Tabulation is a bottom-up approach in dynamic programming where we solve smaller subproblems first and store their results in a table (usually an array). Then, we use these results to solve bigger problems step by step.
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beginner
How does Tabulation differ from Memoization?
Tabulation solves problems iteratively from the smallest subproblem up to the main problem, filling a table. Memoization solves problems recursively and stores results to avoid repeated work.
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intermediate
Why is Tabulation often preferred over Memoization?
Tabulation avoids the overhead of recursion and stack calls, making it more efficient in time and space for many problems. It also guarantees all subproblems are solved in order.
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beginner
In Tabulation, what does the table usually represent?
The table stores the results of subproblems, where each entry corresponds to a smaller problem's solution. This helps build up the answer to the main problem without recomputation.
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beginner
Explain the general steps to solve a problem using Tabulation.
1. Identify the subproblems. 2. Decide the order to solve subproblems (usually smallest to largest). 3. Create a table to store results. 4. Fill the table iteratively using previous results. 5. Return the final answer from the table.
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What approach does Tabulation use in dynamic programming?
ABottom-up iterative
BTop-down recursive
CRandom guessing
DDivide and conquer without storage
✗ Incorrect
Tabulation uses a bottom-up iterative approach to solve subproblems and build the solution.
Which of these is a key advantage of Tabulation over Memoization?
ARequires complex recursion
BUses more memory
CSlower execution
DAvoids recursion overhead
✗ Incorrect
Tabulation avoids recursion overhead by solving problems iteratively.
In Tabulation, what do we store in the table?
AResults of subproblems
BInput values only
CRandom numbers
DFinal answer only
✗ Incorrect
The table stores results of subproblems to reuse them in building the final solution.
Which problem-solving order is typical in Tabulation?
ALargest subproblems to smallest
BRandom order
CSmallest subproblems to largest
DOnly the main problem
✗ Incorrect
Tabulation solves from smallest subproblems up to the main problem.
Which of these is NOT a step in Tabulation?
AFilling a table iteratively
BUsing recursion to solve subproblems
CIdentifying subproblems
DReturning the final answer from the table
✗ Incorrect
Tabulation does not use recursion; it uses iteration.
Describe how Tabulation solves dynamic programming problems step by step.
Think about building the solution from the bottom up.
You got /5 concepts.
Explain the difference between Tabulation and Memoization in simple terms.
Focus on the order and method of solving subproblems.
You got /4 concepts.
Practice
(1/5)
1. What is the main idea behind Tabulation Bottom Up DP?
easy
A. Build a table from the smallest subproblems up to the main problem
B. Solve the problem by dividing it into two halves recursively
C. Use recursion with memoization to avoid repeated work
D. Randomly guess answers and check correctness
Solution
Step 1: Understand Tabulation approach
Tabulation means filling a table starting from the smallest subproblems, moving upwards.
Step 2: Compare with other methods
Unlike recursion with memoization, tabulation solves subproblems iteratively in order.
Final Answer:
Build a table from the smallest subproblems up to the main problem -> Option A
Quick Check:
Tabulation = Bottom Up DP [OK]
Hint: Think bottom-up: solve small parts first, then bigger [OK]
Common Mistakes:
Confusing tabulation with recursion
Thinking tabulation guesses answers
Mixing memoization with tabulation
2. Which of the following is the correct TypeScript syntax to initialize a DP array of size n+1 with zeros for tabulation?
easy
A. const dp = new Array(n+1).fill(0);
B. const dp = Array().map(() => 0);
C. const dp = new Array(n).fill(null);
D. const dp = Array.fill(n+1, 0);
Solution
Step 1: Check correct array initialization
Using new Array(n+1).fill(0) creates an array of length n+1 filled with zeros.
Step 2: Identify incorrect options
const dp = Array().map(() => 0); uses map on empty array which won't fill correctly; const dp = new Array(n).fill(null); fills with nulls; const dp = Array.fill(n+1, 0); is invalid syntax.
Final Answer:
const dp = new Array(n+1).fill(0); -> Option A
Quick Check:
Array fill with zeros = new Array(n+1).fill(0) [OK]
Hint: Use new Array(size).fill(value) to initialize arrays [OK]
Common Mistakes:
Using map on empty array without elements
Wrong array size (n instead of n+1)
Using invalid Array.fill syntax
3. What will be the output of the following TypeScript code using bottom-up DP to find the nth Fibonacci number?
function fib(n: number): number {
const dp = new Array(n + 1).fill(0);
dp[1] = 1;
for (let i = 2; i <= n; i++) {
dp[i] = dp[i - 1] + dp[i - 2];
}
return dp[n];
}
console.log(fib(5));
medium
A. 3
B. 5
C. 8
D. 13
Solution
Step 1: Trace dp array filling for n=5
dp[0]=0, dp[1]=1; then dp[2]=1, dp[3]=2, dp[4]=3, dp[5]=5.
4. Identify the bug in this bottom-up DP code for calculating factorial of n:
function factorial(n: number): number {
const dp = new Array(n + 1).fill(0);
for (let i = 1; i <= n; i++) {
dp[i] = dp[i - 1] * i;
}
return dp[n];
}
console.log(factorial(4));
medium
A. The loop should start from i = 0
B. dp array should be initialized with zeros, not ones
C. The multiplication should be dp[i] = dp[i] * i
D. dp[0] should be set to 1 before the loop
Solution
Step 1: Check dp initialization and base case
dp is filled with 0s, but dp[0] must be explicitly set to 1 as factorial(0)=1.
Step 2: Verify loop correctness
Loop from i=1 to n is correct; dp[i] = dp[i-1] * i is correct formula.
Final Answer:
dp[0] should be set to 1 before the loop -> Option D
Quick Check:
Base case dp[0]=1 needed [OK]
Hint: Always set base case explicitly in DP arrays [OK]
Common Mistakes:
Starting loop at 0 causing dp[-1] access
Wrong initialization of dp array
Incorrect multiplication formula
5. You want to find the minimum number of coins needed to make amount n using coins of denominations [1, 3, 4] with bottom-up DP. Which of these is the correct tabulation approach?
hard
A. Initialize dp array with zeros; for each coin, add 1 to dp[coin] only once
B. Use recursion to try all coin combinations without dp array
C. Initialize dp array with Infinity except dp[0]=0; for each amount i from 1 to n, update dp[i] = min(dp[i], dp[i - coin] + 1) for each coin if i >= coin
D. Initialize dp array with zeros; for each amount i, set dp[i] = dp[i-1] + 1 only
Solution
Step 1: Understand coin change tabulation
We start dp with Infinity except dp[0]=0 because 0 coins needed for amount 0.
Step 2: Update dp for each amount and coin
For each amount i, check all coins; if coin <= i, update dp[i] = min(dp[i], dp[i-coin] + 1).
Final Answer:
Initialize dp array with Infinity except dp[0]=0; for each amount i from 1 to n, update dp[i] = min(dp[i], dp[i - coin] + 1) for each coin if i >= coin -> Option C
Quick Check:
Coin change DP = min coins with dp and Infinity init [OK]
Hint: Use Infinity init and min update for coin change DP [OK]
Common Mistakes:
Not initializing dp with Infinity
Ignoring multiple coin options per amount
Using recursion instead of tabulation
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