Find Minimum in Rotated Sorted Array in DSA Go - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to return the first element as minimum when the array is not rotated.

DSA Go

if nums[0] [1] nums[len(nums)-1] {
    return nums[0]
}

Drag options to blanks, or click blank then click option'

A==

B>

C<

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '<' causes wrong rotation check.

Using '==' or '!=' does not correctly detect rotation.

If the first element is greater than the last, the array is rotated. Otherwise, the first element is the minimum.

2fill in blank

medium

Complete the code to calculate the middle index correctly.

DSA Go

mid := [1] + (high - low) / 2

Drag options to blanks, or click blank then click option'

Alow

Bhigh

Clen(nums)

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using (low + high) / 2 can cause overflow in some languages.

Using 0 or len(nums) as middle index is incorrect.

To avoid overflow, middle index is calculated as low + (high - low) / 2.

3fill in blank

hard

Fix the error in the condition to decide which half to search next.

DSA Go

if nums[mid] [1] nums[high] {
    low = mid + 1
} else {
    high = mid
}

Drag options to blanks, or click blank then click option'

A!=

B<

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' reverses the search direction.

Using '==' or '!=' causes incorrect logic.

If middle element is greater than the last element, minimum is in the right half.

4fill in blank

hard

Fill both blanks to complete the binary search loop and return statement.

DSA Go

for low [1] high {
    mid := low + (high - low) / 2
    if nums[mid] > nums[high] {
        low = mid + 1
    } else {
        high = mid
    }
}
return nums[2]

Drag options to blanks, or click blank then click option'

A<=

B<

C[low]

D[high]

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' instead of '<' causes infinite loop.

Returning nums[high] instead of nums[low] is incorrect.

The loop runs while low is less than high. After the loop, nums[low] is the minimum.

5fill in blank

hard

Fill all three blanks to create a function that finds the minimum in a rotated sorted array.

DSA Go

func findMin(nums []int) int {
    low, high := 0, len(nums) - 1
    if nums[0] [1] nums[high] {
        return nums[0]
    }
    for low [2] high {
        mid := low + (high - low) / 2
        if nums[mid] [3] nums[high] {
            low = mid + 1
        } else {
            high = mid
        }
    }
    return nums[low]
}

Drag options to blanks, or click blank then click option'

A>

B<=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong comparison operators in conditions.

Incorrect loop condition causing infinite loop or missed elements.

The function checks if array is rotated, then uses binary search with correct comparisons to find minimum.