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DSA Javascriptprogramming~15 mins

Why Hash Map Exists and What Problem It Solves in DSA Javascript - See It Work

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Why Hash Map Exists and What Problem It Solves
📖 Scenario: Imagine you run a small library. You want to keep track of which book belongs to which shelf. You have many books, and you want to find any book quickly without searching every shelf.
🎯 Goal: You will create a simple way to store book names and their shelf numbers. Then, you will look up a book's shelf quickly using a hash map concept.
📋 What You'll Learn
Create a JavaScript object called library with exact book-shelf pairs
Create a variable called bookToFind with the exact book name to search
Use the library object to find the shelf number for bookToFind
Print the shelf number for the book
💡 Why This Matters
🌍 Real World
Hash maps are used in many apps to find information quickly, like looking up phone numbers, usernames, or product prices.
💼 Career
Understanding hash maps helps in software development jobs where fast data access is important, such as building search engines, databases, or caching systems.
Progress0 / 4 steps
1
DATA SETUP: Create the library object
Create a JavaScript object called library with these exact entries: 'The Hobbit': 5, '1984': 3, 'Hamlet': 7
DSA Javascript
Hint

Use curly braces {} to create an object. Put book names as keys and shelf numbers as values separated by colons.

2
CONFIGURATION: Choose the book to find
Create a variable called bookToFind and set it to the string '1984'
DSA Javascript
Hint

Use const bookToFind = '1984'; to store the book name you want to find.

3
CORE LOGIC: Find the shelf number using the hash map
Create a variable called shelfNumber and set it to the value in library for the key bookToFind
DSA Javascript
Hint

Use bracket notation library[bookToFind] to get the shelf number for the book.

4
OUTPUT: Print the shelf number
Write console.log(shelfNumber); to print the shelf number of the book
DSA Javascript
Hint

Use console.log(shelfNumber); to show the shelf number in the console.

Practice

(1/5)
1. Why do we use a hash map in programming?
hashMap = {}
easy
A. To store key-value pairs for fast data lookup
B. To store data in a sorted order automatically
C. To perform mathematical calculations faster
D. To create a list of items without duplicates

Solution

  1. Step 1: Understand the purpose of a hash map

    A hash map stores data as key-value pairs, allowing quick access to values using keys.
  2. Step 2: Compare with other data structures

    Unlike lists or arrays, hash maps provide faster lookup by key, not by position or order.
  3. Final Answer:

    To store key-value pairs for fast data lookup -> Option A
  4. Quick Check:

    Hash map = fast key-value lookup [OK]
Hint: Hash maps store data by keys for quick access [OK]
Common Mistakes:
  • Thinking hash maps sort data automatically
  • Confusing hash maps with arrays or lists
  • Assuming hash maps are for math calculations
2. Which of the following is the correct way to create an empty hash map (object) in JavaScript?
easy
A. const map = []
B. const map = {}
C. const map = () => {}
D. const map = new Map[]

Solution

  1. Step 1: Recall JavaScript syntax for objects

    In JavaScript, curly braces {} create an empty object, which can be used as a hash map.
  2. Step 2: Check other options

    Square brackets [] create arrays, () => {} is a function, and new Map[] is invalid syntax.
  3. Final Answer:

    const map = {} -> Option B
  4. Quick Check:

    Empty object = {} [OK]
Hint: Use curly braces {} to create empty hash maps in JavaScript [OK]
Common Mistakes:
  • Using [] which creates an array, not a hash map
  • Trying to use function syntax for hash map
  • Incorrect new Map[] syntax
3. What will be the output of the following code?
const map = {};
map['apple'] = 5;
map['banana'] = 3;
console.log(map['apple']);
medium
A. 5
B. Error
C. 3
D. undefined

Solution

  1. Step 1: Assign values to keys in the hash map

    The code sets map['apple'] = 5 and map['banana'] = 3, storing these key-value pairs.
  2. Step 2: Access the value for key 'apple'

    console.log(map['apple']) prints the value 5 stored at key 'apple'.
  3. Final Answer:

    5 -> Option A
  4. Quick Check:

    map['apple'] = 5, output = 5 [OK]
Hint: Access value by key to get stored number [OK]
Common Mistakes:
  • Expecting output to be 'undefined' if key exists
  • Confusing values of different keys
  • Thinking it causes an error
4. Find the error in this code that tries to use a hash map:
const map = {};
map.apple = 10;
console.log(map['applee']);
medium
A. Syntax error in object creation
B. Using dot notation instead of brackets
C. Cannot assign values to an empty object
D. Accessing a key that does not exist

Solution

  1. Step 1: Check key assignment

    map.apple = 10 correctly assigns value 10 to key 'apple'.
  2. Step 2: Check key access

    console.log(map['applee']) tries to access key 'applee' which was never assigned, so it returns undefined.
  3. Final Answer:

    Accessing a key that does not exist -> Option D
  4. Quick Check:

    Wrong key access = undefined [OK]
Hint: Check spelling of keys when accessing hash map values [OK]
Common Mistakes:
  • Thinking dot notation is wrong here
  • Expecting error on accessing missing key
  • Assuming empty object cannot store values
5. You want to count how many times each word appears in an array using a hash map. Which approach correctly solves this problem?
const words = ['cat', 'dog', 'cat', 'bird'];
const counts = {};
// Fill counts here
console.log(counts);
hard
A. for (const w of words) { counts[w] = 1; }
B. for (const w of words) { counts[w] = counts[w] + 1; }
C. for (const w of words) { counts[w] = (counts[w] || 0) + 1; }
D. for (const w of words) { counts[w] += 1; }

Solution

  1. Step 1: Understand counting logic

    We need to add 1 to the count for each word. If the word is new, start from 0.
  2. Step 2: Analyze each option

    for (const w of words) { counts[w] = 1; } sets count to 1 always, ignoring repeats. for (const w of words) { counts[w] = counts[w] + 1; } tries to add 1 but counts[w] is undefined initially causing NaN. for (const w of words) { counts[w] = (counts[w] || 0) + 1; } uses (counts[w] || 0) + 1 to handle undefined keys correctly. for (const w of words) { counts[w] += 1; } tries to add 1 without initialization, causing NaN.
  3. Final Answer:

    for (const w of words) { counts[w] = (counts[w] || 0) + 1; } -> Option C
  4. Quick Check:

    Initialize with 0 or use || 0 before adding [OK]
Hint: Use (counts[key] || 0) + 1 to count safely [OK]
Common Mistakes:
  • Not initializing counts before adding
  • Overwriting counts instead of incrementing
  • Assuming counts[w] is always defined
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10 questions~5 mineasy hard