Why Hash Map Exists and What Problem It Solves in DSA Javascript - Quick Recap

Recall & Review

beginner

What problem does a Hash Map solve in data storage?

A Hash Map solves the problem of quickly finding, adding, or removing data by using a key to directly access the value, avoiding slow searches through all data.

beginner

How does a Hash Map find data faster than a list or array?

It uses a hash function to convert a key into an index, so it can jump directly to the data instead of checking each item one by one.

beginner

What is a key in a Hash Map?

A key is a unique identifier used to store and find a value quickly in a Hash Map, like a name tag for a piece of data.

beginner

Why not just use an array instead of a Hash Map?

Arrays require checking each item to find a value, which is slow for large data. Hash Maps let you find data instantly using keys.

intermediate

What happens if two keys produce the same hash in a Hash Map?

This is called a collision. Hash Maps handle collisions by storing multiple values in the same spot or finding another spot, so data is not lost.

What is the main benefit of using a Hash Map?

A Fast data lookup using keys

B Storing data in order

C Saving memory space

D Automatically sorting data

Hash Maps allow fast data lookup by using keys to directly access values.

What does a hash function do in a Hash Map?

A Sorts the data alphabetically

B Encrypts the stored data

C Removes duplicate keys

D Converts a key into an index

A hash function converts a key into an index to find the data quickly.

If two keys have the same hash, what is this called?

A Underflow

B Duplication

C Collision

D Overflow

When two keys produce the same hash, it is called a collision.

Why is searching in an array slower than in a Hash Map?

A Arrays use keys to find data

B Arrays require checking each item one by one

C Arrays store data randomly

D Arrays have no memory

Arrays require checking each item one by one, making search slower.

What is a key in a Hash Map?

A A unique identifier for data

B A type of value stored

C A sorting method

D A data encryption tool

A key uniquely identifies data in a Hash Map.

Explain why Hash Maps are useful compared to arrays for searching data.

Think about how you find a friend's phone number quickly.

Describe what happens when two keys produce the same hash in a Hash Map and how it is handled.

Imagine two friends having the same nickname.

Practice

1. Why do we use a hash map in programming?
hashMap = {}

easy

A. To store key-value pairs for fast data lookup

B. To store data in a sorted order automatically

C. To perform mathematical calculations faster

D. To create a list of items without duplicates

Solution

1. Step 1: Understand the purpose of a hash map

   A hash map stores data as key-value pairs, allowing quick access to values using keys.

2. Step 2: Compare with other data structures

   Unlike lists or arrays, hash maps provide faster lookup by key, not by position or order.

3. Final Answer:

   To store key-value pairs for fast data lookup -> Option A

4. Quick Check:

   Hash map = fast key-value lookup [OK]

Hint: Hash maps store data by keys for quick access [OK]

Common Mistakes:

• Thinking hash maps sort data automatically
• Confusing hash maps with arrays or lists
• Assuming hash maps are for math calculations

2. Which of the following is the correct way to create an empty hash map (object) in JavaScript?

easy

A. const map = []

B. const map = {}

C. const map = () => {}

D. const map = new Map[]

Solution

1. Step 1: Recall JavaScript syntax for objects

   In JavaScript, curly braces {} create an empty object, which can be used as a hash map.

2. Step 2: Check other options

   Square brackets [] create arrays, () => {} is a function, and new Map[] is invalid syntax.

3. Final Answer:

   const map = {} -> Option B

4. Quick Check:

   Empty object = {} [OK]

Hint: Use curly braces {} to create empty hash maps in JavaScript [OK]

Common Mistakes:

• Using [] which creates an array, not a hash map
• Trying to use function syntax for hash map
• Incorrect new Map[] syntax

3. What will be the output of the following code?

const map = {};
map['apple'] = 5;
map['banana'] = 3;
console.log(map['apple']);

medium

A. 5

B. Error

C. 3

D. undefined

Solution

1. Step 1: Assign values to keys in the hash map

   The code sets map['apple'] = 5 and map['banana'] = 3, storing these key-value pairs.

2. Step 2: Access the value for key 'apple'

   console.log(map['apple']) prints the value 5 stored at key 'apple'.

3. Final Answer:

   5 -> Option A

4. Quick Check:

   map['apple'] = 5, output = 5 [OK]

Hint: Access value by key to get stored number [OK]

Common Mistakes:

• Expecting output to be 'undefined' if key exists
• Confusing values of different keys
• Thinking it causes an error

4. Find the error in this code that tries to use a hash map:

const map = {};
map.apple = 10;
console.log(map['applee']);

medium

A. Syntax error in object creation

B. Using dot notation instead of brackets

C. Cannot assign values to an empty object

D. Accessing a key that does not exist

Solution

1. Step 1: Check key assignment

   map.apple = 10 correctly assigns value 10 to key 'apple'.

2. Step 2: Check key access

   console.log(map['applee']) tries to access key 'applee' which was never assigned, so it returns undefined.

3. Final Answer:

   Accessing a key that does not exist -> Option D

4. Quick Check:

   Wrong key access = undefined [OK]

Hint: Check spelling of keys when accessing hash map values [OK]

Common Mistakes:

• Thinking dot notation is wrong here
• Expecting error on accessing missing key
• Assuming empty object cannot store values

5. You want to count how many times each word appears in an array using a hash map. Which approach correctly solves this problem?

const words = ['cat', 'dog', 'cat', 'bird'];
const counts = {};
// Fill counts here
console.log(counts);

hard

A. for (const w of words) { counts[w] = 1; }

B. for (const w of words) { counts[w] = counts[w] + 1; }

C. for (const w of words) { counts[w] = (counts[w] || 0) + 1; }

D. for (const w of words) { counts[w] += 1; }

Solution

1. Step 1: Understand counting logic

   We need to add 1 to the count for each word. If the word is new, start from 0.

2. Step 2: Analyze each option

   for (const w of words) { counts[w] = 1; } sets count to 1 always, ignoring repeats. for (const w of words) { counts[w] = counts[w] + 1; } tries to add 1 but counts[w] is undefined initially causing NaN. for (const w of words) { counts[w] = (counts[w] || 0) + 1; } uses (counts[w] || 0) + 1 to handle undefined keys correctly. for (const w of words) { counts[w] += 1; } tries to add 1 without initialization, causing NaN.

3. Final Answer:

   for (const w of words) { counts[w] = (counts[w] || 0) + 1; } -> Option C

4. Quick Check:

   Initialize with 0 or use || 0 before adding [OK]

Hint: Use (counts[key] || 0) + 1 to count safely [OK]

Common Mistakes:

• Not initializing counts before adding
• Overwriting counts instead of incrementing
• Assuming counts[w] is always defined