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iOS Swiftmobile~10 mins

GET request with async/await in iOS Swift - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a URL object from a string.

iOS Swift
guard let url = URL(string: [1]) else { return }
Drag options to blanks, or click blank then click option'
A"https://api.example.com/data"
Bhttps://api.example.com/data
CURL("https://api.example.com/data")
DurlString
Attempts:
3 left
💡 Hint
Common Mistakes
Forgetting to put the URL string in quotes.
Passing a variable name that is not defined.
2fill in blank
medium

Complete the code to perform an asynchronous GET request using URLSession.

iOS Swift
let (data, _) = try await URLSession.shared.[1](from: url)
Drag options to blanks, or click blank then click option'
AdownloadTask
BdataTask
Cpost
Ddata(from:)
Attempts:
3 left
💡 Hint
Common Mistakes
Using dataTask which is not async/await compatible.
Using downloadTask which downloads to a file.
3fill in blank
hard

Fix the error in the async function declaration for fetching data.

iOS Swift
func fetchData() async throws -> Data {
    let url = URL(string: "https://api.example.com/data")!
    let (data, _) = try await URLSession.shared.data(from: url)
    return [1]
}
Drag options to blanks, or click blank then click option'
Aurl
Bdata
Cself
Dresponse
Attempts:
3 left
💡 Hint
Common Mistakes
Returning the URL instead of data.
Returning the response object which is not declared.
4fill in blank
hard

Fill both blanks to decode JSON data into a Swift struct.

iOS Swift
let decoder = JSONDecoder()
let result = try decoder.[1](MyStruct.self, from: [2])
Drag options to blanks, or click blank then click option'
Adecode
Bdata
CjsonData
Dencode
Attempts:
3 left
💡 Hint
Common Mistakes
Using encode instead of decode.
Passing wrong variable instead of data.
5fill in blank
hard

Fill all three blanks to complete the async function that fetches and decodes JSON.

iOS Swift
func fetchAndDecode() async throws -> MyStruct {
    guard let url = URL(string: [1]) else { throw URLError(.badURL) }
    let ([2], _) = try await URLSession.shared.data(from: url)
    let decoder = JSONDecoder()
    return try decoder.decode([3].self, from: data)
}
Drag options to blanks, or click blank then click option'
A"https://api.example.com/data"
Bdata
CMyStruct
Durl
Attempts:
3 left
💡 Hint
Common Mistakes
Not quoting the URL string.
Using wrong variable names for data.
Passing wrong type to decode.

Practice

(1/5)
1. What does the async keyword indicate in a Swift function that performs a GET request?
easy
A. The function is synchronous and blocks the main thread.
B. The function runs asynchronously and can be awaited.
C. The function automatically retries on failure.
D. The function only works with POST requests.

Solution

  1. Step 1: Understand async keyword meaning

    The async keyword means the function runs asynchronously, allowing other code to run while waiting.
  2. Step 2: Connect async with await usage

    Functions marked async can be called with await to pause until the result is ready without blocking.
  3. Final Answer:

    The function runs asynchronously and can be awaited. -> Option B
  4. Quick Check:

    async means asynchronous function [OK]
Hint: async means function can be paused with await [OK]
Common Mistakes:
  • Thinking async means synchronous/blocking
  • Confusing async with retry logic
  • Assuming async only applies to POST requests
2. Which of the following is the correct syntax to perform a GET request using async/await in Swift?
easy
A. let (data, _) = try await URLSession.shared.data(from: url)
B. let data = URLSession.shared.dataTask(with: url)
C. let data = await URLSession.shared.data(from: url)
D. let (data, response) = URLSession.shared.data(from: url)

Solution

  1. Step 1: Identify correct async/await syntax

    The correct syntax uses try await with URLSession.shared.data(from:) to get data and response.
  2. Step 2: Check tuple unpacking

    The method returns a tuple of (Data, URLResponse), so unpacking with (data, _) is correct if response is unused.
  3. Final Answer:

    let (data, _) = try await URLSession.shared.data(from: url) -> Option A
  4. Quick Check:

    Use try await with data(from:) [OK]
Hint: Use try await with data(from:) and unpack tuple [OK]
Common Mistakes:
  • Omitting try keyword
  • Using dataTask without await
  • Not unpacking the returned tuple
3. Given the code below, what will be printed if the GET request succeeds?
func fetchData() async {
  let url = URL(string: "https://example.com/data.json")!
  do {
    let (data, _) = try await URLSession.shared.data(from: url)
    print("Data length: \(data.count)")
  } catch {
    print("Failed to fetch")
  }
}
medium
A. Syntax error
B. Failed to fetch
C. Data length: 0
D. Data length: [number of bytes in data]

Solution

  1. Step 1: Analyze successful GET request

    If the request succeeds, try await returns data and response without throwing an error.
  2. Step 2: Understand print statement output

    The code prints the length of the received data in bytes, so output is "Data length: [number]".
  3. Final Answer:

    Data length: [number of bytes in data] -> Option D
  4. Quick Check:

    Success prints data length [OK]
Hint: Success prints data length, failure prints error [OK]
Common Mistakes:
  • Assuming print shows raw data
  • Confusing catch block output
  • Expecting zero length on success
4. Identify the error in this Swift async GET request code:
func load() async {
  let url = URL(string: "https://api.example.com")!
  let (data, response) = URLSession.shared.data(from: url)
  print(String(data: data, encoding: .utf8) ?? "No data")
}
medium
A. Incorrect print statement syntax
B. URL is invalid
C. Missing await keyword before URLSession.shared.data(from: url)
D. Missing try keyword before URLSession.shared.data(from: url)

Solution

  1. Step 1: Check async call usage

    The method data(from:) is async and must be awaited with await.
  2. Step 2: Confirm missing await keyword

    The code calls URLSession.shared.data(from: url) without await, causing a compile error.
  3. Final Answer:

    Missing await keyword before URLSession.shared.data(from: url) -> Option C
  4. Quick Check:

    Async calls require await [OK]
Hint: Async calls always need await keyword [OK]
Common Mistakes:
  • Forgetting await on async calls
  • Assuming try is optional
  • Misreading URL validity
5. You want to fetch JSON data from a URL and decode it into a Swift struct using async/await. Which code snippet correctly performs the GET request and decodes the data?
struct User: Decodable {
  let id: Int
  let name: String
}

func fetchUser() async throws -> User {
  let url = URL(string: "https://api.example.com/user")!
  // Which code goes here?
}
hard
A. let (data, _) = try await URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data)
B. let data = try URLSession.shared.data(from: url) return JSONDecoder().decode(User.self, from: data)
C. let (data, _) = URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data)
D. let (data, _) = try await URLSession.shared.dataTask(with: url) return try JSONDecoder().decode(User.self, from: data)

Solution

  1. Step 1: Use async/await with data(from:)

    The correct async call is try await URLSession.shared.data(from: url) which returns data and response.
  2. Step 2: Decode JSON data into struct

    Use JSONDecoder().decode(User.self, from: data) to convert JSON bytes into the User struct.
  3. Final Answer:

    let (data, _) = try await URLSession.shared.data(from: url) return try JSONDecoder().decode(User.self, from: data) -> Option A
  4. Quick Check:

    Use try await with data(from:) and decode JSON [OK]
Hint: Use try await data(from:) then decode JSON [OK]
Common Mistakes:
  • Using dataTask instead of data(from:)
  • Omitting await or try keywords
  • Not decoding JSON properly
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10 questions~5 mineasy hard