Dequeue Operation in DSA Typescript - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to remove the first element from the dequeue.

DSA Typescript

const removedElement = dequeue.[1]();

Drag options to blanks, or click blank then click option'

Apop

Bunshift

Cpush

Dshift

Attempts:

3 left

💡 Hint

Common Mistakes

Using pop() removes the last element, not the first.

The shift() method removes the first element from an array or dequeue.

2fill in blank

medium

Complete the code to add an element to the end of the dequeue.

DSA Typescript

dequeue.[1](element);

Drag options to blanks, or click blank then click option'

Ashift

Bpop

Cpush

Dunshift

Attempts:

3 left

💡 Hint

Common Mistakes

Using unshift() adds to the front, not the end.

The push() method adds an element to the end of the dequeue.

3fill in blank

hard

Fix the error in the code to correctly remove the last element from the dequeue.

DSA Typescript

const last = dequeue.[1]();

Drag options to blanks, or click blank then click option'

Apop

Bunshift

Cpush

Dshift

Attempts:

3 left

💡 Hint

Common Mistakes

Using shift() removes the first element, not the last.

The pop() method removes the last element from the dequeue.

4fill in blank

hard

Fill both blanks to add an element to the front and remove an element from the end of the dequeue.

DSA Typescript

dequeue.[1](newElement);
const removed = dequeue.[2]();

Drag options to blanks, or click blank then click option'

Aunshift

Bpush

Cpop

Dshift

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up push and unshift for adding elements.

unshift() adds an element to the front, and pop() removes the last element.

5fill in blank

hard

Fill all three blanks to remove the first element, add a new element to the end, and then remove the last element from the dequeue.

DSA Typescript

const first = dequeue.[1]();
dequeue.[2](newElement);
const last = dequeue.[3]();

Drag options to blanks, or click blank then click option'

Ashift

Bpush

Cpop

Dunshift

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing push and unshift for adding elements.

shift() removes the first element, push() adds to the end, and pop() removes the last element.

Practice

1. What is the main difference between a dequeue and a queue?

easy

A. A dequeue allows insertion and deletion from both ends.

B. A dequeue only allows insertion at the rear.

C. A dequeue only allows deletion from the front.

D. A dequeue is a fixed size data structure.

Solution

1. Step 1: Understand queue operations

   A queue allows insertion at the rear and deletion from the front only.

2. Step 2: Understand dequeue operations

   A dequeue allows insertion and deletion at both front and rear ends.

3. Final Answer:

   A dequeue allows insertion and deletion from both ends. -> Option A

4. Quick Check:

   Dequeue = Both ends operations [OK]

Hint: Dequeue = Double-ended queue, both ends allowed [OK]

Common Mistakes:

• Thinking dequeue is same as queue
• Assuming insertion only at rear
• Confusing dequeue with stack

2. Which of the following is the correct TypeScript method to add an element at the front of a dequeue implemented as an array?

easy

A. dequeue.pushFront(element);

B. dequeue.unshift(element);

C. dequeue.addFirst(element);

D. dequeue.insertFront(element);

Solution

1. Step 1: Recall array methods for front insertion

   In TypeScript/JavaScript, unshift() adds element at the front of an array.

2. Step 2: Check other options

   Methods like pushFront, addFirst, insertFront do not exist in standard arrays.

3. Final Answer:

   dequeue.unshift(element); -> Option B

4. Quick Check:

   Array front insert = unshift() [OK]

Hint: Use unshift() to add at front in arrays [OK]

Common Mistakes:

• Using push() instead of unshift()
• Assuming pushFront() exists
• Confusing with linked list methods

3. Consider this TypeScript code using an array as a dequeue:

let dequeue = [10, 20, 30];
dequeue.pop();
dequeue.unshift(5);
console.log(dequeue);

What is the output?

medium

A. [5, 10, 20]

B. [5, 10, 20, 30]

C. [10, 20, 30, 5]

D. [10, 20]

Solution

1. Step 1: Execute pop()

   pop() removes last element 30, so array becomes [10, 20].

2. Step 2: Execute unshift(5)

   unshift(5) adds 5 at front, array becomes [5, 10, 20].

3. Final Answer:

   [5, 10, 20] -> Option A

4. Quick Check:

   pop removes last, unshift adds front [OK]

Hint: pop removes last, unshift adds front [OK]

Common Mistakes:

• Assuming pop removes front
• Thinking unshift adds at end
• Confusing array order after operations

4. The following TypeScript code tries to remove an element from the front of a dequeue implemented as an array:

let dequeue = [1, 2, 3];
dequeue.removeFront();
console.log(dequeue);

What is the issue and how to fix it?

medium

A. removeFront() works only on linked lists; convert array to linked list.

B. removeFront() removes last element; use pop() instead.

C. removeFront() is not a valid method; use shift() instead.

D. No issue; code runs correctly.

Solution

1. Step 1: Identify invalid method

   Arrays in TypeScript do not have removeFront() method; this causes a runtime error.

2. Step 2: Use correct method for front removal

   shift() removes the first element from an array correctly.

3. Final Answer:

   removeFront() is not a valid method; use shift() instead. -> Option C

4. Quick Check:

   Front removal in arrays = shift() [OK]

Hint: Use shift() to remove front element in arrays [OK]

Common Mistakes:

• Using non-existent removeFront() method
• Confusing pop() with front removal
• Thinking arrays have linked list methods

5. You have a dequeue implemented as an array: let dq = [1, 2, 3, 4];. You perform these operations:

dq.pop();
dq.unshift(0);
dq.push(5);
dq.shift();
console.log(dq);

What is the final state of the dequeue?

hard

A. [0, 1, 2, 3, 5]

B. [2, 3, 4, 5]

C. [1, 2, 3, 4, 5]

D. [1, 2, 3, 5]

Solution

1. Step 1: Execute pop()

   pop() removes last element 4, dq becomes [1, 2, 3].

2. Step 2: Execute unshift(0)

   unshift(0) adds 0 at front, dq becomes [0, 1, 2, 3].

3. Step 3: Execute push(5)

   push(5) adds 5 at end, dq becomes [0, 1, 2, 3, 5].

4. Step 4: Execute shift()

   shift() removes first element 0, dq becomes [1, 2, 3, 5].

5. Final Answer:

   [1, 2, 3, 5] -> Option D

6. Quick Check:

   pop removes end, unshift adds front, push adds end, shift removes front [OK]

Hint: Track each operation stepwise on array [OK]

Common Mistakes:

• Forgetting shift removes front element
• Mixing order of operations
• Assuming unshift adds at end