Fibonacci Using DP in DSA Typescript - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the main idea behind using Dynamic Programming (DP) to calculate Fibonacci numbers?

DP stores the results of smaller subproblems (previous Fibonacci numbers) to avoid repeated calculations, making the process faster and efficient.

beginner

In Fibonacci DP, what does the 'memoization' technique mean?

Memoization means saving the result of each Fibonacci number once calculated, so if we need it again, we just reuse it instead of recalculating.

intermediate

What is the time complexity of Fibonacci calculation using DP?

The time complexity is O(n) because each Fibonacci number from 0 to n is calculated once and stored for reuse.

beginner

Why is the simple recursive Fibonacci approach inefficient compared to DP?

Simple recursion recalculates the same Fibonacci numbers many times, causing exponential time complexity, while DP avoids this by storing results.

beginner

Show the base cases used in Fibonacci DP and explain why they are important.

Base cases are Fib(0) = 0 and Fib(1) = 1. They stop the recursion and provide starting points to build all other Fibonacci numbers.

What does DP store to optimize Fibonacci calculation?

A Previously calculated Fibonacci numbers

B Random numbers

C Only the last Fibonacci number

D No values, it recalculates every time

DP stores all previously calculated Fibonacci numbers to avoid repeated work.

What is the time complexity of Fibonacci using DP?

A O(n)

B O(2^n)

C O(log n)

D O(n^2)

DP calculates each Fibonacci number once, so time complexity is linear O(n).

Which technique is used in DP to save results of subproblems?

A Greedy

B Backtracking

C Memoization

D Brute force

Memoization saves results to avoid repeated calculations.

What are the base cases for Fibonacci DP?

A Fib(1) = 1 and Fib(2) = 2

B Fib(0) = 0 and Fib(1) = 1

C Fib(0) = 1 and Fib(1) = 1

D Fib(2) = 1 and Fib(3) = 2

Base cases start the sequence correctly with Fib(0) = 0 and Fib(1) = 1.

Why is simple recursion inefficient for Fibonacci?

A It only works for small numbers

B It uses too much memory

C It does not return correct results

D It recalculates the same values many times

Simple recursion repeats calculations, causing exponential time.

Explain how Dynamic Programming improves Fibonacci number calculation compared to simple recursion.

Think about how saving answers helps avoid doing the same work twice.

Describe the role of base cases in the Fibonacci DP approach and why they are necessary.

Base cases are like the first steps in a staircase you need to climb.

Practice

1. What is the main advantage of using Dynamic Programming (DP) to calculate Fibonacci numbers compared to a simple recursive approach?

easy

A. It uses less memory by not storing any results.

B. It avoids repeated calculations by storing intermediate results.

C. It calculates Fibonacci numbers randomly.

D. It only works for small Fibonacci numbers.

Solution

1. Step 1: Understand recursive Fibonacci calculation

   Simple recursion recalculates the same Fibonacci numbers many times, causing inefficiency.

2. Step 2: Understand DP optimization

   DP stores previously calculated Fibonacci numbers in a table (memoization or tabulation) to avoid repeated work.

3. Final Answer:

   It avoids repeated calculations by storing intermediate results. -> Option B

4. Quick Check:

   DP = stores results to save time [OK]

Hint: DP saves time by remembering past answers [OK]

Common Mistakes:

• Thinking DP uses less memory than recursion
• Believing DP calculates randomly
• Assuming DP only works for small inputs

2. Which of the following TypeScript code snippets correctly initializes the DP array for Fibonacci calculation up to n?

easy

A. const dp: number[] = new Array(n + 1).fill(0); dp[1] = 1;

B. const dp: number[] = new Array(n).fill(1);

C. const dp: number[] = []; dp[0] = 1; dp[1] = 1;

D. const dp: number[] = new Array(n + 1); dp[1] = 1;

Solution

1. Step 1: Check array size and initialization

   We need an array of size n+1 to store Fibonacci numbers from 0 to n. Filling with 0 and setting dp[1] = 1 is correct.

2. Step 2: Validate each option

   const dp: number[] = new Array(n + 1).fill(0); dp[1] = 1; correctly creates dp with size n+1, fills with 0, and sets dp[1] = 1. Others have wrong sizes or initial values.

3. Final Answer:

   const dp: number[] = new Array(n + 1).fill(0); dp[1] = 1; -> Option A

4. Quick Check:

   Array size = n+1, dp[1] = 1 [OK]

Hint: DP array size must be n+1 with dp[1] = 1 [OK]

Common Mistakes:

• Using array size n instead of n+1
• Initializing dp[0] or dp[1] incorrectly
• Leaving dp array uninitialized

3. What will be the output of the following TypeScript code?

function fib(n: number): number {
  const dp: number[] = new Array(n + 1).fill(0);
  dp[1] = 1;
  for (let i = 2; i <= n; i++) {
    dp[i] = dp[i - 1] + dp[i - 2];
  }
  return dp[n];
}
console.log(fib(5));

medium

A. 13

B. 8

C. 3

D. 5

Solution

1. Step 1: Trace DP array values for n=5

   dp[0]=0, dp[1]=1; then dp[2]=1, dp[3]=2, dp[4]=3, dp[5]=5.

2. Step 2: Return dp[5]

   The function returns dp[5] which is 5.

3. Final Answer:

   5 -> Option D

4. Quick Check:

   Fibonacci(5) = 5 [OK]

Hint: Remember Fibonacci sequence: 0,1,1,2,3,5... [OK]

Common Mistakes:

• Confusing index starting point
• Returning dp[n-1] instead of dp[n]
• Miscomputing dp values in loop

4. Identify the error in this TypeScript DP Fibonacci code and select the fix:

function fib(n: number): number {
  const dp: number[] = new Array(n).fill(0);
  dp[0] = 0;
  dp[1] = 1;
  for (let i = 2; i <= n; i++) {
    dp[i] = dp[i - 1] + dp[i - 2];
  }
  return dp[n];
}

medium

A. Change array size to n+1.

B. Initialize dp[2] to 1 before the loop.

C. Start loop from i = 1 instead of 2.

D. Remove dp[0] initialization.

Solution

1. Step 1: Analyze array size and access

   Array dp has size n, but loop accesses dp[n] beyond the initial length.

2. Step 2: Fix array size

   Increase dp size to n+1 to safely access dp[n].

3. Final Answer:

   Change array size to n+1 to avoid out-of-bounds error. -> Option A

4. Quick Check:

   Array size must cover dp[n] [OK]

Hint: Array size must be n+1 for dp[n] access [OK]

Common Mistakes:

• Ignoring array size mismatch
• Starting loop incorrectly
• Unnecessary dp initialization changes

5. You want to optimize the space used by the DP Fibonacci function. Which modification correctly reduces space complexity from O(n) to O(1)?

hard

A. Use a recursive function without memoization.

B. Store all Fibonacci numbers in a global array.

C. Use two variables to store only the last two Fibonacci numbers instead of an array.

D. Initialize the dp array with zeros and fill it completely every call.

Solution

1. Step 1: Understand space usage in DP Fibonacci

   DP uses an array of size n+1, so space is O(n).

2. Step 2: Optimize space by storing only needed values

   Since each Fibonacci number depends only on the previous two, storing just two variables suffices.

3. Step 3: Compare options

   Use two variables to store only the last two Fibonacci numbers instead of an array. uses two variables, reducing space to O(1). Others do not reduce space or are inefficient.

4. Final Answer:

   Use two variables to store only the last two Fibonacci numbers instead of an array. -> Option C

5. Quick Check:

   Two vars = O(1) space [OK]

Hint: Keep only last two Fibonacci numbers to save space [OK]

Common Mistakes:

• Using recursion without memoization increases time
• Storing all numbers globally wastes space
• Filling full dp array every call wastes memory