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Goprogramming~10 mins

Why input and output are required in Go - Test Your Understanding

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to read a number from the user.

Go
var num int
fmt.Scanln([1])
Drag options to blanks, or click blank then click option'
Anum&
Bnum
C*num
D&num
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Passing the variable without & causes runtime error.
Using *num is invalid syntax for input.
2fill in blank
medium

Complete the code to print the value of num.

Go
fmt.Println([1])
Drag options to blanks, or click blank then click option'
Anum&
Bnum
C*num
D&num
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using &num prints the memory address, not the value.
Using *num causes error unless num is a pointer.
3fill in blank
hard

Fix the error in reading input into variable x.

Go
var x int
fmt.Scanln([1])
Drag options to blanks, or click blank then click option'
A&x
Bx&
C*x
Dx
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Passing x instead of &x causes input to fail.
Using *x is invalid because x is not a pointer.
4fill in blank
hard

Fill both blanks to create a program that reads and prints a string.

Go
var input string
fmt.Scanln([1])
fmt.Println([2])
Drag options to blanks, or click blank then click option'
A&input
Binput
Cinput&
D*input
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using input instead of &input for reading input.
Using &input when printing prints the address.
5fill in blank
hard

Fill all three blanks to read two integers and print their sum.

Go
var a, b int
fmt.Scanln([1], [2])
sum := [3]
fmt.Println(sum)
Drag options to blanks, or click blank then click option'
A&a
B&b
Ca + b
Da - b
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Passing a and b instead of &a and &b to Scanln.
Using subtraction instead of addition for sum.

Practice

(1/5)
1. Why do programs need input and output?
easy
A. To avoid writing code
B. To run faster without errors
C. To use more memory
D. To interact with users and show results

Solution

  1. Step 1: Understand the role of input

    Input allows programs to receive information from users or files, which is necessary to perform tasks.
  2. Step 2: Understand the role of output

    Output lets programs display results or messages back to users, completing the interaction.
  3. Final Answer:

    To interact with users and show results -> Option D
  4. Quick Check:

    Input and output enable interaction = A [OK]
Hint: Input gets data; output shows results [OK]
Common Mistakes:
  • Thinking input/output only affects speed
  • Believing programs don't need to communicate
  • Confusing input/output with memory usage
2. Which Go code snippet correctly reads input from the user?
easy
A. fmt.Scanln(&name)
B. fmt.Println(name)
C. var name string = input()
D. read(name)

Solution

  1. Step 1: Identify correct input function in Go

    In Go, fmt.Scanln(&variable) reads input from the user into the variable.
  2. Step 2: Check other options for correctness

    fmt.Println prints output, not input; input() and read() are not valid Go functions.
  3. Final Answer:

    fmt.Scanln(&name) -> Option A
  4. Quick Check:

    Use fmt.Scanln for input = C [OK]
Hint: Use fmt.Scanln(&var) to read input [OK]
Common Mistakes:
  • Using fmt.Println to read input
  • Assuming input() exists in Go
  • Forgetting the & before variable
3. What will be the output of this Go program?
package main
import "fmt"
func main() {
    var name string
    fmt.Print("Enter name: ")
    fmt.Scanln(&name)
    fmt.Println("Hello,", name)
}
medium
A. Syntax error
B. Enter name: Hello,
C. Hello,
D. Hello, name

Solution

  1. Step 1: Understand input reading

    The program asks for input with fmt.Print, then reads user input into variable 'name'.
  2. Step 2: Understand output printing

    It prints "Hello," followed by the input value stored in 'name'.
  3. Final Answer:

    Hello, <user input> -> Option C
  4. Quick Check:

    Input read and printed = D [OK]
Hint: Input stored in variable, then printed [OK]
Common Mistakes:
  • Expecting prompt and output on same line
  • Confusing variable name with string literal
  • Thinking code has syntax errors
4. Find the error in this Go code that reads input and prints it:
package main
import "fmt"
func main() {
    var age int
    fmt.Scanln(age)
    fmt.Println("Age is", age)
}
medium
A. fmt.Println cannot print variables
B. Missing & before variable in fmt.Scanln
C. Variable age should be string
D. No import for fmt package

Solution

  1. Step 1: Check input reading syntax

    fmt.Scanln requires a pointer to variable, so &age is needed, not age.
  2. Step 2: Verify other parts

    fmt.Println can print variables; age as int is fine; fmt is imported correctly.
  3. Final Answer:

    Missing & before variable in fmt.Scanln -> Option B
  4. Quick Check:

    Use &variable for input = B [OK]
Hint: Always use & before variable in fmt.Scanln [OK]
Common Mistakes:
  • Omitting & causes runtime error
  • Thinking fmt.Println can't print variables
  • Changing variable type unnecessarily
5. You want to write a Go program that asks the user for two numbers, adds them, and shows the result. Why is input and output required here?
hard
A. Input gets numbers from user; output shows the sum
B. Input stores the sum; output reads numbers
C. Input and output are not needed for calculations
D. Only output is needed to display the sum

Solution

  1. Step 1: Understand input role in the program

    The program needs input to get the two numbers from the user to add them.
  2. Step 2: Understand output role in the program

    After adding, output is needed to show the sum to the user.
  3. Final Answer:

    Input gets numbers from user; output shows the sum -> Option A
  4. Quick Check:

    Input for data, output for result = A [OK]
Hint: Input collects data; output shows answers [OK]
Common Mistakes:
  • Thinking calculations happen without input
  • Believing output can replace input
  • Ignoring need to show results
Recommended

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10 questions~5 mineasy hard