Break statement in Go - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to exit the loop when i equals 3.

Go

for i := 1; i <= 5; i++ {
    if i == 3 {
        [1]
    }
    fmt.Println(i)
}

Drag options to blanks, or click blank then click option'

Abreak

Breturn

Ccontinue

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' instead of 'break' causes the loop to skip the current iteration but not exit.

Using 'return' inside the loop exits the function, not just the loop.

The break statement exits the nearest enclosing loop immediately.

2fill in blank

medium

Complete the code to stop the loop when the character 'x' is found in the string.

Go

str := "golang"
for _, ch := range str {
    if ch == '[1]' {
        break
    }
    fmt.Printf("%c", ch)
}

Drag options to blanks, or click blank then click option'

Ax

Bo

Ca

Dg

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a character that is in the string but not intended to stop the loop.

Using double quotes instead of single quotes for a rune.

The loop breaks when the character 'x' is found, stopping the printing.

3fill in blank

hard

Fix the error in the loop to break when the number is greater than 10.

Go

nums := []int{5, 8, 12, 3}
for _, num := range nums {
    if num [1] 10 {
        break
    }
    fmt.Println(num)
}

Drag options to blanks, or click blank then click option'

A<=

B<

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' breaks the loop too early or too late.

Using '==' only breaks if the number equals 10 exactly.

The condition should check if the number is greater than 10 to break the loop.

4fill in blank

hard

Fill both blanks to create a map of squares for numbers greater than 2.

Go

squares := map[int]int{}
for i := 1; i <= 5; i++ {
    if i [1] 2 {
        squares[i] = i [2] i
    }
}

Drag options to blanks, or click blank then click option'

A>

B<

C**

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' causes wrong numbers to be squared.

Using '**' is invalid in Go for exponentiation.

The loop adds squares of numbers greater than 2 using the multiplication operator.

5fill in blank

hard

Fill the blanks to create a map of uppercase keys and values greater than 0.

Go

import "strings"
data := map[string]int{"a": 1, "b": 0, "c": 3}
result := map[string]int{}
for k, v := range data {
    if v [1] 0 {
        result[[2]] = v
    }
}

fmt.Println(result)

Drag options to blanks, or click blank then click option'

A>=

B>

Ck

Dstrings.ToUpper(k)

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>=' includes zero values, which is not intended.

Using 'k' as key keeps keys lowercase.

The loop adds entries with values greater than 0, using uppercase keys.

Practice

1. What does the break statement do inside a loop in Go?

easy

A. It pauses the loop for a moment and then continues.

B. It skips the current iteration and moves to the next one.

C. It immediately stops the loop and continues after it.

D. It restarts the loop from the beginning.

Solution

1. Step 1: Understand the role of break in loops

   The break statement is used to exit a loop immediately, stopping any further iterations.

2. Step 2: Compare with other loop controls

   Unlike continue which skips to the next iteration, break stops the loop entirely and moves on.

3. Final Answer:

   It immediately stops the loop and continues after it. -> Option C

4. Quick Check:

   Break stops loop = It immediately stops the loop and continues after it. [OK]

Hint: Break stops loop immediately, no more repeats [OK]

Common Mistakes:

• Confusing break with continue
• Thinking break pauses the loop
• Assuming break restarts the loop

2. Which of the following is the correct syntax to use break inside a for loop in Go?

easy

A. for i := 0; i < 5; i++ { if i == 3 { exit } }

B. for i := 0; i < 5; i++ { if i == 3 { stop } }

C. for i := 0; i < 5; i++ { if i == 3 { continue } }

D. for i := 0; i < 5; i++ { if i == 3 { break } }

Solution

1. Step 1: Identify the correct keyword for stopping a loop

   In Go, break is the keyword used to exit a loop early.

2. Step 2: Check syntax correctness

   for i := 0; i < 5; i++ { if i == 3 { break } } uses break correctly inside an if statement within the for loop.

3. Final Answer:

   for i := 0; i < 5; i++ { if i == 3 { break } } -> Option D

4. Quick Check:

   Correct break syntax = for i := 0; i < 5; i++ { if i == 3 { break } } [OK]

Hint: Use 'break' keyword exactly to stop loops [OK]

Common Mistakes:

• Using 'stop' or 'exit' instead of 'break'
• Confusing 'continue' with 'break'
• Missing curly braces around break

3. What will be the output of this Go code?

for i := 1; i <= 5; i++ {
    if i == 3 {
        break
    }
    fmt.Print(i, " ")
}

medium

A. 1 2 3 4 5

B. 1 2

C. 3 4 5

D. 1 2 3

Solution

1. Step 1: Trace the loop iterations

   The loop starts at i=1 and prints i. When i=3, the break stops the loop immediately.

2. Step 2: Determine printed values before break

   Values printed before break are 1 and 2, then loop stops before printing 3.

3. Final Answer:

   1 2 -> Option B

4. Quick Check:

   Break at 3 stops loop = 1 2 [OK]

Hint: Break stops before printing 3, so only 1 and 2 print [OK]

Common Mistakes:

• Including 3 in output
• Printing all numbers ignoring break
• Confusing break with continue

4. Find the error in this Go code snippet using break:

for i := 0; i < 5; i++ {
    if i == 2 {
        break 2
    }
    fmt.Println(i)
}

medium

A. Using break with a number is invalid in Go.

B. The loop condition is wrong.

C. fmt.Println is not imported.

D. The break statement should be continue.

Solution

1. Step 1: Understand break usage in Go

   Go's break does not accept a number to break multiple loops; it only breaks the closest loop.

2. Step 2: Identify invalid syntax

   Using break 2 causes a syntax error because Go does not support labeled breaks with numbers.

3. Final Answer:

   Using break with a number is invalid in Go. -> Option A

4. Quick Check:

   Break with number invalid = Using break with a number is invalid in Go. [OK]

Hint: Go break never takes a number, only plain break [OK]

Common Mistakes:

• Trying to break multiple loops with a number
• Confusing Go with other languages like JavaScript
• Ignoring syntax errors from break usage

5. Given nested loops, how can you use break to exit only the inner loop in Go?

for i := 1; i <= 3; i++ {
    for j := 1; j <= 3; j++ {
        if j == 2 {
            break
        }
        fmt.Printf("%d,%d ", i, j)
    }
}

What will be the output?

hard

A. 1,1 2,1 3,1

B. 1,1 1,2 2,1 2,2 3,1 3,2

C. 1,1 1,2 2,1 2,2 3,1 3,2 2,2 3,2

D. 1,1 1,2 1,3 2,1 2,2 2,3 3,1 3,2 3,3

Solution

1. Step 1: Understand break in nested loops

   The break inside the inner loop stops only that inner loop when j == 2.

2. Step 2: Trace output for each iteration

   For each i, inner loop prints when j=1, then breaks at j=2, so output is pairs with j=1 only.

3. Final Answer:

   1,1 2,1 3,1 -> Option A

4. Quick Check:

   Break stops inner loop only = 1,1 2,1 3,1 [OK]

Hint: Break stops only closest loop, inner loop ends early [OK]

Common Mistakes:

• Thinking break exits both loops
• Expecting all j values printed
• Confusing break with continue