int
D. String

Solution

  1. Step 1: Recall Java primitive types

    Java primitive types include int, boolean, char, byte, short, long, float, and double.
  2. Step 2: Identify non-primitive type

    String is a class in Java, not a primitive type.
  3. Final Answer:

    String -> Option D
  4. Quick Check:

    Primitive types exclude classes like String [OK]
Hint: Remember primitives are simple types, not objects like String [OK]
Common Mistakes:
  • Confusing String as primitive
  • Thinking boolean is not primitive
  • Mixing wrapper classes with primitives
2. Which of the following is the correct way to declare a variable of type byte in Java?
easy
A. byte b = 127;
B. byte b = 128;
C. byte b = 'a';
D. byte b = 128L;

Solution

  1. Step 1: Understand byte range

    byte stores values from -128 to 127 inclusive.
  2. Step 2: Check each option

    byte b = 128; uses 128 which is out of range; byte b = 127; uses 127 which is valid; byte b = 'a'; assigns a char which is not directly compatible; byte b = 128L; uses long literal 128L which is invalid for byte.
  3. Final Answer:

    byte b = 127; -> Option A
  4. Quick Check:

    byte max value = 127 [OK]
Hint: byte max is 127, so use values within -128 to 127 [OK]
Common Mistakes:
  • Assigning values outside byte range
  • Using char or long literals directly
  • Not knowing byte limits
3. What is the output of the following Java code?
int x = 5;
float y = 2.0f;
System.out.println(x + y);
medium
A. 7.0
B. 7.0f
C. 7
D. 7.0d

Solution

  1. Step 1: Understand type promotion in expression

    int x is promoted to float when added to float y.
  2. Step 2: Calculate the sum and output type

    5 + 2.0f = 7.0 (float), but println prints float as decimal number without suffix.
  3. Final Answer:

    7.0 -> Option A
  4. Quick Check:

    int + float = float output 7.0 [OK]
Hint: int + float results in float decimal output [OK]
Common Mistakes:
  • Expecting integer output
  • Confusing float suffix in output
  • Ignoring type promotion rules
4. Identify the error in the following Java code snippet:
char c = 'AB';
medium
A. char cannot be assigned a value directly
B. Missing semicolon at end
C. char can only hold a single character
D. char must be initialized with a number

Solution

  1. Step 1: Check char assignment rules

    char stores a single 16-bit Unicode character, so it must be assigned a single character in single quotes.
  2. Step 2: Analyze the given code

    'AB' is two characters, which is invalid for char type.
  3. Final Answer:

    char can only hold a single character -> Option C
  4. Quick Check:

    char = single character only [OK]
Hint: char holds exactly one character in single quotes [OK]
Common Mistakes:
  • Assigning multiple characters to char
  • Confusing char with String
  • Forgetting single quotes for char
5. You want to store a large whole number that is bigger than int can hold. Which primitive type should you use in Java?
hard
A. short
B. long
C. float
D. double

Solution

  1. Step 1: Recall int and long ranges

    int holds up to about 2 billion (2^31-1), long holds much larger values (2^63-1).
  2. Step 2: Choose type for large whole number

    long is the correct primitive type for large integers beyond int range; float and double are for decimals, short is smaller than int.
  3. Final Answer:

    long -> Option B
  4. Quick Check:

    Use long for large integers beyond int [OK]
Hint: Use long for big whole numbers beyond int range [OK]
Common Mistakes:
  • Using float/double for whole numbers
  • Choosing short which is smaller
  • Not knowing long size
Recommended

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10 questions~5 mineasy hard