Why GET request with async/await in iOS Swift? - Purpose & Use Cases

The Big Idea

What if you could fetch data from the internet without making your app freeze or your code messy?

The Scenario

Imagine you want to fetch weather data from the internet for your app. You write code that waits for the data to come back before moving on. But the app freezes and becomes unresponsive while waiting.

The Problem

Using old methods, your app can freeze or lag because it waits for the network response on the main thread. This makes the app feel slow and frustrating. Also, handling callbacks manually can get messy and confusing.

The Solution

With async/await, you write code that looks simple and clear, but runs in the background without freezing the app. It waits for the data smoothly, then continues once the data arrives, keeping your app fast and responsive.

Before vs After

✗ Before

URLSession.shared.dataTask(with: url) { data, _, _ in
  if let data = data {
    print(String(data: data, encoding: .utf8) ?? "")
  }
}.resume()

✓ After

let (data, _) = try await URLSession.shared.data(from: url)
print(String(data: data, encoding: .utf8) ?? "")

What It Enables

You can write clean, readable code that fetches data from the internet without freezing your app or getting lost in complex callbacks.

Real Life Example

Fetching user profiles from a server in a social media app smoothly, so the app stays responsive while loading new content.

Key Takeaways

Old network calls can freeze your app and are hard to read.

Async/await lets you write simple code that runs smoothly in the background.

This makes your app faster and easier to maintain.

Practice

1. What does the async keyword indicate in a Swift function that performs a GET request?

easy

A. The function is synchronous and blocks the main thread.

B. The function runs asynchronously and can be awaited.

C. The function automatically retries on failure.

D. The function only works with POST requests.

Solution

1. Step 1: Understand async keyword meaning

   The async keyword means the function runs asynchronously, allowing other code to run while waiting.

2. Step 2: Connect async with await usage

   Functions marked async can be called with await to pause until the result is ready without blocking.

3. Final Answer:

   The function runs asynchronously and can be awaited. -> Option B

4. Quick Check:

   async means asynchronous function [OK]

Hint: async means function can be paused with await [OK]

Common Mistakes:

• Thinking async means synchronous/blocking
• Confusing async with retry logic
• Assuming async only applies to POST requests

2. Which of the following is the correct syntax to perform a GET request using async/await in Swift?

easy

A. let (data, _) = try await URLSession.shared.data(from: url)

B. let data = URLSession.shared.dataTask(with: url)

C. let data = await URLSession.shared.data(from: url)

D. let (data, response) = URLSession.shared.data(from: url)

Solution

1. Step 1: Identify correct async/await syntax

   The correct syntax uses try await with URLSession.shared.data(from:) to get data and response.

2. Step 2: Check tuple unpacking

   The method returns a tuple of (Data, URLResponse), so unpacking with (data, _) is correct if response is unused.

3. Final Answer:

   let (data, _) = try await URLSession.shared.data(from: url) -> Option A

4. Quick Check:

   Use try await with data(from:) [OK]

Hint: Use try await with data(from:) and unpack tuple [OK]

Common Mistakes:

• Omitting try keyword
• Using dataTask without await
• Not unpacking the returned tuple

3. Given the code below, what will be printed if the GET request succeeds?

func fetchData() async {
  let url = URL(string: "https://example.com/data.json")!
  do {
    let (data, _) = try await URLSession.shared.data(from: url)
    print("Data length: \(data.count)")
  } catch {
    print("Failed to fetch")
  }
}

medium

A. Syntax error

B. Failed to fetch

C. Data length: 0

D. Data length: [number of bytes in data]

Solution

1. Step 1: Analyze successful GET request

   If the request succeeds, try await returns data and response without throwing an error.

2. Step 2: Understand print statement output

   The code prints the length of the received data in bytes, so output is "Data length: [number]".

3. Final Answer:

   Data length: [number of bytes in data] -> Option D

4. Quick Check:

   Success prints data length [OK]

Hint: Success prints data length, failure prints error [OK]

Common Mistakes:

• Assuming print shows raw data
• Confusing catch block output
• Expecting zero length on success

4. Identify the error in this Swift async GET request code:

func load() async {
  let url = URL(string: "https://api.example.com")!
  let (data, response) = URLSession.shared.data(from: url)
  print(String(data: data, encoding: .utf8) ?? "No data")
}

medium

A. Incorrect print statement syntax

B. URL is invalid

C. Missing await keyword before URLSession.shared.data(from: url)

D. Missing try keyword before URLSession.shared.data(from: url)

Solution

1. Step 1: Check async call usage

   The method data(from:) is async and must be awaited with await.

2. Step 2: Confirm missing await keyword

   The code calls URLSession.shared.data(from: url) without await, causing a compile error.

3. Final Answer:

   Missing await keyword before URLSession.shared.data(from: url) -> Option C

4. Quick Check:

   Async calls require await [OK]

Hint: Async calls always need await keyword [OK]

Common Mistakes:

• Forgetting await on async calls
• Assuming try is optional
• Misreading URL validity

5. You want to fetch JSON data from a URL and decode it into a Swift struct using async/await. Which code snippet correctly performs the GET request and decodes the data?

struct User: Decodable {
  let id: Int
  let name: String
}

func fetchUser() async throws -> User {
  let url = URL(string: "https://api.example.com/user")!
  // Which code goes here?
}

hard

A. let (data, _) = try await URLSession.shared.data(from: url)
return try JSONDecoder().decode(User.self, from: data)

B. let data = try URLSession.shared.data(from: url)
return JSONDecoder().decode(User.self, from: data)

C. let (data, _) = URLSession.shared.data(from: url)
return try JSONDecoder().decode(User.self, from: data)

D. let (data, _) = try await URLSession.shared.dataTask(with: url)
return try JSONDecoder().decode(User.self, from: data)

Solution

1. Step 1: Use async/await with data(from:)

   The correct async call is try await URLSession.shared.data(from: url) which returns data and response.

2. Step 2: Decode JSON data into struct

   Use JSONDecoder().decode(User.self, from: data) to convert JSON bytes into the User struct.

3. Final Answer:

   let (data, _) = try await URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data) -> Option A

4. Quick Check:

   Use try await with data(from:) and decode JSON [OK]

Hint: Use try await data(from:) then decode JSON [OK]

Common Mistakes:

• Using dataTask instead of data(from:)
• Omitting await or try keywords
• Not decoding JSON properly