An if statement lets the program decide to run some code only if a condition is true. It helps the program make choices.
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beginner
Write the basic syntax of an if statement in Java.
The basic syntax is:
if (condition) { // code to run if condition is true }
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beginner
What happens if the condition in an if statement is false?
If the condition is false, the code inside the if block does not run. The program skips it and continues.
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beginner
Can an if statement be used without an else part?
Yes, an if statement can stand alone. The else part is optional and runs code when the condition is false.
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beginner
How do you write an if-else statement in Java?
You write it like this:
if (condition) { // code if true } else { // code if false }
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What does the if statement check in Java?
AA condition that is true or false
BA loop counter
CA variable declaration
DA method call
✗ Incorrect
The if statement checks a condition that evaluates to true or false to decide which code to run.
What happens if the if condition is false and there is no else?
AThe program skips the <code>if</code> block and continues
BThe program runs the code inside the <code>if</code> block
CThe program stops running
DThe program throws an error
✗ Incorrect
If the condition is false and no else is present, the program skips the if block and continues.
Which of these is the correct syntax for an if statement?
Aif condition { }
Bif condition then { }
Cif [condition] { }
Dif (condition) { }
✗ Incorrect
In Java, the condition must be inside parentheses: if (condition) { }.
Can you have multiple if statements one after another?
ANo, only one <code>if</code> per program
BOnly if they have <code>else</code> parts
CYes, you can have many <code>if</code> statements
DOnly if they are inside a loop
✗ Incorrect
You can have many if statements in a program to check different conditions.
What keyword do you use to run code when an if condition is false?
Aelseif
Belse
Cwhen
Dotherwise
✗ Incorrect
The keyword else runs code when the if condition is false.
Explain how an if statement works in Java and write a simple example.
Think about how you decide to do something only if a certain condition is true.
You got /4 concepts.
Describe the difference between an if statement and an if-else statement.
Consider what happens when the condition is false.
You got /4 concepts.
Practice
(1/5)
1. What does an if statement do in Java?
easy
A. It stores data in a variable.
B. It repeats code multiple times.
C. It creates a new class.
D. It runs code only if a condition is true.
Solution
Step 1: Understand the purpose of an if statement
An if statement checks a condition and decides whether to run some code based on that condition.
Step 2: Match the description to the options
It runs code only if a condition is true. correctly says it runs code only if the condition is true, which matches the if statement's behavior.
Final Answer:
It runs code only if a condition is true. -> Option D
Quick Check:
If statement = runs code if true [OK]
Hint: If checks true condition to run code [OK]
Common Mistakes:
Confusing if with loops
Thinking if stores data
Mixing if with class creation
2. Which of these is the correct syntax for an if statement in Java?
easy
A. if (condition) System.out.println("Yes");
B. if condition { System.out.println("Yes"); }
C. if condition: System.out.println("Yes");
D. if (condition) then { System.out.println("Yes"); }
Solution
Step 1: Recall Java if statement syntax
Java requires parentheses around the condition and braces are optional if only one statement follows.
Step 2: Check each option
if (condition) System.out.println("Yes"); uses parentheses and a single statement without braces, which is valid syntax.
Final Answer:
if (condition) System.out.println("Yes"); -> Option A
Quick Check:
Parentheses needed around condition [OK]
Hint: Use parentheses around condition in if [OK]
Common Mistakes:
Omitting parentheses around condition
Using colons instead of braces
Adding 'then' keyword
3. What will be the output of this code?
int x = 10;
if (x > 5) {
System.out.println("Big number");
} else {
System.out.println("Small number");
}
medium
A. Small number
B. Big number
C. No output
D. Syntax error
Solution
Step 1: Evaluate the condition x > 5
Since x is 10, the condition 10 > 5 is true.
Step 2: Determine which block runs
The if block runs and prints "Big number" because the condition is true.
Final Answer:
Big number -> Option B
Quick Check:
10 > 5 is true, prints "Big number" [OK]
Hint: Check if condition true to pick output [OK]
Common Mistakes:
Choosing else output when condition is true
Thinking no output if condition true
Confusing syntax with output
4. Find the error in this code:
int num = 7;
if num > 5 {
System.out.println("Greater");
}
medium
A. Braces not allowed in if
B. Missing semicolon after if
C. Missing parentheses around condition
D. Wrong variable name
Solution
Step 1: Check if statement syntax
Java requires parentheses around the condition in an if statement.
Step 2: Identify the missing parentheses
The code has if num > 5 without parentheses, which causes a syntax error.
Final Answer:
Missing parentheses around condition -> Option C
Quick Check:
If condition must be in parentheses [OK]
Hint: Always put condition in parentheses [OK]
Common Mistakes:
Forgetting parentheses around condition
Adding semicolon after if line
Misnaming variables
5. You want to print "Even" if a number is even and "Odd" if it is odd. Which code correctly uses an if statement to do this?
int n = 4;
// Your code here
hard
A. if (n % 2 == 0) {
System.out.println("Even");
} else {
System.out.println("Odd");
}
B. if (n / 2 == 0) {
System.out.println("Even");
} else {
System.out.println("Odd");
}
C. if (n % 2 = 0) {
System.out.println("Even");
} else {
System.out.println("Odd");
}
D. if (n % 2 != 0) {
System.out.println("Even");
} else {
System.out.println("Odd");
}
Solution
Step 1: Understand how to check even numbers
A number is even if dividing by 2 leaves remainder 0, so use n % 2 == 0.
Step 2: Check each option's condition
if (n % 2 == 0) {
System.out.println("Even");
} else {
System.out.println("Odd");
} correctly uses n % 2 == 0 to check evenness and prints "Even" or "Odd" accordingly.
Final Answer:
if (n % 2 == 0) { System.out.println("Even"); } else { System.out.println("Odd"); } -> Option A
Quick Check:
Use modulus == 0 for even check [OK]
Hint: Use n % 2 == 0 to check even numbers [OK]
Common Mistakes:
Using assignment = instead of comparison ==
Checking division instead of remainder
Reversing even and odd conditions
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