Why loops are needed in Go - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print numbers from 1 to 3 using a loop.

Go

for i := 1; i <= [1]; i++ {
    fmt.Println(i)
}

Drag options to blanks, or click blank then click option'

A5

B3

C0

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number too large or too small for the loop condition.

The loop runs while i is less than or equal to 3, printing numbers 1, 2, and 3.

2fill in blank

medium

Complete the code to sum numbers from 1 to 4 using a loop.

Go

sum := 0
for i := 1; i <= 4; [1] {
    sum += i
}
fmt.Println(sum)

Drag options to blanks, or click blank then click option'

Ai++

Bi += 2

Ci = i

Di--

Attempts:

3 left

💡 Hint

Common Mistakes

Using i-- which decreases the variable and causes an infinite loop.

The loop variable i increases by 1 each time to add all numbers from 1 to 4.

3fill in blank

hard

Fix the error in the loop to print numbers from 1 to 5.

Go

for i := 1; i < [1]; i++ {
    fmt.Println(i)
}

Drag options to blanks, or click blank then click option'

A5

B4

C6

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using i < 5 which stops before printing 5.

Using i < 6 makes the loop print numbers 1 to 5 because it stops before 6.

4fill in blank

hard

Fill both blanks to create a loop that prints even numbers from 2 to 8.

Go

for i := [1]; i <= [2]; i += 2 {
    fmt.Println(i)
}

Drag options to blanks, or click blank then click option'

A2

B1

C8

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Starting at 1 or stopping before 8.

The loop starts at 2 and goes up to 8, increasing by 2 each time to print even numbers.

5fill in blank

hard

Fill all three blanks to create a loop that prints numbers from 10 down to 6.

Go

for i := [1]; i [2] [3]; i-- {
    fmt.Println(i)
}

Drag options to blanks, or click blank then click option'

A10

B>=

C6

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using <= instead of >= in the condition.

The loop starts at 10 and decreases by 1 until it reaches 6, printing numbers 10 to 6.

Practice

1. Why do we use loops like for in Go programming?

easy

A. To stop the program from running

B. To store data permanently

C. To create new variables

D. To repeat a set of instructions multiple times without rewriting code

Solution

1. Step 1: Understand the purpose of loops

   Loops allow repeating actions multiple times without writing the same code again.

2. Step 2: Identify the correct use case

   Using loops saves time and makes code shorter and easier to manage.

3. Final Answer:

   To repeat a set of instructions multiple times without rewriting code -> Option D

4. Quick Check:

   Loops repeat actions = A [OK]

Hint: Loops repeat tasks to avoid rewriting code [OK]

Common Mistakes:

• Thinking loops store data
• Confusing loops with variable creation
• Believing loops stop program execution

2. Which of the following is the correct syntax for a basic for loop in Go?

easy

A. for i := 0; i < 5; i++ { fmt.Println(i) }

B. loop i from 0 to 5 { fmt.Println(i) }

C. while i < 5 { fmt.Println(i) }

D. repeat 5 times { fmt.Println(i) }

Solution

1. Step 1: Recall Go loop syntax

   Go uses for with initialization, condition, and post statement separated by semicolons.

2. Step 2: Match syntax to options

   for i := 0; i < 5; i++ { fmt.Println(i) } matches Go's for loop syntax exactly.

3. Final Answer:

   for i := 0; i < 5; i++ { fmt.Println(i) } -> Option A

4. Quick Check:

   Go uses for with semicolons = C [OK]

Hint: Go loops use for with semicolons, not while or loop [OK]

Common Mistakes:

• Using while instead of for
• Using loop keyword which Go doesn't have
• Missing semicolons in for loop

3. What will be the output of this Go code?

for i := 1; i <= 3; i++ {
    fmt.Print(i, " ")
}

medium

A. 1 2 3

B. 0 1 2 3

C. 1 2 3 4

D. 3 2 1

Solution

1. Step 1: Analyze loop range

   The loop starts at i=1 and runs while i is less than or equal to 3, incrementing by 1 each time.

2. Step 2: Trace output for each iteration

   It prints 1, then 2, then 3, each followed by a space.

3. Final Answer:

   1 2 3 -> Option A

4. Quick Check:

   Loop prints 1 to 3 = D [OK]

Hint: Check loop start, end, and increments carefully [OK]

Common Mistakes:

• Starting loop from 0 instead of 1
• Including extra numbers beyond 3
• Printing in reverse order

4. Identify the error in this Go loop code:

for i := 0; i < 5 i++ {
    fmt.Println(i)
}

medium

A. Incorrect variable declaration

B. Using wrong loop keyword

C. Missing semicolon between condition and increment

D. Missing braces around loop body

Solution

1. Step 1: Check for syntax errors in for loop

   Go requires semicolons separating initialization, condition, and post statements in for loops.

2. Step 2: Locate missing semicolon

   The code misses a semicolon between i < 5 and i++.

3. Final Answer:

   Missing semicolon between condition and increment -> Option C

4. Quick Check:

   For loop parts need semicolons = A [OK]

Hint: Remember semicolons separate for loop parts [OK]

Common Mistakes:

• Omitting semicolons in for loop header
• Using while instead of for
• Forgetting braces for loop body

5. You want to print all even numbers from 2 to 10 using a loop in Go. Which code snippet correctly does this?

hard

A. for i := 2; i < 10; i += 2 { fmt.Println(i) }

B. for i := 1; i <= 10; i++ { if i%2 == 0 { fmt.Println(i) } }

C. for i := 2; i < 10; i++ { if i%2 == 0 { fmt.Println(i) } }

D. for i := 2; i <= 10; i++ { fmt.Println(i*2) }

Solution

1. Step 1: Understand the goal

   We want to print even numbers from 2 to 10 inclusive.

2. Step 2: Check each option

   for i := 2; i < 10; i += 2 { fmt.Println(i) } prints 2,4,6,8 missing 10.
   for i := 1; i <= 10; i++ { if i%2 == 0 { fmt.Println(i) } } loops 1 to 10 and prints only if number is even.
   for i := 2; i < 10; i++ { if i%2 == 0 { fmt.Println(i) } } loops 2 to 9, missing 10.
   for i := 2; i <= 10; i++ { fmt.Println(i*2) } prints multiples of i*2, which gives 4,6,8,... not correct.

3. Step 3: Identify the correct option

   for i := 1; i <= 10; i++ { if i%2 == 0 { fmt.Println(i) } } correctly prints all even numbers from 2 to 10 inclusive.

4. Final Answer:

   for i := 1; i <= 10; i++ { if i%2 == 0 { fmt.Println(i) } } -> Option B

5. Quick Check:

   Check condition inside loop for even numbers = B [OK]

Hint: Use if inside loop to filter even numbers [OK]

Common Mistakes:

• Forgetting to include 10 in range
• Incrementing by wrong step
• Printing wrong multiples