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Goprogramming~15 mins

Writing first Go program - Mini Project: Build & Apply

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Writing first Go program
📖 Scenario: You want to create a simple Go program that prints a friendly greeting to the screen. This is like saying hello to a new friend using code.
🎯 Goal: Build a Go program that prints the message Hello, Go! to the console.
📋 What You'll Learn
Create a main package
Write a main function
Use fmt.Println to print the greeting
Print exactly Hello, Go!
💡 Why This Matters
🌍 Real World
Every Go program starts with this structure. Printing messages helps you check your program works.
💼 Career
Knowing how to write a basic Go program is essential for software development jobs using Go.
Progress0 / 4 steps
1
Create the main package
Write package main at the top of your Go file to define the package.
Go
Hint

Every Go program starts with a package declaration. Use package main for executable programs.

2
Add the main function
Write a func main() function below the package line to start your program.
Go
Hint

The main function is where your program begins running.

3
Import the fmt package
Add an import statement to include the fmt package above the main function.
Go
Hint

The fmt package lets you print text to the screen.

4
Print the greeting message
Inside the main function, write fmt.Println("Hello, Go!") to print the greeting.
Go
Hint

Use fmt.Println with the exact text Hello, Go! inside quotes.

Practice

(1/5)
1. What is the purpose of the main function in a Go program?
easy
A. It is the starting point where the program begins execution.
B. It defines a package for the program.
C. It imports external libraries.
D. It declares variables for the program.

Solution

  1. Step 1: Understand the role of main function

    The main function is special in Go; it is where the program starts running.
  2. Step 2: Differentiate from other parts

    Packages define code grouping, imports bring libraries, and variables store data, but none start execution.
  3. Final Answer:

    It is the starting point where the program begins execution. -> Option A
  4. Quick Check:

    Program starts at main() -> D [OK]
Hint: Remember: main() is the program's entry point [OK]
Common Mistakes:
  • Confusing package declaration with program start
  • Thinking imports start the program
  • Assuming variables control program flow
2. Which of the following is the correct way to print "Hello, Go!" in a Go program?
easy
A. fmt.Println("Hello, Go!")
B. print("Hello, Go!")
C. fmt.print("Hello, Go!")
D. console.log("Hello, Go!")

Solution

  1. Step 1: Identify the correct print function in Go

    Go uses the fmt package with Println to print with a newline.
  2. Step 2: Check syntax correctness

    fmt.Println("Hello, Go!") is correct; others are either wrong function names or from other languages.
  3. Final Answer:

    fmt.Println("Hello, Go!") -> Option A
  4. Quick Check:

    Use fmt.Println() to print lines in Go [OK]
Hint: Use fmt.Println() for printing with newline [OK]
Common Mistakes:
  • Using fmt.print instead of fmt.Println
  • Using print() which is not standard in Go
  • Using console.log from JavaScript
3. What will be the output of this Go program?
package main
import "fmt"
func main() {
    fmt.Println("Welcome to Go!")
}
medium
A. package main import "fmt" func main() { fmt.Println("Welcome to Go!") }
B. fmt.Println("Welcome to Go!")
C. Welcome to Go!
D. Error: missing main function

Solution

  1. Step 1: Understand program structure

    The program imports fmt and defines main(), which prints the string.
  2. Step 2: Identify output of fmt.Println

    It prints the string exactly: Welcome to Go! with a newline.
  3. Final Answer:

    Welcome to Go! -> Option C
  4. Quick Check:

    fmt.Println prints string output [OK]
Hint: fmt.Println prints the string content, not code [OK]
Common Mistakes:
  • Confusing code with output
  • Expecting code to print itself
  • Thinking main function is missing
4. Identify the error in this Go program:
package main
import "fmt"
func main() {
    fmt.Println("Hello, world!"
}
medium
A. Missing import statement
B. Incorrect function name
C. Missing package declaration
D. Missing closing parenthesis in fmt.Println call

Solution

  1. Step 1: Check syntax of fmt.Println

    The call to fmt.Println is missing a closing parenthesis at the end.
  2. Step 2: Verify other parts

    Package and import are present, function name is correct, so no errors there.
  3. Final Answer:

    Missing closing parenthesis in fmt.Println call -> Option D
  4. Quick Check:

    Check parentheses in function calls [OK]
Hint: Count opening and closing parentheses carefully [OK]
Common Mistakes:
  • Forgetting closing parenthesis in function calls
  • Assuming missing import or package causes this error
  • Misnaming main function
5. You want to write a Go program that prints "Hello" on one line and "World" on the next line. Which code snippet achieves this correctly?
hard
A. package main import "fmt" func main() { fmt.Print("Hello\nWorld") }
B. package main import "fmt" func main() { fmt.Println("Hello") fmt.Println("World") }
C. package main import "fmt" func main() { fmt.Println("Hello\nWorld") }
D. package main import "fmt" func main() { fmt.Print("Hello") fmt.Print("World") }

Solution

  1. Step 1: Understand printing with new lines

    fmt.Println prints text and adds a newline automatically.
  2. Step 2: Check each option's output

    A: Two fmt.Println calls print "Hello" on one line and "World" on the next. Correct.
    B: fmt.Print("Hello\nWorld") prints "Hello\nWorld" (with actual newline) on one line.
    C: fmt.Println("Hello\nWorld") prints "Hello\nWorld" (with actual newline) followed by newline, so output is two lines.
    D: Two fmt.Print calls print "HelloWorld" on one line.
  3. Final Answer:

    package main import "fmt" func main() { fmt.Println("Hello") fmt.Println("World") } -> Option B
  4. Quick Check:

    Use fmt.Println twice for separate lines [OK]
Hint: Use fmt.Println for each line to print separately [OK]
Common Mistakes:
  • Using fmt.Print without newline causes joined output
  • Expecting \n inside fmt.Println to create new line
  • Confusing fmt.Print and fmt.Println behavior
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