Complete the formula to get the first 5 rows from the range A1:A10.
=INDEX(A1:A10, SEQUENCE([1]))The SEQUENCE function generates a list of numbers from 1 to the number you specify. Using 5 returns the first 5 rows.
Complete the formula to skip the first 3 rows and get the next 4 rows from A1:A10.
=INDEX(A1:A10, SEQUENCE([1], 1, 4))
The SEQUENCE function here creates 4 numbers starting at 4, which skips the first 3 rows and gets the next 4.
Fix the error in the formula to get 3 rows starting from row 6 in A1:A10.
=INDEX(A1:A10, SEQUENCE([1], 1, 6))
The first argument to SEQUENCE is how many rows to return. To get 3 rows starting at 6, use 3.
Fill both blanks to get 5 rows starting from row 4 in range B2:B20.
=INDEX(B2:B20, SEQUENCE([1], 1, [2]))
The first blank is how many rows to get (5). The second blank is the starting row (4).
Fill all three blanks to get 4 rows starting from row 3 in range C5:C25 and multiply each by 2.
=INDEX(C5:C25, SEQUENCE([1], 1, [2])) * [3]
Get 4 rows starting at 3, then multiply each value by 2.