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Javaprogramming~10 mins

Loop initialization, condition, update in Java - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the loop variable correctly.

Java
for ([1]; i < 5; i++) {
    System.out.println(i);
}
Drag options to blanks, or click blank then click option'
Aint = 0
Bi = 0
Cint i
Dint i = 0
Attempts:
3 left
💡 Hint
Common Mistakes
Forgetting to declare the variable type.
Using assignment without declaration.
2fill in blank
medium

Complete the code to write the correct loop condition.

Java
for (int i = 0; [1]; i++) {
    System.out.println(i);
}
Drag options to blanks, or click blank then click option'
Ai < 5
Bi == 5
Ci > 5
Di <= 5
Attempts:
3 left
💡 Hint
Common Mistakes
Using <= 5 runs the loop one extra time.
Using == 5 does not run the loop at all.
3fill in blank
hard

Fix the error in the loop update expression.

Java
for (int i = 0; i < 5; [1]) {
    System.out.println(i);
}
Drag options to blanks, or click blank then click option'
Ai++
Bi = i + 1
Ci--
Di += 2
Attempts:
3 left
💡 Hint
Common Mistakes
Using decrement i-- causes an infinite loop.
Using i += 2 skips numbers.
4fill in blank
hard

Fill both blanks to create a loop that counts down from 10 to 1.

Java
for (int i = [1]; i [2] 0; i--) {
    System.out.println(i);
}
Drag options to blanks, or click blank then click option'
A10
B>
C>=
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Starting at 0 instead of 10.
Using i < 0 as condition causes no iterations.
5fill in blank
hard

Fill all three blanks to create a loop that prints even numbers from 2 to 10.

Java
for (int [1] = [2]; [1] [3] 10; [1] += 2) {
    System.out.println([1]);
}
Drag options to blanks, or click blank then click option'
Ai
B2
C<=
Dj
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong variable names.
Starting at 0 or 1 instead of 2.
Using < instead of <= causes missing 10.

Practice

(1/5)
1. Which part of a for loop in Java sets the starting value of the loop variable?
easy
A. Initialization
B. Condition
C. Update
D. Body

Solution

  1. Step 1: Understand the parts of a for loop

    A for loop has three parts: initialization, condition, and update.
  2. Step 2: Identify the starting value part

    The initialization part sets the starting value of the loop variable before the loop runs.
  3. Final Answer:

    Initialization -> Option A
  4. Quick Check:

    Starting value = Initialization [OK]
Hint: Initialization always sets the loop's start value [OK]
Common Mistakes:
  • Confusing condition with initialization
  • Thinking update sets the start value
  • Mixing loop body with initialization
2. Which of the following is the correct syntax for a for loop in Java that counts from 0 to 4?
easy
A. for(int i = 0; i < 4; i++) {}
B. for(int i = 0; i <= 4; i++) {}
C. for(int i = 1; i <= 5; i++) {}
D. for(int i = 0; i != 5; i--) {}

Solution

  1. Step 1: Check initialization and condition

    for(int i = 0; i <= 4; i++) {} starts at 0 and runs while i is less than or equal to 4, which covers 0 to 4.
  2. Step 2: Check update direction

    for(int i = 0; i <= 4; i++) {} increments i by 1 each time, moving forward correctly.
  3. Final Answer:

    for(int i = 0; i <= 4; i++) {} -> Option B
  4. Quick Check:

    0 to 4 inclusive = for(int i = 0; i <= 4; i++) {} [OK]
Hint: Use i <= max to include last number [OK]
Common Mistakes:
  • Using i < 4 excludes 4
  • Starting at 1 misses 0
  • Decrementing i causes infinite loop
3. What is the output of this Java code?
for(int i = 1; i < 5; i += 2) {
    System.out.print(i + " ");
}
medium
A. 1 2 3 4
B. 1 3 5
C. 2 4
D. 1 3

Solution

  1. Step 1: Trace loop values

    i starts at 1, prints 1, then i increases by 2 to 3, prints 3, then i increases by 2 to 5.
  2. Step 2: Check loop condition

    Loop runs while i < 5. When i is 5, condition fails, so loop stops.
  3. Final Answer:

    1 3 -> Option D
  4. Quick Check:

    Prints 1 and 3 only [OK]
Hint: Add update to i and check condition carefully [OK]
Common Mistakes:
  • Assuming loop runs when i equals 5
  • Forgetting i increments by 2
  • Printing values after loop ends
4. Identify the error in this Java loop:
for(int i = 0; i > 5; i++) {
    System.out.println(i);
}
medium
A. Condition causes loop to never run
B. Update should decrement i
C. Initialization is incorrect
D. Missing loop body braces

Solution

  1. Step 1: Analyze the loop condition

    The condition is i > 5, but i starts at 0, so 0 > 5 is false immediately.
  2. Step 2: Understand loop execution

    Since condition is false at start, loop body never runs.
  3. Final Answer:

    Condition causes loop to never run -> Option A
  4. Quick Check:

    False condition stops loop immediately [OK]
Hint: Check if condition is true at start to run loop [OK]
Common Mistakes:
  • Thinking loop runs at least once
  • Confusing > with < in condition
  • Assuming update fixes condition
5. You want to print all even numbers from 2 to 20 using a for loop in Java. Which loop correctly does this?
hard
A. for(int i = 2; i < 20; i++) { if(i % 2 == 0) System.out.print(i + " "); }
B. for(int i = 1; i < 20; i++) { if(i % 2 == 0) System.out.print(i + " "); }
C. for(int i = 2; i <= 20; i += 2) { System.out.print(i + " "); }
D. for(int i = 0; i <= 20; i += 2) { System.out.print(i + " "); }

Solution

  1. Step 1: Check initialization and update for even numbers

    for(int i = 2; i <= 20; i += 2) { System.out.print(i + " "); } starts at 2 and increments by 2, printing even numbers directly up to 20.
  2. Step 2: Verify condition includes 20

    Condition i <= 20 ensures 20 is included in output.
  3. Final Answer:

    for(int i = 2; i <= 20; i += 2) { System.out.print(i + " "); } -> Option C
  4. Quick Check:

    Start at 2, step 2, up to 20 [OK]
Hint: Start at first even, add 2 each time [OK]
Common Mistakes:
  • Starting at 0 prints unwanted 0
  • Using < 20 excludes 20
  • Forgetting to increment by 2
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10 questions~5 mineasy hard