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DSA Goprogramming~10 mins

Two Sum in BST in DSA Go - Execution Trace

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Concept Flow - Two Sum in BST
Start at root
Initialize empty set
Inorder traversal node
Check if complement exists in set
Return true
Move to next node
Repeat until all nodes visited or found
Return false if no pair found
Traverse the BST in order, check if complement of current node value exists in a set, return true if found, else add value and continue.
Execution Sample
DSA Go
func findTarget(root *TreeNode, k int) bool {
    set := make(map[int]bool)
    var inorder func(*TreeNode) bool
    inorder = func(node *TreeNode) bool {
        if node == nil { return false }
        if inorder(node.Left) { return true }
        if set[k - node.Val] { return true }
        set[node.Val] = true
        return inorder(node.Right)
    }
    return inorder(root)
}
This code checks if there exist two nodes in BST whose values sum to k using inorder traversal and a set.
Execution Table
StepOperationCurrent Node ValueSet ContentsCheck ComplementActionVisual State
1Start at root5{}Check if 9 - 5 = 4 in set4 not in set, add 55
2Go left3{5}Check if 9 - 3 = 6 in set6 not in set, add 33 -> 5
3Go left2{3,5}Check if 9 - 2 = 7 in set7 not in set, add 22 -> 3 -> 5
4Left nilnil{2,3,5}N/AReturn false2 -> 3 -> 5
5Back to 22{2,3,5}Already processedGo right2 -> 3 -> 5
6Right nilnil{2,3,5}N/AReturn false2 -> 3 -> 5
7Back to 33{2,3,5}Already processedGo right2 -> 3 -> 5
8Go right4{2,3,5}Check if 9 - 4 = 5 in set5 found! Return true4 -> 3 -> 5
9Found pair (4,5)N/A{2,3,5}N/AStop traversal4 -> 3 -> 5
💡 Found complement 5 for node 4, sum 9 achieved, traversal stops.
Variable Tracker
VariableStartAfter Step 1After Step 2After Step 3After Step 8Final
Current Noderoot (5)3244N/A
Set Contents{}{5}{3,5}{2,3,5}{2,3,5}{2,3,5}
Return Valuefalsefalsefalsefalsetruetrue
Key Moments - 3 Insights
Why do we check if complement exists before adding current node value to the set?
Because checking complement first avoids pairing a node with itself. See step 8 in execution_table where complement 5 is found before adding 4.
Why do we use inorder traversal for this problem?
Inorder traversal visits nodes in ascending order, but here it mainly ensures all nodes are visited systematically. The set handles complement checks. See steps 1-9 for traversal order.
What happens if the BST is empty?
The traversal immediately returns false since root is nil, no nodes to check. This is implied at step 4 when node is nil and returns false.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what is the set contents after step 3?
A{}
B{5}
C{3,5}
D{2,3,5}
💡 Hint
Check the 'Set Contents' column at step 3 in execution_table.
At which step does the traversal find the pair that sums to 9?
AStep 4
BStep 6
CStep 8
DStep 9
💡 Hint
Look for the step where 'Check if 9 - 4 = 5 in set' is true in execution_table.
If the target sum was 7 instead of 9, what would happen to the execution?
APair found earlier than step 8
BNo pair found, traversal completes all nodes
CTraversal stops at step 3
DSet remains empty
💡 Hint
Consider how complement checks depend on target k and see variable_tracker for set contents.
Concept Snapshot
Two Sum in BST:
- Traverse BST inorder
- Use a set to store visited values
- For each node, check if (target - node.Val) in set
- If yes, return true
- Else add node.Val to set
- Return false if no pair found
Full Transcript
This visualization shows how to find two numbers in a BST that add up to a target sum. We start at the root and traverse the tree in order. At each node, we check if the complement (target minus current node value) is already in a set of visited values. If it is, we found a pair and return true. If not, we add the current node value to the set and continue. The traversal stops early if a pair is found. The execution table tracks each step, the current node, the set contents, and actions taken. Variable tracker shows how the current node and set change over time. Key moments clarify why we check complement before adding the node value and why inorder traversal is used. The quiz tests understanding of set contents and when the pair is found.