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GET request with async/await in iOS Swift - Practice Problems & Coding Challenges

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Challenge - 5 Problems
🎖️
Swift Async GET Master
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❓ ui_behavior
intermediate
2:00remaining
What is the output of this Swift async GET request code?
Consider this Swift code that fetches JSON data asynchronously. What will be printed if the request succeeds and the JSON contains {"message": "Hello"}?
iOS Swift
import Foundation

func fetchMessage() async {
  guard let url = URL(string: "https://example.com/api/message") else { return }
  do {
    let (data, _) = try await URLSession.shared.data(from: url)
    if let json = try? JSONSerialization.jsonObject(with: data) as? [String: String],
       let message = json["message"] {
      print(message)
    } else {
      print("No message found")
    }
  } catch {
    print("Request failed")
  }
}

Task {
  await fetchMessage()
}
ARequest failed
BNo message found
CHello
DCompilation error
Attempts:
2 left
💡 Hint
Look at how the JSON is parsed and the key accessed.
❓ lifecycle
intermediate
2:00remaining
When is the async GET request executed in this SwiftUI view?
Given this SwiftUI view, when does the fetchData() async function run?
iOS Swift
import SwiftUI

struct ContentView: View {
  @State private var text = ""

  var body: some View {
    Text(text)
      .task {
        await fetchData()
      }
  }

  func fetchData() async {
    // async GET request code here
    text = "Data loaded"
  }
}
AImmediately when the app launches
BWhen the view appears on screen
COnly when the user taps the Text
DWhen the view disappears
Attempts:
2 left
💡 Hint
The .task modifier runs code related to the view's lifecycle.
🔧 Debug
advanced
2:00remaining
What error does this async GET request code produce?
Identify the error in this Swift async GET request code snippet.
iOS Swift
func loadData() async {
  let url = URL(string: "https://example.com/data")!
  let (data, response) = try await URLSession.shared.data(from: url)
  print(String(data: data, encoding: .utf8) ?? "No data")
}
AMissing await keyword before URLSession.shared.data call
BMissing try keyword before URLSession.shared.data call
CNo error, code runs fine
DURL is optional and not unwrapped safely
Attempts:
2 left
💡 Hint
Check how async functions are called with await.
🧠 Conceptual
advanced
1:30remaining
Which statement about async GET requests in Swift is true?
Choose the correct statement about using async/await for GET requests in Swift.
AAsync/await requires manually creating completion handlers
BAsync/await can only be used with POST requests
CAsync/await blocks the main thread until the request finishes
DAsync/await allows writing asynchronous code that looks like synchronous code
Attempts:
2 left
💡 Hint
Think about how async/await changes code style.
📝 Syntax
expert
2:30remaining
What is the value of 'result' after this Swift async GET request code runs?
Given this code snippet, what will be the value of 'result' after execution?
iOS Swift
import Foundation

func fetchNumber() async throws -> Int {
  let url = URL(string: "https://example.com/number")!
  let (data, _) = try await URLSession.shared.data(from: url)
  let numberString = String(data: data, encoding: .utf8) ?? "0"
  return Int(numberString) ?? 0
}

var result = 0

Task {
  do {
    result = try await fetchNumber()
  } catch {
    result = -1
  }
}
AAll of the above depending on server response
B0 if the server returns invalid data
C0 if the server returns empty data
D42 if the server returns "42" as plain text
Attempts:
2 left
💡 Hint
Consider how the code handles different server responses and errors.

Practice

(1/5)
1. What does the async keyword indicate in a Swift function that performs a GET request?
easy
A. The function is synchronous and blocks the main thread.
B. The function runs asynchronously and can be awaited.
C. The function automatically retries on failure.
D. The function only works with POST requests.

Solution

  1. Step 1: Understand async keyword meaning

    The async keyword means the function runs asynchronously, allowing other code to run while waiting.
  2. Step 2: Connect async with await usage

    Functions marked async can be called with await to pause until the result is ready without blocking.
  3. Final Answer:

    The function runs asynchronously and can be awaited. -> Option B
  4. Quick Check:

    async means asynchronous function [OK]
Hint: async means function can be paused with await [OK]
Common Mistakes:
  • Thinking async means synchronous/blocking
  • Confusing async with retry logic
  • Assuming async only applies to POST requests
2. Which of the following is the correct syntax to perform a GET request using async/await in Swift?
easy
A. let (data, _) = try await URLSession.shared.data(from: url)
B. let data = URLSession.shared.dataTask(with: url)
C. let data = await URLSession.shared.data(from: url)
D. let (data, response) = URLSession.shared.data(from: url)

Solution

  1. Step 1: Identify correct async/await syntax

    The correct syntax uses try await with URLSession.shared.data(from:) to get data and response.
  2. Step 2: Check tuple unpacking

    The method returns a tuple of (Data, URLResponse), so unpacking with (data, _) is correct if response is unused.
  3. Final Answer:

    let (data, _) = try await URLSession.shared.data(from: url) -> Option A
  4. Quick Check:

    Use try await with data(from:) [OK]
Hint: Use try await with data(from:) and unpack tuple [OK]
Common Mistakes:
  • Omitting try keyword
  • Using dataTask without await
  • Not unpacking the returned tuple
3. Given the code below, what will be printed if the GET request succeeds?
func fetchData() async {
  let url = URL(string: "https://example.com/data.json")!
  do {
    let (data, _) = try await URLSession.shared.data(from: url)
    print("Data length: \(data.count)")
  } catch {
    print("Failed to fetch")
  }
}
medium
A. Syntax error
B. Failed to fetch
C. Data length: 0
D. Data length: [number of bytes in data]

Solution

  1. Step 1: Analyze successful GET request

    If the request succeeds, try await returns data and response without throwing an error.
  2. Step 2: Understand print statement output

    The code prints the length of the received data in bytes, so output is "Data length: [number]".
  3. Final Answer:

    Data length: [number of bytes in data] -> Option D
  4. Quick Check:

    Success prints data length [OK]
Hint: Success prints data length, failure prints error [OK]
Common Mistakes:
  • Assuming print shows raw data
  • Confusing catch block output
  • Expecting zero length on success
4. Identify the error in this Swift async GET request code:
func load() async {
  let url = URL(string: "https://api.example.com")!
  let (data, response) = URLSession.shared.data(from: url)
  print(String(data: data, encoding: .utf8) ?? "No data")
}
medium
A. Incorrect print statement syntax
B. URL is invalid
C. Missing await keyword before URLSession.shared.data(from: url)
D. Missing try keyword before URLSession.shared.data(from: url)

Solution

  1. Step 1: Check async call usage

    The method data(from:) is async and must be awaited with await.
  2. Step 2: Confirm missing await keyword

    The code calls URLSession.shared.data(from: url) without await, causing a compile error.
  3. Final Answer:

    Missing await keyword before URLSession.shared.data(from: url) -> Option C
  4. Quick Check:

    Async calls require await [OK]
Hint: Async calls always need await keyword [OK]
Common Mistakes:
  • Forgetting await on async calls
  • Assuming try is optional
  • Misreading URL validity
5. You want to fetch JSON data from a URL and decode it into a Swift struct using async/await. Which code snippet correctly performs the GET request and decodes the data?
struct User: Decodable {
  let id: Int
  let name: String
}

func fetchUser() async throws -> User {
  let url = URL(string: "https://api.example.com/user")!
  // Which code goes here?
}
hard
A. let (data, _) = try await URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data)
B. let data = try URLSession.shared.data(from: url) return JSONDecoder().decode(User.self, from: data)
C. let (data, _) = URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data)
D. let (data, _) = try await URLSession.shared.dataTask(with: url) return try JSONDecoder().decode(User.self, from: data)

Solution

  1. Step 1: Use async/await with data(from:)

    The correct async call is try await URLSession.shared.data(from: url) which returns data and response.
  2. Step 2: Decode JSON data into struct

    Use JSONDecoder().decode(User.self, from: data) to convert JSON bytes into the User struct.
  3. Final Answer:

    let (data, _) = try await URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data) -> Option A
  4. Quick Check:

    Use try await with data(from:) and decode JSON [OK]
Hint: Use try await data(from:) then decode JSON [OK]
Common Mistakes:
  • Using dataTask instead of data(from:)
  • Omitting await or try keywords
  • Not decoding JSON properly
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10 questions~5 mineasy hard