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DSA Javascriptprogramming~20 mins

Why Hash Map Exists and What Problem It Solves in DSA Javascript - Challenge Your Understanding

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Challenge - 5 Problems
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Hash Map Mastery
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🧠 Conceptual
intermediate
2:00remaining
Why do we use a hash map instead of a list for key-value storage?

Imagine you want to store and quickly find phone numbers by name. You have two options: a list of pairs (name, number) or a hash map. Why is a hash map better for this?

ABecause a hash map stores items in order, making it easier to read.
BBecause a list automatically sorts the phone numbers alphabetically.
CBecause a list uses less memory than a hash map, so it is faster.
DBecause a hash map can find a phone number by name in constant time, while a list requires checking each item one by one.
Attempts:
2 left
💡 Hint

Think about how long it takes to find an item in a list versus a hash map.

❓ Predict Output
intermediate
2:00remaining
What is the output of this hash map usage example?

Consider this JavaScript code using a Map to store fruit colors. What will it print?

DSA Javascript
const fruitColors = new Map();
fruitColors.set('apple', 'red');
fruitColors.set('banana', 'yellow');
fruitColors.set('grape', 'purple');
console.log(fruitColors.get('banana'));
Aundefined
B"banana"
C"yellow"
Dnull
Attempts:
2 left
💡 Hint

Look at what value is stored with the key 'banana'.

❓ Predict Output
advanced
2:00remaining
What error occurs when accessing a missing key in a JavaScript object used as a hash map?

What will this code print or error?

DSA Javascript
const map = {a: 1, b: 2};
console.log(map['c'].toString());
ATypeError: Cannot read property 'toString' of undefined
Bundefined
Cnull
DReferenceError: c is not defined
Attempts:
2 left
💡 Hint

What happens if you try to call a method on undefined?

🧠 Conceptual
advanced
2:00remaining
How does a hash map solve the problem of slow search in large data?

When you have thousands of items, searching for one by scanning all items is slow. How does a hash map solve this problem?

AIt uses a hash function to convert keys into indexes, allowing direct access without scanning all items.
BIt sorts all items alphabetically to speed up search.
CIt stores all items in a linked list for faster traversal.
DIt duplicates all items to multiple places to find them faster.
Attempts:
2 left
💡 Hint

Think about how a hash function helps find the place to look.

🚀 Application
expert
3:00remaining
Which data structure is best for counting word frequencies in a large text?

You want to count how many times each word appears in a large text. Which data structure is best to store and update counts efficiently?

AStack to push each word and count.
BHash map (object or Map) to store words as keys and counts as values.
CLinked list to store words and counts sequentially.
DArray to store all words and counts in order.
Attempts:
2 left
💡 Hint

Think about fast lookup and update by word.

Practice

(1/5)
1. Why do we use a hash map in programming?
hashMap = {}
easy
A. To store key-value pairs for fast data lookup
B. To store data in a sorted order automatically
C. To perform mathematical calculations faster
D. To create a list of items without duplicates

Solution

  1. Step 1: Understand the purpose of a hash map

    A hash map stores data as key-value pairs, allowing quick access to values using keys.
  2. Step 2: Compare with other data structures

    Unlike lists or arrays, hash maps provide faster lookup by key, not by position or order.
  3. Final Answer:

    To store key-value pairs for fast data lookup -> Option A
  4. Quick Check:

    Hash map = fast key-value lookup [OK]
Hint: Hash maps store data by keys for quick access [OK]
Common Mistakes:
  • Thinking hash maps sort data automatically
  • Confusing hash maps with arrays or lists
  • Assuming hash maps are for math calculations
2. Which of the following is the correct way to create an empty hash map (object) in JavaScript?
easy
A. const map = []
B. const map = {}
C. const map = () => {}
D. const map = new Map[]

Solution

  1. Step 1: Recall JavaScript syntax for objects

    In JavaScript, curly braces {} create an empty object, which can be used as a hash map.
  2. Step 2: Check other options

    Square brackets [] create arrays, () => {} is a function, and new Map[] is invalid syntax.
  3. Final Answer:

    const map = {} -> Option B
  4. Quick Check:

    Empty object = {} [OK]
Hint: Use curly braces {} to create empty hash maps in JavaScript [OK]
Common Mistakes:
  • Using [] which creates an array, not a hash map
  • Trying to use function syntax for hash map
  • Incorrect new Map[] syntax
3. What will be the output of the following code?
const map = {};
map['apple'] = 5;
map['banana'] = 3;
console.log(map['apple']);
medium
A. 5
B. Error
C. 3
D. undefined

Solution

  1. Step 1: Assign values to keys in the hash map

    The code sets map['apple'] = 5 and map['banana'] = 3, storing these key-value pairs.
  2. Step 2: Access the value for key 'apple'

    console.log(map['apple']) prints the value 5 stored at key 'apple'.
  3. Final Answer:

    5 -> Option A
  4. Quick Check:

    map['apple'] = 5, output = 5 [OK]
Hint: Access value by key to get stored number [OK]
Common Mistakes:
  • Expecting output to be 'undefined' if key exists
  • Confusing values of different keys
  • Thinking it causes an error
4. Find the error in this code that tries to use a hash map:
const map = {};
map.apple = 10;
console.log(map['applee']);
medium
A. Syntax error in object creation
B. Using dot notation instead of brackets
C. Cannot assign values to an empty object
D. Accessing a key that does not exist

Solution

  1. Step 1: Check key assignment

    map.apple = 10 correctly assigns value 10 to key 'apple'.
  2. Step 2: Check key access

    console.log(map['applee']) tries to access key 'applee' which was never assigned, so it returns undefined.
  3. Final Answer:

    Accessing a key that does not exist -> Option D
  4. Quick Check:

    Wrong key access = undefined [OK]
Hint: Check spelling of keys when accessing hash map values [OK]
Common Mistakes:
  • Thinking dot notation is wrong here
  • Expecting error on accessing missing key
  • Assuming empty object cannot store values
5. You want to count how many times each word appears in an array using a hash map. Which approach correctly solves this problem?
const words = ['cat', 'dog', 'cat', 'bird'];
const counts = {};
// Fill counts here
console.log(counts);
hard
A. for (const w of words) { counts[w] = 1; }
B. for (const w of words) { counts[w] = counts[w] + 1; }
C. for (const w of words) { counts[w] = (counts[w] || 0) + 1; }
D. for (const w of words) { counts[w] += 1; }

Solution

  1. Step 1: Understand counting logic

    We need to add 1 to the count for each word. If the word is new, start from 0.
  2. Step 2: Analyze each option

    for (const w of words) { counts[w] = 1; } sets count to 1 always, ignoring repeats. for (const w of words) { counts[w] = counts[w] + 1; } tries to add 1 but counts[w] is undefined initially causing NaN. for (const w of words) { counts[w] = (counts[w] || 0) + 1; } uses (counts[w] || 0) + 1 to handle undefined keys correctly. for (const w of words) { counts[w] += 1; } tries to add 1 without initialization, causing NaN.
  3. Final Answer:

    for (const w of words) { counts[w] = (counts[w] || 0) + 1; } -> Option C
  4. Quick Check:

    Initialize with 0 or use || 0 before adding [OK]
Hint: Use (counts[key] || 0) + 1 to count safely [OK]
Common Mistakes:
  • Not initializing counts before adding
  • Overwriting counts instead of incrementing
  • Assuming counts[w] is always defined
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