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Goprogramming~10 mins

Constants in Go - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare a constant named Pi with the value 3.14.

Go
const Pi [1] 3.14
Drag options to blanks, or click blank then click option'
A=
B:=
C==
D:
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using := instead of = for constants
Using == which is a comparison operator
2fill in blank
medium

Complete the code to declare multiple constants Pi and E with values 3.14 and 2.71.

Go
const (
    Pi [1] 3.14
    E  [1] 2.71
)
Drag options to blanks, or click blank then click option'
A:=
B==
C=
D:
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using := inside const blocks
Using : instead of =
3fill in blank
hard

Fix the error in the constant declaration to assign the value 100 to MaxScore.

Go
const MaxScore [1] 100
Drag options to blanks, or click blank then click option'
A:=
B=
C==
D:
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using := instead of =
Using == which causes syntax errors
4fill in blank
hard

Fill both blanks to declare constants Width and Height with values 1920 and 1080.

Go
const Width [1] 1920
const Height [2] 1080
Drag options to blanks, or click blank then click option'
A=
B:=
C==
D:
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using := for constants
Using : or == instead of =
5fill in blank
hard

Fill all three blanks to declare constants Name, Age, and Active with values "Alice", 30, and true.

Go
const Name [1] "Alice"
const Age [2] 30
const Active [3] true
Drag options to blanks, or click blank then click option'
A=
B:=
C==
D:
Attempts:
3 left
๐Ÿ’ก Hint
Common Mistakes
Using := for constants
Using == or : instead of =

Practice

(1/5)
1. What is the purpose of using const in Go programming?
easy
A. To declare a value that cannot be changed
B. To declare a variable that can change
C. To create a function
D. To start a loop

Solution

  1. Step 1: Understand the role of const

    The const keyword is used to declare constants, which are fixed values that cannot be changed after being set.
  2. Step 2: Compare options with the definition

    To declare a value that cannot be changed correctly states that const declares a value that cannot be changed, while other options describe unrelated concepts.
  3. Final Answer:

    To declare a value that cannot be changed -> Option A
  4. Quick Check:

    Constants = fixed values [OK]
Hint: Constants hold fixed values, variables do not change [OK]
Common Mistakes:
  • Confusing constants with variables
  • Thinking const declares functions
  • Assuming const starts loops
2. Which of the following is the correct way to declare a constant named Pi with value 3.14 in Go?
easy
A. const Pi = 3.14
B. let Pi = 3.14
C. Pi := 3.14
D. var Pi = 3.14

Solution

  1. Step 1: Recall Go syntax for constants

    In Go, constants are declared using the const keyword followed by the name and value.
  2. Step 2: Identify the correct syntax

    const Pi = 3.14 uses const Pi = 3.14, which is the correct syntax. Options A and C declare variables, and B uses invalid Go syntax.
  3. Final Answer:

    const Pi = 3.14 -> Option A
  4. Quick Check:

    const keyword = correct declaration [OK]
Hint: Use const keyword for fixed values, not var or := [OK]
Common Mistakes:
  • Using var or := instead of const
  • Using let which is not Go syntax
  • Missing the const keyword
3. What will be the output of this Go program?
package main
import "fmt"
const greeting = "Hello"
func main() {
    fmt.Println(greeting)
}
medium
A. greeting
B. Compilation error
C. Hello\n
D. Hello

Solution

  1. Step 1: Understand constant usage in the program

    The constant greeting is declared with value "Hello" and printed in main.
  2. Step 2: Predict the output of fmt.Println

    fmt.Println(greeting) prints the string value of the constant, which is "Hello" without quotes.
  3. Final Answer:

    Hello -> Option D
  4. Quick Check:

    Printing constant value = Hello [OK]
Hint: Print constant name to get its fixed value output [OK]
Common Mistakes:
  • Expecting the name 'greeting' to print
  • Thinking it prints with quotes
  • Assuming a compile error
4. Identify the error in this Go code snippet:
package main
import "fmt"
const x = 10
func main() {
    x = 20
    fmt.Println(x)
}
medium
A. Variable 'x' not declared
B. Cannot assign to constant 'x' after declaration
C. Missing import of fmt package
D. No error, code runs fine

Solution

  1. Step 1: Check constant reassignment

    The code declares x as a constant with value 10, then tries to assign 20 to it, which is not allowed.
  2. Step 2: Verify other possible errors

    There are no other compilation errors; the only issue is reassignment of the constant.
  3. Final Answer:

    Cannot assign to constant 'x' after declaration -> Option B
  4. Quick Check:

    Constants cannot be reassigned [OK]
Hint: Constants cannot be changed after declaration [OK]
Common Mistakes:
  • Trying to assign new value to a constant
  • Ignoring missing imports
  • Confusing constants with variables
5. Given the following Go code, what will be the output?
package main
import "fmt"
const (
    A = iota
    B
    C = 5
    D
)
func main() {
    fmt.Println(A, B, C, D)
}
hard
A. 0 1 2 3
B. 0 1 5 5
C. 0 1 5 3
D. Compilation error due to iota usage

Solution

  1. Step 1: Understand iota behavior in constant blocks

    iota starts at 0 and increments by 1 for each line unless overridden.
  2. Step 2: Analyze each constant value

    A = iota (0), iota increments to 1; B = iota (1), iota to 2; C = 5 (explicit), iota to 3; D = iota (3).
  3. Step 3: Confirm output

    Printing A, B, C, D outputs: 0 1 5 3
  4. Final Answer:

    0 1 5 3 -> Option C
  5. Quick Check:

    iota increments except when overridden [OK]
Hint: iota increments unless constant value is explicitly set [OK]
Common Mistakes:
  • Assuming D equals C's value (5)
  • Thinking iota resets after explicit value
  • Expecting compilation error
Recommended

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10 questions~5 mineasy hard