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DSA Typescriptprogramming~3 mins

Why N Queens Problem in DSA Typescript?

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The Big Idea

What if you could solve a tricky chess puzzle without guessing every move?

The Scenario

Imagine you have a chessboard and you want to place queens so that none can attack each other. Doing this by trying every possible way manually is like trying to find a needle in a huge haystack.

The Problem

Manually checking every arrangement is slow and confusing. You might miss some attacks or repeat the same checks many times, making it very tiring and error-prone.

The Solution

The N Queens Problem uses smart searching and backtracking to quickly find safe spots for queens. It avoids useless tries and finds solutions without missing any.

Before vs After
✗ Before
for (let i = 0; i < Math.pow(8, 8); i++) {
  // try placing queens randomly
  // check if safe
  // repeat
}
✓ After
function solveNQueens(row: number, n: number): boolean {
  if (row === n) return true;
  for (let col = 0; col < n; col++) {
    if (isSafe(row, col)) {
      placeQueen(row, col);
      if (solveNQueens(row + 1, n)) return true;
      removeQueen(row, col);
    }
  }
  return false;
}
What It Enables

This problem-solving method lets us handle complex puzzles and find safe arrangements efficiently.

Real Life Example

It's like planning seating at a wedding so no two people who dislike each other sit close, using smart steps instead of guessing.

Key Takeaways

Manual trial is slow and error-prone.

Backtracking finds safe queen placements efficiently.

Enables solving complex arrangement puzzles smartly.

Practice

(1/5)
1. What is the main goal of the N Queens Problem?
easy
A. Place N queens on an NxN chessboard so that no two queens attack each other
B. Count the total number of queens on the board
C. Place queens only on the main diagonal of the board
D. Find the shortest path for a queen to move across the board

Solution

  1. Step 1: Understand the problem statement

    The N Queens Problem asks to place N queens on an NxN chessboard so that no two queens threaten each other.
  2. Step 2: Identify the correct goal

    This means no two queens share the same row, column, or diagonal.
  3. Final Answer:

    Place N queens on an NxN chessboard so that no two queens attack each other -> Option A
  4. Quick Check:

    Goal = Place queens safely [OK]
Hint: Remember queens must not attack each other on rows, columns, diagonals [OK]
Common Mistakes:
  • Thinking queens can share rows or columns
  • Confusing the problem with counting queens
  • Ignoring diagonal attacks
2. Which of the following TypeScript function signatures correctly represents a recursive function to solve the N Queens Problem?
easy
A. function solveNQueens(): string
B. function solveNQueens(board: string): void
C. function solveNQueens(row: string, board: number[]): number
D. function solveNQueens(row: number, board: number[][]): boolean

Solution

  1. Step 1: Identify correct parameter types for recursion

    The recursive function usually takes the current row (number) and the board state (2D array) to place queens step-by-step.
  2. Step 2: Match function signature with recursion needs

    function solveNQueens(row: number, board: number[][]): boolean uses row: number and board: number[][], suitable for recursion and board tracking.
  3. Final Answer:

    function solveNQueens(row: number, board: number[][]): boolean -> Option D
  4. Quick Check:

    Recursive function needs row and board parameters [OK]
Hint: Recursive solve needs current row and board state parameters [OK]
Common Mistakes:
  • Using wrong parameter types like string for row
  • Missing board state parameter
  • Wrong return type for recursion
3. What will be the output of the following TypeScript code snippet for N=4?
function isSafe(board: number[][], row: number, col: number): boolean {
  for (let i = 0; i < col; i++) {
    if (board[row][i] === 1) return false;
  }
  for (let i = row, j = col; i >= 0 && j >= 0; i--, j--) {
    if (board[i][j] === 1) return false;
  }
  for (let i = row, j = col; i < 4 && j >= 0; i++, j--) {
    if (board[i][j] === 1) return false;
  }
  return true;
}

const board = [
  [0, 0, 0, 0],
  [1, 0, 0, 0],
  [0, 0, 0, 0],
  [0, 0, 0, 0]
];
console.log(isSafe(board, 1, 1));
medium
A. false
B. true
C. SyntaxError
D. undefined

Solution

  1. Step 1: Check row left side for queen

    For row=1, col=1, check columns 0 to 0 in row 1. board[1][0] = 1, so return false.
  2. Step 2: No need to check diagonals as left row check failed

    Since a queen is found on the left in the same row, position is unsafe.
  3. Final Answer:

    false -> Option A
  4. Quick Check:

    Left row check finds queen = false [OK]
Hint: Check left row first; queen found means unsafe [OK]
Common Mistakes:
  • Ignoring left row check
  • Confusing true/false return values
  • Assuming diagonals checked first
4. Identify the bug in this TypeScript snippet for placing queens:
function placeQueens(board: number[][], col: number): boolean {
  if (col >= board.length) return true;
  for (let i = 0; i < board.length; i++) {
    if (isSafe(board, i, col)) {
      board[i][col] = 1;
      if (placeQueens(board, col + 1)) return true;
      board[i][col] = 0;
    }
  }
  return false;
}

// isSafe function is correct

What is the bug?
medium
A. The base case should check if col > board.length
B. No bug; the code works correctly
C. The function does not backtrack correctly
D. The function does not check all rows in the current column

Solution

  1. Step 1: Analyze base case correctness

    The base case col >= board.length correctly stops recursion when all columns are processed.
  2. Step 2: Check backtracking and row iteration

    The loop tries all rows in the current column, places queen if safe, recurses, and backtracks if needed.
  3. Final Answer:

    No bug; the code works correctly -> Option B
  4. Quick Check:

    Backtracking and base case are correct [OK]
Hint: Check base case and backtracking carefully [OK]
Common Mistakes:
  • Changing base case incorrectly
  • Missing backtracking step
  • Assuming incomplete row checks
5. Given a 5x5 chessboard, how many distinct solutions exist for the N Queens Problem? (Assuming solutions that differ by rotation or reflection are counted separately)
hard
A. 8
B. 12
C. 10
D. 2

Solution

  1. Step 1: Recall known solution counts for N=5

    For a 5x5 board, the total number of distinct solutions is known to be 10 when counting all unique placements.
  2. Step 2: Confirm counting method

    Since rotations and reflections are counted separately, the count remains 10.
  3. Final Answer:

    10 -> Option C
  4. Quick Check:

    N=5 solutions = 10 [OK]
Hint: Memorize small N solution counts: N=4(2), N=5(10) [OK]
Common Mistakes:
  • Confusing unique solutions with symmetrical counts
  • Mixing counts for N=4 and N=5
  • Assuming fewer solutions than actual
Recommended

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10 questions~5 mineasy hard