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DSA Typescriptprogramming~5 mins

Generate All Combinations Sum K in DSA Typescript - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does the problem 'Generate All Combinations Sum K' ask you to find?
It asks to find all unique combinations of numbers from a given list that add up exactly to a target sum K.
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beginner
Which algorithmic technique is commonly used to solve 'Generate All Combinations Sum K'?
Backtracking is commonly used because it explores all possible combinations and abandons paths that exceed the target sum.
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intermediate
In backtracking for combinations sum K, why do we sort the input array first?
Sorting helps to stop early when the current number exceeds the remaining sum and to avoid duplicate combinations.
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intermediate
What is the role of the 'start index' in the recursive backtracking function for combinations sum K?
It ensures combinations are built without reusing previous elements and helps avoid duplicates by moving forward in the list.
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advanced
How do you handle duplicates in the input list when generating all combinations that sum to K?
By skipping over numbers that are the same as the previous one at the same recursive level to avoid duplicate combinations.
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What is the first step before starting backtracking in 'Generate All Combinations Sum K'?
ASort the input array
BReverse the input array
CShuffle the input array
DRemove duplicates from the input array
In backtracking, what do you do when the current sum exceeds the target K?
AContinue exploring deeper
BRestart from the beginning
CStop exploring this path and backtrack
DAdd more numbers to reach K
How do you avoid duplicate combinations in the result?
AUse a set to store results
BSkip duplicate numbers during recursion
CSort the results after generation
DAllow duplicates and filter later
What does the 'start index' parameter control in the recursive function?
AWhere to start adding numbers in the input array
BThe current sum value
CThe target sum K
DThe length of the combination
Which data structure is best to store the current combination during backtracking?
AQueue
BHash map
CSet
DStack or list
Explain how backtracking works to generate all combinations that sum to K.
Think of exploring a tree of choices, going deeper and backtracking when needed.
You got /5 concepts.
    Describe how to handle duplicates in the input array when generating combinations that sum to K.
    Sorting helps to detect duplicates easily.
    You got /3 concepts.

      Practice

      (1/5)
      1. What does the problem "Generate All Combinations Sum K" ask you to find?
      easy
      A. The count of numbers equal to K
      B. The largest number less than K
      C. All unique combinations of numbers that add up to K
      D. The smallest number greater than K

      Solution

      1. Step 1: Understand the problem goal

        The problem asks to find all unique sets of numbers whose sum equals K.
      2. Step 2: Clarify uniqueness and sum condition

        Each combination must sum exactly to K without duplicates in the result.
      3. Final Answer:

        All unique combinations of numbers that add up to K -> Option C
      4. Quick Check:

        Combinations sum to K = All unique combinations of numbers that add up to K [OK]
      Hint: Focus on combinations that sum exactly to K [OK]
      Common Mistakes:
      • Confusing sum with count
      • Including duplicate combinations
      • Looking for single numbers only
      2. Which of the following TypeScript function signatures correctly represents a function to generate all combinations summing to K from an array of numbers?
      easy
      A. function generateCombinations(nums: number, target: number[]): number[]
      B. function generateCombinations(nums: number[], target: number): number[][]
      C. function generateCombinations(nums: string[], target: string): string[]
      D. function generateCombinations(nums: number[], target: number): number[]

      Solution

      1. Step 1: Analyze parameter types

        The function should take an array of numbers and a target number.
      2. Step 2: Analyze return type

        It should return an array of arrays of numbers representing combinations.
      3. Final Answer:

        function generateCombinations(nums: number[], target: number): number[][] -> Option B
      4. Quick Check:

        Input array and target number, output array of number arrays [OK]
      Hint: Input array and target number, output array of arrays [OK]
      Common Mistakes:
      • Using wrong parameter types
      • Returning flat array instead of array of arrays
      • Mixing string and number types
      3. What is the output of the following TypeScript code?
      function combineSum(nums: number[], target: number): number[][] {
        const result: number[][] = [];
        function backtrack(start: number, path: number[], sum: number) {
          if (sum === target) {
            result.push([...path]);
            return;
          }
          if (sum > target) return;
          for (let i = start; i < nums.length; i++) {
            path.push(nums[i]);
            backtrack(i + 1, path, sum + nums[i]);
            path.pop();
          }
        }
        backtrack(0, [], 0);
        return result;
      }
      
      console.log(combineSum([1, 2, 3], 3));
      medium
      A. [[1, 2], [3]]
      B. [[1, 3], [2]]
      C. [[3], [2, 1]]
      D. [[1, 2, 3]]

      Solution

      1. Step 1: Trace backtracking calls

        Starting from 0, combinations are built adding numbers without reuse: [1,2] sums to 3, [3] sums to 3.
      2. Step 2: Confirm valid combinations

        Other combinations like [2] or [1,3] do not sum to 3 or are invalid due to index increment.
      3. Final Answer:

        [[1, 2], [3]] -> Option A
      4. Quick Check:

        Combinations summing to 3 = [[1, 2], [3]] [OK]
      Hint: Check sums and index increments carefully [OK]
      Common Mistakes:
      • Including combinations with reused elements
      • Ignoring sum > target condition
      • Confusing order of elements
      4. Identify the bug in this TypeScript function that aims to generate all combinations summing to K:
      function findCombos(nums: number[], target: number): number[][] {
        const res: number[][] = [];
        function dfs(i: number, path: number[], total: number) {
          if (total === target) {
            res.push(path);
            return;
          }
          if (total > target || i === nums.length) return;
          dfs(i + 1, path, total);
          path.push(nums[i]);
          dfs(i + 1, path, total + nums[i]);
          path.pop();
        }
        dfs(0, [], 0);
        return res;
      }
      medium
      A. The function does not return any result
      B. The base case does not check for total > target
      C. The recursion does not increment index i
      D. The path array is pushed by reference causing incorrect results

      Solution

      1. Step 1: Check how path is stored

        The path array is pushed directly without copying, so later changes affect stored results.
      2. Step 2: Understand impact on results

        Because path is referenced, all stored combinations end up empty or incorrect after backtracking.
      3. Final Answer:

        The path array is pushed by reference causing incorrect results -> Option D
      4. Quick Check:

        Push copy of path, not reference [OK]
      Hint: Always push a copy of path, not the original [OK]
      Common Mistakes:
      • Pushing path without copying
      • Not handling base cases properly
      • Incorrect index increment
      5. Given an array with duplicates, how can you modify the combination sum algorithm to generate all unique combinations summing to K without duplicates in the result?
      nums = [1, 2, 2, 3], target = 4
      hard
      A. Sort the array and skip duplicates during recursion
      B. Use a Set to store all combinations as strings
      C. Allow duplicates and filter results after generation
      D. Ignore duplicates and generate all combinations

      Solution

      1. Step 1: Sort the input array

        Sorting groups duplicates together, making it easier to skip them during recursion.
      2. Step 2: Skip duplicates in recursion

        When iterating, skip elements equal to the previous to avoid duplicate combinations.
      3. Final Answer:

        Sort the array and skip duplicates during recursion -> Option A
      4. Quick Check:

        Sorting + skipping duplicates = unique combinations [OK]
      Hint: Sort and skip duplicates while recursing [OK]
      Common Mistakes:
      • Not sorting before recursion
      • Filtering duplicates after generation (inefficient)
      • Ignoring duplicates causing repeated results
      Recommended

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