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DSA Typescriptprogramming~10 mins

Rod Cutting Problem in DSA Typescript - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the maximum revenue array with zeros.

DSA Typescript
const maxRevenue: number[] = new Array(n + 1).fill([1]);
Drag options to blanks, or click blank then click option'
A1
Bnull
C0
D-1
Attempts:
3 left
💡 Hint
Common Mistakes
Initializing with 1 instead of 0 causes incorrect revenue calculations.
Using null or -1 can cause runtime errors when adding revenues.
2fill in blank
medium

Complete the code to loop through all possible first cut lengths.

DSA Typescript
for (let i = 1; i <= [1]; i++) {
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An
Blength
Cprice.length
DmaxRevenue.length
Attempts:
3 left
💡 Hint
Common Mistakes
Using price.length causes incorrect loop bounds.
Using maxRevenue.length is off by one due to array size.
3fill in blank
hard

Fix the error in updating the maximum revenue inside the nested loop.

DSA Typescript
maxRevenue[j] = Math.max(maxRevenue[j], price[i - 1] + [1]);
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AmaxRevenue[j - i]
BmaxRevenue[i]
Cprice[j - i]
Dprice[j]
Attempts:
3 left
💡 Hint
Common Mistakes
Adding price[j - i] instead of maxRevenue[j - i] causes wrong revenue calculation.
Using maxRevenue[i] ignores the remaining length.
4fill in blank
hard

Fill both blanks to complete the nested loop for calculating max revenue.

DSA Typescript
for (let j = [1]; j <= n; j++) {
  maxRevenue[j] = Math.max(maxRevenue[j], price[i - 1] + [2]);
}
Drag options to blanks, or click blank then click option'
Ai
Bj
Cj - i
Dn
Attempts:
3 left
💡 Hint
Common Mistakes
Starting j from 1 instead of i causes invalid cuts.
Adding maxRevenue[j] instead of maxRevenue[j - i] causes wrong results.
5fill in blank
hard

Fill all three blanks to complete the rod cutting function.

DSA Typescript
function rodCutting(price: number[], n: number): number {
  const maxRevenue: number[] = new Array(n + 1).fill([1]);
  for (let i = 1; i <= [2]; i++) {
    for (let j = i; j <= n; j++) {
      maxRevenue[j] = Math.max(maxRevenue[j], price[i - 1] + [3]);
    }
  }
  return maxRevenue[n];
}
Drag options to blanks, or click blank then click option'
A0
Bn
CmaxRevenue[j - i]
Dprice.length
Attempts:
3 left
💡 Hint
Common Mistakes
Incorrect initialization of maxRevenue.
Wrong loop bounds for i.
Adding price[j] instead of maxRevenue[j - i].