Dequeue Operation in DSA Typescript - Time & Space Complexity
We want to understand how long it takes to remove an item from a dequeue (double-ended queue).
Specifically, how the time changes as the number of items grows.
Analyze the time complexity of the dequeue operation removing from the front.
class Dequeue {
items: number[] = [];
dequeueFront(): number | undefined {
if (this.items.length === 0) return undefined;
return this.items.shift();
}
}
This code removes the first item from the dequeue array.
Look for loops or repeated steps inside the dequeueFront method.
- Primary operation: Removing the first item using
shift(). - How many times: Each call removes one item, but internally
shift()moves all other items one step forward.
When the dequeue has more items, shift() moves more elements.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 9 moves |
| 100 | About 99 moves |
| 1000 | About 999 moves |
Pattern observation: The number of moves grows roughly the same as the number of items.
Time Complexity: O(n)
This means removing from the front takes longer as the dequeue grows because items must shift.
[X] Wrong: "Removing from the front is always fast and constant time like popping from the end."
[OK] Correct: In arrays, removing the first item shifts all others, so it takes time proportional to the number of items.
Understanding this helps you choose the right data structure for fast front removals, a key skill in coding interviews.
"What if we used a linked list instead of an array for the dequeue? How would the time complexity of removing from the front change?"
Practice
Solution
Step 1: Understand queue operations
A queue allows insertion at the rear and deletion from the front only.Step 2: Understand dequeue operations
A dequeue allows insertion and deletion at both front and rear ends.Final Answer:
A dequeue allows insertion and deletion from both ends. -> Option AQuick Check:
Dequeue = Both ends operations [OK]
- Thinking dequeue is same as queue
- Assuming insertion only at rear
- Confusing dequeue with stack
Solution
Step 1: Recall array methods for front insertion
In TypeScript/JavaScript,unshift()adds element at the front of an array.Step 2: Check other options
Methods likepushFront,addFirst,insertFrontdo not exist in standard arrays.Final Answer:
dequeue.unshift(element); -> Option BQuick Check:
Array front insert = unshift() [OK]
- Using push() instead of unshift()
- Assuming pushFront() exists
- Confusing with linked list methods
let dequeue = [10, 20, 30]; dequeue.pop(); dequeue.unshift(5); console.log(dequeue);What is the output?
Solution
Step 1: Execute pop()
pop() removes last element 30, so array becomes [10, 20].Step 2: Execute unshift(5)
unshift(5) adds 5 at front, array becomes [5, 10, 20].Final Answer:
[5, 10, 20] -> Option AQuick Check:
pop removes last, unshift adds front [OK]
- Assuming pop removes front
- Thinking unshift adds at end
- Confusing array order after operations
let dequeue = [1, 2, 3]; dequeue.removeFront(); console.log(dequeue);What is the issue and how to fix it?
Solution
Step 1: Identify invalid method
Arrays in TypeScript do not have removeFront() method; this causes a runtime error.Step 2: Use correct method for front removal
shift() removes the first element from an array correctly.Final Answer:
removeFront() is not a valid method; use shift() instead. -> Option CQuick Check:
Front removal in arrays = shift() [OK]
- Using non-existent removeFront() method
- Confusing pop() with front removal
- Thinking arrays have linked list methods
let dq = [1, 2, 3, 4];. You perform these operations:
dq.pop(); dq.unshift(0); dq.push(5); dq.shift(); console.log(dq);What is the final state of the dequeue?
Solution
Step 1: Execute pop()
pop() removes last element 4, dq becomes [1, 2, 3].Step 2: Execute unshift(0)
unshift(0) adds 0 at front, dq becomes [0, 1, 2, 3].Step 3: Execute push(5)
push(5) adds 5 at end, dq becomes [0, 1, 2, 3, 5].Step 4: Execute shift()
shift() removes first element 0, dq becomes [1, 2, 3, 5].Final Answer:
[1, 2, 3, 5] -> Option DQuick Check:
pop removes end, unshift adds front, push adds end, shift removes front [OK]
- Forgetting shift removes front element
- Mixing order of operations
- Assuming unshift adds at end
Ready to prove it?
Pass the test and this pattern moves unknown
