Else–if ladder in Java - Mini Project: Build & Apply

Else-if ladder

📖 Scenario: You are creating a simple program that assigns a grade based on a student's score.

🎯 Goal: Build a Java program that uses an else-if ladder to print the correct grade for a given score.

📋 What You'll Learn

Create an integer variable called score with the exact value 85.

Create an integer variable called passingScore with the exact value 50.

Use an else-if ladder with the variable score to assign grades:

90 and above is Grade A

80 to 89 is Grade B

70 to 79 is Grade C

60 to 69 is Grade D

50 to 59 is Grade E

Below 50 is Fail.

Print the grade using System.out.println.

💡 Why This Matters

🌍 Real World

Grading systems in schools or colleges use similar logic to assign letter grades based on numeric scores.

💼 Career

Understanding conditional statements like else-if ladders is essential for decision-making in software development.

1

Create the score variable

Create an integer variable called score and set it to 85.

Java

# Your code here

Hint

Use int score = 85; inside the main method.

2

Create the passingScore variable

Add an integer variable called passingScore and set it to 50 below the score variable.

Java

public class Main {
    public static void main(String[] args) {
        int score = 85;
        // Your code here
    }
}

Hint

Declare int passingScore = 50; just after score.

3

Write the else-if ladder for grades

Write an else-if ladder using the variable score to assign grades as follows: if score >= 90, print Grade A; else if score >= 80, print Grade B; else if score >= 70, print Grade C; else if score >= 60, print Grade D; else if score >= 50, print Grade E; else print Fail. Use System.out.println inside each block.

Java

public class Main {
    public static void main(String[] args) {
        int score = 85;
        int passingScore = 50;
        // Your else-if ladder here
    }
}

Hint

Use if, multiple else if, and a final else to cover all score ranges.

4

Print the grade result

Run the program to print the grade for the score 85. The output should be Grade B.

Java

public class Main {
    public static void main(String[] args) {
        int score = 85;
        int passingScore = 50;
        if (score >= 90) {
            System.out.println("Grade A");
        } else if (score >= 80) {
            System.out.println("Grade B");
        } else if (score >= 70) {
            System.out.println("Grade C");
        } else if (score >= 60) {
            System.out.println("Grade D");
        } else if (score >= 50) {
            System.out.println("Grade E");
        } else {
            System.out.println("Fail");
        }
        // Program prints the grade
    }
}

Hint

Run the program and check the console output.

Practice

1. What does an else-if ladder in Java help you do?

easy

A. Run all conditions regardless of their truth

B. Check multiple conditions one by one until one is true

C. Only check the first condition and ignore others

D. Skip conditions and run else block always

Solution

1. Step 1: Understand the purpose of else-if ladder

   An else-if ladder lets you test several conditions in order, stopping at the first true one.

2. Step 2: Compare options with this behavior

   Only Check multiple conditions one by one until one is true correctly describes checking conditions one by one until one is true.

3. Final Answer:

   Check multiple conditions one by one until one is true -> Option B

4. Quick Check:

   Else-if ladder = check conditions one by one [OK]

Hint: Else-if ladder stops at first true condition [OK]

Common Mistakes:

• Thinking all conditions run regardless
• Confusing else-if with separate if statements
• Believing else runs before conditions

2. Which of the following is the correct syntax for an else-if ladder in Java?

easy

A. if(condition) { } else if condition { } else { }

B. if(condition) { } else(condition) { } else { }

C. if condition { } else if(condition) { } else { }

D. if(condition) { } else if(condition) { } else { }

Solution

1. Step 1: Recall Java syntax for else-if ladder

   Java requires parentheses around conditions and braces for blocks: if(condition) { } else if(condition) { } else { }

2. Step 2: Check each option for syntax errors

   Only if(condition) { } else if(condition) { } else { } uses correct parentheses and braces. Others miss parentheses or use wrong keywords.

3. Final Answer:

   if(condition) { } else if(condition) { } else { } -> Option D

4. Quick Check:

   Correct else-if syntax = if(condition) { } else if(condition) { } else { } [OK]

Hint: Use parentheses for conditions and braces for blocks [OK]

Common Mistakes:

• Omitting parentheses around conditions
• Writing else with a condition (should be else if)
• Missing braces for code blocks

3. What will be the output of this Java code?

int score = 75;
if(score >= 90) {
  System.out.println("Grade A");
} else if(score >= 80) {
  System.out.println("Grade B");
} else if(score >= 70) {
  System.out.println("Grade C");
} else {
  System.out.println("Fail");
}

medium

A. Grade C

B. Grade B

C. Fail

D. Grade A

Solution

1. Step 1: Check conditions in order with score = 75

   score >= 90? No (75 < 90). Next condition.

2. Step 2: Check next conditions

   score >= 80? No (75 < 80). Next condition.
   score >= 70? Yes (75 >= 70). So print "Grade C" and skip else.

3. Final Answer:

   Grade C -> Option A

4. Quick Check:

   75 is between 70 and 79 = Grade C [OK]

Hint: Check conditions top to bottom, first true runs [OK]

Common Mistakes:

• Choosing Grade B or A by mistake
• Ignoring else-if order
• Assuming else runs even if condition true

4. Find the error in this else-if ladder code snippet:

int num = 10;
if(num > 10) {
  System.out.println("Greater than 10");
} else if num == 10 {
  System.out.println("Equal to 10");
} else {
  System.out.println("Less than 10");
}

medium

A. Missing semicolon after print statements

B. Using else instead of else-if

C. Missing parentheses around condition in else-if

D. No error, code is correct

Solution

1. Step 1: Check syntax of else-if condition

   In Java, conditions must be inside parentheses. Here, else if num == 10 lacks parentheses.

2. Step 2: Verify other parts

   Print statements have semicolons, else-if is used correctly, so no other errors.

3. Final Answer:

   Missing parentheses around condition in else-if -> Option C

4. Quick Check:

   Conditions need parentheses [OK]

Hint: Always put conditions inside parentheses [OK]

Common Mistakes:

• Forgetting parentheses in else-if
• Confusing else and else-if syntax
• Missing semicolons (not the issue here)

5. You want to write a program that assigns a letter grade based on score:
- 90 and above: A
- 80 to 89: B
- 70 to 79: C
- 60 to 69: D
- Below 60: F
Which else-if ladder correctly implements this?

hard

A. if(score >= 90) { grade = 'A'; } else if(score >= 80) { grade = 'B'; } else if(score >= 70) { grade = 'C'; } else if(score >= 60) { grade = 'D'; } else { grade = 'F'; }

B. if(score > 90) { grade = 'A'; } else if(score > 80) { grade = 'B'; } else if(score > 70) { grade = 'C'; } else if(score > 60) { grade = 'D'; } else { grade = 'F'; }

C. if(score >= 90) { grade = 'A'; } else if(score > 80) { grade = 'B'; } else if(score >= 70) { grade = 'C'; } else if(score >= 60) { grade = 'D'; } else { grade = 'F'; }

D. if(score >= 90) { grade = 'A'; } else if(score >= 80) { grade = 'B'; } else if(score >= 70) { grade = 'C'; } else if(score > 60) { grade = 'D'; } else { grade = 'F'; }

Solution

1. Step 1: Understand the grade ranges and conditions

   Grades are assigned for score ranges including boundaries: 90+, 80-89, 70-79, 60-69, below 60.

2. Step 2: Check each option's condition operators

   if(score >= 90) { grade = 'A'; } else if(score >= 80) { grade = 'B'; } else if(score >= 70) { grade = 'C'; } else if(score >= 60) { grade = 'D'; } else { grade = 'F'; } uses >= for lower bounds correctly. The other options use > in some places, which excludes boundary values (like 80 or 60).

3. Final Answer:

   if(score >= 90) { grade = 'A'; } else if(score >= 80) { grade = 'B'; } else if(score >= 70) { grade = 'C'; } else if(score >= 60) { grade = 'D'; } else { grade = 'F'; } -> Option A

4. Quick Check:

   Use >= for inclusive ranges [OK]

Hint: Use >= for inclusive score ranges [OK]

Common Mistakes:

• Using > instead of >= excludes boundary scores
• Overlapping or missing ranges
• Incorrect else placement