Break statement in Java - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of break in nested loops

What is the output of this Java code snippet?

Java

public class Test {
    public static void main(String[] args) {
        int count = 0;
        outer: for (int i = 1; i <= 3; i++) {
            for (int j = 1; j <= 3; j++) {
                if (i * j > 3) {
                    break outer;
                }
                count++;
            }
        }
        System.out.println(count);
    }
}

A 5

B 3

C 4

D 6

💡 Hint

Look at how the labeled break exits the outer loop immediately.

The inner loop increments count while i*j <= 3. When i=2 and j=2, i*j=4 > 3, so break outer exits both loops. The count increments 4 times before breaking.

🧠 Conceptual

intermediate

Effect of break in switch-case

What will be printed when the following Java code runs?

Java

public class Test {
    public static void main(String[] args) {
        int x = 2;
        switch (x) {
            case 1:
                System.out.println("One");
            case 2:
                System.out.println("Two");
            case 3:
                System.out.println("Three");
                break;
            default:
                System.out.println("Default");
        }
    }
}

A

Two
Three

B Two

C

Two
Three
Default

D

One
Two
Three

💡 Hint

Remember that break stops execution inside switch cases.

Since case 2 matches, it prints "Two" then falls through to case 3 and prints "Three" before break stops further execution.

🔧 Debug

advanced

Why does this break not stop the loop?

Consider this Java code. Why does the loop terminate immediately without printing any numbers instead of stopping at 3?

Java

public class Test {
    public static void main(String[] args) {
        for (int i = 0; i < 5; i++) {
            if (i == 3);
                break;
            System.out.println(i);
        }
    }
}

A The loop condition is wrong, so break never executes.

B The break is inside the if block and stops the loop at i=3 as expected.

C The break statement is unreachable and causes a compile error.

D The semicolon after if condition ends the if statement, so break always executes on first iteration.

💡 Hint

Check the semicolon after the if condition carefully.

The semicolon after if(i == 3) ends the if statement. The break is outside the if and executes unconditionally on first iteration.

📝 Syntax

advanced

Identify the syntax error with break usage

Which option shows the code that will cause a compile-time error due to incorrect break usage?

Java

public class Test {
    public static void main(String[] args) {
        // Code snippet here
    }
}

A

int i = 0;
break;

B

while(true) {
  break;
}

C

for(int i=0; i<5; i++) {
  if(i==3) break;
}

D

switch(1) {
  case 1: break;
}

💡 Hint

break must be inside a loop or switch block.

Option A uses break outside any loop or switch, causing compile-time error.

🚀 Application

expert

Count iterations before break in nested loop

What is the value of variable total after running this Java code?

Java

public class Test {
    public static void main(String[] args) {
        int total = 0;
        outer: for (int i = 1; i <= 4; i++) {
            for (int j = 1; j <= 4; j++) {
                if (i + j > 5) {
                    break outer;
                }
                total++;
            }
        }
        System.out.println(total);
    }
}

A 9

B 7

C 12

D 10

💡 Hint

Count how many times total increments before i+j > 5 triggers break.

The loops increment total while i+j <= 5. The break outer stops both loops when i+j > 5. Counting increments gives 7.