For loop as while in Go - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a loop that runs while i is less than 5.

Go

package main

import "fmt"

func main() {
    i := 0
    for [1] {
        fmt.Println(i)
        i++
    }
}

Drag options to blanks, or click blank then click option'

Ai < 5

Bi <= 5

Ci > 5

Di == 5

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'i > 5' which never runs the loop initially.

Using 'i == 5' which runs only when i equals 5.

The condition i < 5 makes the loop run while i is less than 5.

2fill in blank

medium

Complete the code to print numbers from 1 to 3 using a for loop as while.

Go

package main

import "fmt"

func main() {
    i := 1
    for [1] {
        fmt.Println(i)
        i++
    }
}

Drag options to blanks, or click blank then click option'

Ai < 3

Bi <= 3

Ci >= 3

Di == 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'i < 3' which stops before printing 3.

Using 'i == 3' which runs only once when i equals 3.

The condition i <= 3 makes the loop run while i is 1, 2, and 3.

3fill in blank

hard

Fix the error in the loop condition to run while count is less than 4.

Go

package main

import "fmt"

func main() {
    count := 0
    for [1] {
        fmt.Println(count)
        count++
    }
}

Drag options to blanks, or click blank then click option'

Acount >= 4

Bcount > 4

Ccount < 4

Dcount == 4

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'count > 4' which never runs the loop initially.

Using 'count == 4' which runs only once when count equals 4.

The condition count < 4 runs the loop while count is 0, 1, 2, and 3.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers from 2 to 6.

Go

package main

import "fmt"

func main() {
    num := 2
    for [1] {
        fmt.Println(num)
        num [2]
    }
}

Drag options to blanks, or click blank then click option'

Anum <= 6

Bnum < 6

C++

D++num

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'num < 6' which stops before printing 6.

Using '++num' which is invalid syntax in Go.

The condition num <= 6 keeps the loop running until 6. The increment num++ increases num by 1 each time.

5fill in blank

hard

Fill all three blanks to create a loop that prints even numbers from 0 to 4.

Go

package main

import "fmt"

func main() {
    i := 0
    for [1] {
        fmt.Println(i)
        i [2] 2
    }
}

Drag options to blanks, or click blank then click option'

Ai <= 4

B+=

C-=

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' as an operator in the increment step.

Using '-=' which decreases i instead of increasing.

The condition i <= 4 runs the loop while i is 0, 2, and 4. The operator += adds 2 to i each time.

Practice

1. Which of the following is the correct way to write a while loop in Go using a for loop?

easy

A. for i < 5 { i++ }

B. while i < 5 { i++ }

C. for (i < 5) { i++ }

D. loop i < 5 { i++ }

Solution

1. Step 1: Understand Go's while loop syntax

   Go uses for condition { } to act like a while loop.

2. Step 2: Identify the correct syntax

   for i < 5 { i++ } uses for i < 5 { i++ }, which is valid Go syntax for a while loop.

3. Final Answer:

   for i < 5 { i++ } -> Option A

4. Quick Check:

   Go while loop = for condition { } [OK]

Hint: Remember: Go uses 'for' with condition as while loop [OK]

Common Mistakes:

• Using 'while' keyword which Go does not support
• Adding parentheses around the condition unnecessarily
• Using 'loop' keyword which is invalid in Go

2. Which of the following Go code snippets correctly uses a for loop as a while loop to print numbers from 1 to 3?

easy

A. i := 1
for i <= 3 {
fmt.Println(i)
i++
}

B. i := 1
for (i <= 3) {
fmt.Println(i)
i++
}

C. i := 1
for i < 3 {
fmt.Println(i)
i++
}

D. i := 1
while i <= 3 {
fmt.Println(i)
i++
}

Solution

1. Step 1: Check syntax for Go while loop

   Go uses for condition { } without parentheses around condition.

2. Step 2: Verify loop condition and output

   i := 1 for i <= 3 { fmt.Println(i) i++ } uses i <= 3 and increments i, printing 1, 2, 3 correctly.

3. Final Answer:

   i := 1 for i <= 3 { fmt.Println(i) i++ } -> Option A

4. Quick Check:

   Correct Go while loop syntax = i := 1 for i <= 3 { fmt.Println(i) i++ } [OK]

Hint: No parentheses needed around condition in Go for loop [OK]

Common Mistakes:

• Using 'while' keyword which is invalid in Go
• Using '<' instead of '<=' causing missing last number
• Adding parentheses around condition causing syntax error

3. What will be the output of the following Go code?

i := 0
for i < 3 {
    fmt.Print(i, " ")
    i++
}

medium

A. 1 2 3

B. 0 1 2

C. 0 1 2 3

D. 1 2

Solution

1. Step 1: Analyze loop condition and initial value

   Variable i starts at 0 and loop runs while i < 3.

2. Step 2: Trace loop iterations and output

   i prints 0, then increments to 1; prints 1, increments to 2; prints 2, increments to 3; loop stops.

3. Final Answer:

   0 1 2 -> Option B

4. Quick Check:

   Loop prints 0 to 2 with spaces [OK]

Hint: Loop runs while condition true, stops when false [OK]

Common Mistakes:

• Assuming loop includes i=3 output
• Starting i from 1 instead of 0
• Forgetting to increment i causing infinite loop

4. Identify the error in the following Go code that tries to use a for loop as a while loop:

i := 0
for i < 3 {
    fmt.Println(i)
}

medium

A. Variable i should be declared inside the loop

B. Incorrect loop condition syntax

C. Using fmt.Println instead of fmt.Print

D. Missing increment of i inside the loop causing infinite loop

Solution

1. Step 1: Check loop condition and body

   The loop condition is valid, but i is never changed inside the loop.

2. Step 2: Understand consequences of missing increment

   Without incrementing i, the condition i < 3 remains true forever, causing an infinite loop.

3. Final Answer:

   Missing increment of i inside the loop causing infinite loop -> Option D

4. Quick Check:

   Change loop variable inside loop to avoid infinite loop [OK]

Hint: Always update loop variable inside for-as-while loop [OK]

Common Mistakes:

• Forgetting to increment or change loop variable
• Thinking fmt.Println causes error
• Declaring variable inside loop unnecessarily

5. You want to use a for loop as a while loop in Go to read user input until the user types "exit". Which code snippet correctly implements this?

hard

A. var input string
for input != "exit" {
fmt.Print("Enter text: ")
fmt.Scanln(&input)
}

B. var input string
for input == "exit" {
fmt.Print("Enter text: ")
fmt.Scanln(&input)
}

C. var input string
for {
fmt.Print("Enter text: ")
fmt.Scanln(&input)
if input == "exit" { break }
}

D. var input string
while input != "exit" {
fmt.Print("Enter text: ")
fmt.Scanln(&input)
}

Solution

1. Step 1: Understand the loop condition for reading input

   We want to keep reading until input equals "exit".

2. Step 2: Analyze options for correct loop behavior

   var input string for { fmt.Print("Enter text: ") fmt.Scanln(&input) if input == "exit" { break } } uses an infinite loop with a break when input is "exit", which is safe and common in Go.

3. Step 3: Why other options fail

   var input string for input != "exit" { fmt.Print("Enter text: ") fmt.Scanln(&input) } uses input before reading it, so loop condition is false initially (empty string != "exit" is true, but input is empty initially). var input string for input == "exit" { fmt.Print("Enter text: ") fmt.Scanln(&input) } loops only if input == "exit" which is opposite. var input string while input != "exit" { fmt.Print("Enter text: ") fmt.Scanln(&input) } uses invalid 'while' keyword.

4. Final Answer:

   Use infinite for loop with break on "exit" input -> Option C

5. Quick Check:

   Use for { ... if condition { break } } for while loops with input [OK]

Hint: Use infinite loop with break for input-based while loops [OK]

Common Mistakes:

• Using 'while' keyword which is invalid in Go
• Checking condition before first input read
• Using wrong loop condition causing no input read