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Diameter of Binary Tree in DSA Go - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is the diameter of a binary tree?
The diameter of a binary tree is the length of the longest path between any two nodes in the tree. This path may or may not pass through the root.
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intermediate
How do you calculate the diameter of a binary tree using recursion?
Calculate the height of left and right subtrees for each node. The diameter at that node is left height + right height. The overall diameter is the maximum of these values for all nodes.
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intermediate
Why do we use a helper function to calculate height and diameter together?
Using a helper function allows us to calculate the height of subtrees and update the diameter at the same time, avoiding repeated calculations and improving efficiency.
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intermediate
What is the time complexity of the diameter of binary tree algorithm using a single traversal?
The time complexity is O(n), where n is the number of nodes, because each node is visited once during the traversal.
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beginner
In Go, what data structure is commonly used to represent a binary tree node?
A struct with fields for the node's value and pointers to left and right child nodes is used to represent a binary tree node in Go.
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What does the diameter of a binary tree represent?
AThe longest path between any two nodes
BThe height of the tree
CThe number of leaf nodes
DThe number of nodes in the tree
Which of these is needed to compute the diameter at a node?
ANumber of children nodes
BOnly the height of the left subtree
COnly the height of the right subtree
DSum of heights of left and right subtrees
What is the best time complexity to find the diameter of a binary tree?
AO(log n)
BO(n^2)
CO(n)
DO(1)
In Go, how do you represent a binary tree node?
AUsing an array
BUsing a struct with value and pointers to left and right nodes
CUsing a map
DUsing a slice
Why is a helper function useful in diameter calculation?
ATo calculate height and update diameter in one traversal
BTo print the tree
CTo sort the nodes
DTo delete nodes
Explain how to find the diameter of a binary tree using recursion.
Think about how height and diameter relate at each node.
You got /4 concepts.
    Describe the structure of a binary tree node in Go and how it supports diameter calculation.
    Focus on how the node connects to its children.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the diameter of a binary tree represent?
      easy
      A. The length of the longest path between any two nodes in the tree
      B. The number of nodes in the tree
      C. The height of the tree
      D. The number of leaf nodes in the tree

      Solution

      1. Step 1: Understand the diameter definition

        The diameter is the longest path between any two nodes, which may or may not pass through the root.
      2. Step 2: Differentiate from other tree properties

        Height is the longest path from root to leaf, number of nodes counts all nodes, leaves count only leaf nodes.
      3. Final Answer:

        The length of the longest path between any two nodes in the tree -> Option A
      4. Quick Check:

        Diameter = longest path between nodes [OK]
      Hint: Diameter is longest path, not height or node count [OK]
      Common Mistakes:
      • Confusing diameter with height
      • Thinking diameter counts nodes instead of edges
      • Assuming diameter must pass through root
      2. Which Go function signature correctly represents a helper function to compute the height of a binary tree node for diameter calculation?
      easy
      A. func height(node int) int
      B. func height(node *TreeNode) int
      C. func height(node *TreeNode) bool
      D. func height(node TreeNode) string

      Solution

      1. Step 1: Identify correct parameter type

        The function should accept a pointer to TreeNode to handle nil nodes and avoid copying.
      2. Step 2: Identify correct return type

        Height is an integer value representing depth, so return type must be int.
      3. Final Answer:

        func height(node *TreeNode) int -> Option B
      4. Quick Check:

        Pointer input and int output for height [OK]
      Hint: Height function uses pointer receiver and returns int [OK]
      Common Mistakes:
      • Using value receiver instead of pointer
      • Returning wrong type like string or bool
      • Passing int instead of TreeNode pointer
      3. Given the following Go code snippet, what is the diameter of the binary tree?
      type TreeNode struct {
          Val int
          Left *TreeNode
          Right *TreeNode
      }
      
      root := &TreeNode{Val: 1}
      root.Left = &TreeNode{Val: 2}
      root.Right = &TreeNode{Val: 3}
      root.Left.Left = &TreeNode{Val: 4}
      root.Left.Right = &TreeNode{Val: 5}
      
      // Diameter function uses height helper internally
      func diameterOfBinaryTree(root *TreeNode) int {
          maxDiameter := 0
          var height func(node *TreeNode) int
          height = func(node *TreeNode) int {
              if node == nil {
                  return 0
              }
              leftHeight := height(node.Left)
              rightHeight := height(node.Right)
              if leftHeight+rightHeight > maxDiameter {
                  maxDiameter = leftHeight + rightHeight
              }
              if leftHeight > rightHeight {
                  return leftHeight + 1
              }
              return rightHeight + 1
          }
          height(root)
          return maxDiameter
      }
      
      fmt.Println(diameterOfBinaryTree(root))
      medium
      A. 4
      B. 2
      C. 3
      D. 5

      Solution

      1. Step 1: Calculate heights of subtrees

        Left subtree of root has height 2 (nodes 2->4 or 2->5), right subtree height is 1 (node 3).
      2. Step 2: Calculate diameter as sum of left and right heights

        Diameter = leftHeight + rightHeight = 2 + 1 = 3 edges, but diameter counts edges, so longest path is 3 edges which means 4 nodes.
      3. Final Answer:

        3 -> Option C
      4. Quick Check:

        Longest path length = 3 edges [OK]
      Hint: Diameter = sum of left and right subtree heights at max node [OK]
      Common Mistakes:
      • Counting nodes instead of edges for diameter
      • Ignoring one subtree height
      • Confusing height with diameter
      4. Identify the bug in this Go code snippet for computing the diameter of a binary tree:
      func diameterOfBinaryTree(root *TreeNode) int {
          maxDiameter := 0
          var height func(node *TreeNode) int
          height = func(node *TreeNode) int {
              if node == nil {
                  return 0
              }
              leftHeight := height(node.Left)
              rightHeight := height(node.Right)
              maxDiameter = leftHeight + rightHeight
              if leftHeight > rightHeight {
                  return leftHeight + 1
              }
              return rightHeight + 1
          }
          height(root)
          return maxDiameter
      }
      medium
      A. Function does not call height recursively
      B. height function returns wrong type
      C. Missing base case for nil node
      D. maxDiameter is overwritten without checking max value

      Solution

      1. Step 1: Analyze maxDiameter update

        maxDiameter is assigned leftHeight + rightHeight every time, overwriting previous max without comparison.
      2. Step 2: Correct maxDiameter update

        Should update maxDiameter only if leftHeight + rightHeight is greater than current maxDiameter.
      3. Final Answer:

        maxDiameter is overwritten without checking max value -> Option D
      4. Quick Check:

        Use max check before assignment [OK]
      Hint: Update maxDiameter only if new value is greater [OK]
      Common Mistakes:
      • Overwriting maxDiameter without max check
      • Forgetting base case for nil node
      • Not calling height recursively
      5. You want to find the diameter of a binary tree but also return the path nodes forming that diameter. Which approach correctly extends the diameter calculation in Go?
      hard
      A. Modify height function to return both height and path, update max path when diameter increases
      B. Calculate diameter first, then do a separate BFS to find path
      C. Store all paths in a global slice and pick the longest after traversal
      D. Use only height function and return diameter length without path

      Solution

      1. Step 1: Extend height function to track paths

        Modify the recursive height function to return both height and the path nodes from current node to leaf.
      2. Step 2: Update max diameter and store path

        When leftHeight + rightHeight exceeds maxDiameter, update maxDiameter and store concatenated path from left and right subtrees through current node.
      3. Step 3: Return stored path after traversal

        After full traversal, return the stored path representing the diameter.
      4. Final Answer:

        Modify height function to return both height and path, update max path when diameter increases -> Option A
      5. Quick Check:

        Track height and path together for diameter path [OK]
      Hint: Return height and path from helper to track diameter path [OK]
      Common Mistakes:
      • Trying to find path after diameter without tracking
      • Storing all paths wastes memory
      • Ignoring path tracking in recursion
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