Increment and decrement in Go - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to increment the variable count by 1.

Go

package main

import "fmt"

func main() {
    count := 5
    count[1]
    fmt.Println(count)
}

Drag options to blanks, or click blank then click option'

A++

B+=

C++=

D--

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+=' causes a syntax error because it requires an operand like 1 after it.

Using '--' decreases the value instead of increasing.

In Go, count++ increases count by 1. The ++ operator is a postfix statement, not an expression.

2fill in blank

medium

Complete the code to decrement the variable num by 1 using the correct operator.

Go

package main

import "fmt"

func main() {
    num := 10
    num[1] 1
    fmt.Println(num)
}

Drag options to blanks, or click blank then click option'

A-=

B+=

C++

D--

Attempts:

3 left

💡 Hint

Common Mistakes

Using '--' with a value causes syntax error.

Using '+=' increases the value instead of decreasing.

The operator -= subtracts a value from a variable. So num -= 1 decreases num by 1.

3fill in blank

hard

Fix the error in the code to correctly increment value by 1.

Go

package main

import "fmt"

func main() {
    value := 3
    value [1]
    fmt.Println(value)
}

Drag options to blanks, or click blank then click option'

A--

B++

C++ 1

D+= 1

Attempts:

3 left

💡 Hint

Common Mistakes

Using '++' causes syntax error due to the space separating variable and operator.

Using '++ 1' is invalid syntax.

In Go, value += 1 correctly increments value by 1 given the space after value. The ++ operator requires no space: value++.

4fill in blank

hard

Fill both blanks to create a map of words to their lengths, including only words longer than 3 characters.

Go

package main

import "fmt"

func main() {
    words := []string{"go", "code", "play", "fun"}
    lengths := make(map[string]int)
    for _, word := range words {
        if len(word) > 3 {
            lengths[[1]] = len([2])
        }
    }
    fmt.Println(lengths)
}

Drag options to blanks, or click blank then click option'

A"word"

Bword

Cwords

D"words"

Attempts:

3 left

💡 Hint

Common Mistakes

Using '"word"' (quoted literal) instead of variable word for dynamic key.

Using the whole list 'words' instead of the current 'word' for length.

In the loop's if block, use word as the key (string variable, no quotes). Use word for len(word) value.

5fill in blank

hard

Fill all three blanks to create a map of uppercase words to their lengths, including only words longer than 3 characters.

Go

package main

import (
    "fmt"
    "strings"
)

func main() {
    words := []string{"go", "code", "play", "fun"}
    lengths := make(map[string]int)
    for _, word := range words {
        if len(word) [3] 3 {
            lengths[[1]] = [2]
        }
    }
    fmt.Println(lengths)
}

Drag options to blanks, or click blank then click option'

Astrings.ToUpper(word)

Blen(word)

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the original word instead of uppercase as key.

Using '<' instead of '>' in the condition.

Use strings.ToUpper(word) to convert the word to uppercase for the key. Use len(word) for the value. The condition len(word) > 3 filters words longer than 3 characters.