[Solved] Identify the error in this Swift async GET request code: func load() async { let url =... let (data, response) = URLSession.shared.data(from: url) print(String(data: data, encoding: .utf8) ?? | iOS Swift

iOS Swift - Networking

Identify the error in this Swift async GET request code:

func load() async {
  let url = URL(string: "https://api.example.com")!
  let (data, response) = URLSession.shared.data(from: url)
  print(String(data: data, encoding: .utf8) ?? "No data")
}

AIncorrect print statement syntax

BURL is invalid

CMissing await keyword before URLSession.shared.data(from: url)

DMissing try keyword before URLSession.shared.data(from: url)

Step-by-Step Solution

Solution:

Step 1: Check async call usage
The method data(from:) is async and must be awaited with await.
Step 2: Confirm missing await keyword
The code calls URLSession.shared.data(from: url) without await, causing a compile error.
Final Answer:
Missing await keyword before URLSession.shared.data(from: url) -> Option C
Quick Check:
Async calls require await [OK]

Quick Trick: Async calls always need await keyword [OK]

Common Mistakes:

Forgetting await on async calls
Assuming try is optional
Misreading URL validity

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More iOS Swift Quizzes

Identify the error in this Swift async GET request code:

Step 1: Check async call usage

Step 2: Confirm missing await keyword

Final Answer:

Quick Check:

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