Minimum Spanning Tree Prim's Algorithm in DSA Typescript - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the key array with infinite values.

DSA Typescript

const key: number[] = new Array(V).fill([1]);

Drag options to blanks, or click blank then click option'

A0

B-1

CInfinity

Dnull

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 instead of Infinity causes incorrect minimum edge selection.

Using null or -1 can cause runtime errors when comparing weights.

We use Infinity to represent that initially all vertices have an infinite key value before being updated.

2fill in blank

medium

Complete the code to mark the starting vertex as included in MST.

DSA Typescript

mstSet[[1]] = true;

Drag options to blanks, or click blank then click option'

AV - 1

B1

C-1

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Starting from vertex 1 or -1 causes index errors or skips the first vertex.

Using V - 1 starts from the last vertex, which is not standard.

The algorithm starts from vertex 0, so we mark mstSet[0] as true to include it first.

3fill in blank

hard

Fix the error in the loop condition to find the vertex with minimum key value not yet included in MST.

DSA Typescript

for (let v = 0; v < [1]; v++) {

Drag options to blanks, or click blank then click option'

Akey.length

BV

CmstSet.length

Dgraph.length

Attempts:

3 left

💡 Hint

Common Mistakes

Using mstSet.length or key.length may work but is less clear.

Using graph.length may cause errors if graph is adjacency matrix with different dimensions.

The loop must run from 0 to V (number of vertices) to check all vertices.

4fill in blank

hard

Fill both blanks to update key and parent arrays when a better edge is found.

DSA Typescript

if (graph[u][v] && mstSet[v] === false && graph[u][v] < [1][v]) {
  [2][v] = u;
}

Drag options to blanks, or click blank then click option'

Akey

Bparent

CmstSet

Dgraph

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing key and parent arrays causes wrong MST construction.

Updating mstSet or graph instead causes logic errors.

We update key[v] with the new smaller weight and set parent[v] to u to record the MST edge.

5fill in blank

hard

Fill all three blanks to complete the key update inside the loop.

DSA Typescript

key[v] = graph[[1]][[2]];
mstSet[[3]] = true;

Drag options to blanks, or click blank then click option'

Au

Bv

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping u and v causes wrong edge weight assignment.

Marking mstSet[v] instead of mstSet[u] causes incorrect MST inclusion.

We update key[v] with the weight from u to v, and mark mstSet[u] as true to include vertex u in MST.

Practice

1. What is the main goal of Prim's algorithm in graph theory?

easy

A. To find the minimum spanning tree connecting all vertices with the least total edge weight

B. To find the shortest path between two vertices

C. To detect cycles in a graph

D. To sort vertices based on their degree

Solution

1. Step 1: Understand Prim's algorithm purpose

   Prim's algorithm builds a tree connecting all vertices with minimum total edge weight.

2. Step 2: Compare with other graph algorithms

   Shortest path and cycle detection are different problems; Prim's focuses on spanning tree.

3. Final Answer:

   To find the minimum spanning tree connecting all vertices with the least total edge weight -> Option A

4. Quick Check:

   Prim's algorithm = Minimum Spanning Tree [OK]

Hint: Prim's always finds minimum spanning tree, not shortest path [OK]

Common Mistakes:

• Confusing Prim's with Dijkstra's algorithm
• Thinking it finds shortest path
• Assuming it detects cycles

2. Which of the following is the correct way to initialize the key array in Prim's algorithm in TypeScript?

easy

A. const key: number[] = Array(n).fill(0);

B. const key: number[] = new Array(n).fill(Infinity);

C. const key: number[] = new Array(n).fill(null);

D. const key: number[] = Array(n).fill(-1);

Solution

1. Step 1: Understand key array role

   Key array stores minimum edge weights; initialize with Infinity to find minimum.

2. Step 2: Check initialization options

   Filling with Infinity ensures any edge weight will be smaller initially.

3. Final Answer:

   const key: number[] = new Array(n).fill(Infinity); -> Option B

4. Quick Check:

   Initialize keys with Infinity for minimum comparison [OK]

Hint: Use Infinity to initialize keys for minimum edge weight tracking [OK]

Common Mistakes:

• Initializing keys with 0 causes wrong minimum comparisons
• Using null instead of a number
• Filling with -1 which is invalid for weights

3. Consider the following TypeScript code snippet implementing Prim's algorithm on a graph with 4 vertices. What is the printed MST total weight?

const graph = [
  [0, 2, 0, 6],
  [2, 0, 3, 8],
  [0, 3, 0, 0],
  [6, 8, 0, 0]
];

function primMST(graph: number[][]): number {
  const n = graph.length;
  const key = new Array(n).fill(Infinity);
  const mstSet = new Array(n).fill(false);
  key[0] = 0;
  let totalWeight = 0;

  for (let count = 0; count < n - 1; count++) {
    let min = Infinity;
    let u = -1;
    for (let v = 0; v < n; v++) {
      if (!mstSet[v] && key[v] < min) {
        min = key[v];
        u = v;
      }
    }
    mstSet[u] = true;
    totalWeight += min;

    for (let v = 0; v < n; v++) {
      if (graph[u][v] && !mstSet[v] && graph[u][v] < key[v]) {
        key[v] = graph[u][v];
      }
    }
  }
  return totalWeight;
}

console.log(primMST(graph));

medium

A. 11

B. 9

C. 14

D. 10

Solution

1. Step 1: Trace MST selection steps

   Start with vertex 0: key[0]=0, others Infinity. Select vertex 0 (weight 0), add edges: 2 (to 1), 6 (to 3).

2. Step 2: Select next minimum edge

   Choose vertex 1 (key=2), add edge weight 2. Update keys: vertex 2 gets 3 (edge 1-2), vertex 3 remains 6.

3. Step 3: Select next minimum edge

   Choose vertex 2 (key=3), add edge weight 3. Vertex 3 key remains 6.

4. Step 4: Select last vertex

   Choose vertex 3 (key=6), add edge weight 6.

5. Step 5: Calculate total weight

   Total = 2 + 3 + 6 = 11

6. Final Answer:

   11 -> Option A

7. Quick Check:

   MST total weight = 11 [OK]

Hint: Add chosen edge weights stepwise to get MST total [OK]

Common Mistakes:

• Forgetting to add the first vertex key (0) to total
• Adding all edges instead of MST edges
• Mixing up vertex indices

4. The following TypeScript code for Prim's algorithm has a bug. What is the error?

function primMST(graph: number[][]): number {
  const n = graph.length;
  const key = new Array(n).fill(Infinity);
  const mstSet = new Array(n).fill(false);
  key[0] = 0;
  let totalWeight = 0;

  for (let count = 0; count <= n - 1; count++) {
    let min = Infinity;
    let u = -1;
    for (let v = 0; v < n; v++) {
      if (!mstSet[v] && key[v] < min) {
        min = key[v];
        u = v;
      }
    }
    mstSet[u] = true;
    totalWeight += min;

    for (let v = 0; v < n; v++) {
      if (graph[u][v] && !mstSet[v] && graph[u][v] < key[v]) {
        key[v] = graph[u][v];
      }
    }
  }
  return totalWeight;
}

medium

A. The inner loop condition should be v <= n

B. The key array is not initialized correctly

C. The mstSet array should be initialized with true values

D. The outer loop runs one extra time causing an invalid vertex selection

Solution

1. Step 1: Analyze outer loop range

   The loop runs from 0 to n inclusive (<= n - 1), which means n iterations instead of n-1.

2. Step 2: Understand impact of extra iteration

   Extra iteration causes selection of u = -1 (no valid vertex), leading to errors or invalid updates.

3. Final Answer:

   The outer loop runs one extra time causing an invalid vertex selection -> Option D

4. Quick Check:

   Loop count must be n-1, not n [OK]

Hint: Outer loop should run n-1 times, not n [OK]

Common Mistakes:

• Using <= instead of < in loop condition
• Initializing mstSet incorrectly
• Changing inner loop bounds wrongly

5. Given a weighted undirected graph represented by the adjacency matrix below, apply Prim's algorithm starting from vertex 0. Which edges are included in the MST?

const graph = [
  [0, 1, 4, 0, 0, 0],
  [1, 0, 4, 2, 7, 0],
  [4, 4, 0, 3, 5, 0],
  [0, 2, 3, 0, 4, 6],
  [0, 7, 5, 4, 0, 7],
  [0, 0, 0, 6, 7, 0]
];

Options list edges as pairs (u-v):

hard

A. (0-2), (2-3), (3-1), (3-4), (4-5)

B. (0-1), (1-3), (3-5), (5-4), (4-2)

C. (0-1), (1-3), (3-2), (3-4), (3-5)

D. (0-1), (1-2), (2-3), (3-4), (4-5)

Solution

1. Step 1: Start from vertex 0 and pick minimum edges

   From 0, edges: (0-1)=1, (0-2)=4. Choose (0-1) with weight 1.

2. Step 2: Update keys and select next minimum edge

   From vertices {0,1}, edges: (1-3)=2, (1-2)=4, (0-2)=4. Choose (1-3) with weight 2.

3. Step 3: Continue selecting minimum edges connecting MST

   From {0,1,3}, edges: (3-2)=3, (3-4)=4, (3-5)=6. Choose (3-2) with weight 3.

4. Step 4: Next minimum edge from MST

   From {0,1,2,3}, edges: (3-4)=4, (3-5)=6. Choose (3-4) with weight 4.

5. Step 5: Final edge to include

   From {0,1,2,3,4}, edges: (3-5)=6, (4-5)=7. Choose (3-5) with weight 6.

6. Final Answer:

   (0-1), (1-3), (3-2), (3-4), (3-5) -> Option C

7. Quick Check:

   Edges chosen minimize total weight connecting all vertices [OK]

Hint: Pick smallest connecting edge each step starting from vertex 0 [OK]

Common Mistakes:

• Choosing edges with larger weights early
• Not updating keys after adding vertices
• Assuming linear chain instead of MST shape