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DSA Goprogramming~10 mins

Boundary Traversal of Binary Tree in DSA Go - Execution Trace

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Concept Flow - Boundary Traversal of Binary Tree
Start at root
Add root to boundary
Traverse left boundary down
Add leaf nodes from left to right
Traverse right boundary up
Combine all parts for final boundary
Start from root, add left boundary top-down, then leaves left to right, then right boundary bottom-up to get full boundary.
Execution Sample
DSA Go
func BoundaryTraversal(root *Node) []int {
  if root == nil { return []int{} }
  res := []int{root.Val}
  addLeftBoundary(root.Left, &res)
  addLeaves(root.Left, &res)
  addLeaves(root.Right, &res)
  addRightBoundary(root.Right, &res)
  return res
}
This code collects the boundary nodes of a binary tree in anti-clockwise order.
Execution Table
StepOperationNode VisitedPointer ChangesVisual State
1Start at root1root points to Node(1)Boundary: [1]
2Add left boundary top-down2current moves down left boundaryBoundary: [1, 2, 4]
3Add leaf nodes left subtree4, 7traverse leavesBoundary: [1, 2, 4, 7]
4Add leaf nodes right subtree8, 9traverse leavesBoundary: [1, 2, 4, 7, 8, 9]
5Add right boundary bottom-up3, 6current moves up right boundaryBoundary: [1, 2, 4, 7, 8, 9, 6, 3]
6Traversal completenilnoneFinal Boundary: [1, 2, 4, 7, 8, 9, 6, 3]
💡 All boundary nodes visited in anti-clockwise order, traversal ends.
Variable Tracker
VariableStartAfter Step 2After Step 3After Step 4After Step 5Final
res (boundary list)[][1, 2, 4][1, 2, 4, 7][1, 2, 4, 7, 8, 9][1, 2, 4, 7, 8, 9, 6, 3][1, 2, 4, 7, 8, 9, 6, 3]
current (left boundary)Node(2)Node(4)nilnilnilnil
current (right boundary)Node(3)Node(6)nilnilnilnil
Key Moments - 3 Insights
Why do we add leaf nodes separately after left boundary traversal?
Left boundary traversal adds only non-leaf nodes on the left edge (see Step 2). Leaf nodes are added separately (Steps 3 and 4) to avoid duplicates and to include leaves from both left and right subtrees.
Why is the right boundary added bottom-up?
Right boundary nodes are added bottom-up (Step 5) to maintain anti-clockwise order. Adding them top-down would reverse the boundary order.
What happens if the root has no left or right child?
If root has no left or right child, left and right boundary traversals add nothing, and only root and leaf nodes (which may be root itself) are added (Step 1 and leaf steps).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, what is the boundary list after Step 3?
A[1, 2, 4, 7]
B[1, 2, 4]
C[1, 2, 4, 7, 8]
D[1, 2]
💡 Hint
Check the 'Visual State' column at Step 3 in the execution_table.
At which step does the right boundary get added to the boundary list?
AStep 2
BStep 5
CStep 4
DStep 3
💡 Hint
Look for 'Add right boundary bottom-up' operation in the execution_table.
If the tree had no right subtree, how would the final boundary list change?
AIt would exclude nodes 2 and 4
BIt would include extra leaf nodes from right
CIt would exclude nodes 3 and 6
DIt would be empty
💡 Hint
Refer to variable_tracker and execution_table steps involving right boundary nodes.
Concept Snapshot
Boundary Traversal of Binary Tree:
- Start at root, add root value
- Traverse left boundary top-down (exclude leaves)
- Add all leaf nodes left to right
- Traverse right boundary bottom-up (exclude leaves)
- Combine all for anti-clockwise boundary
- Avoid duplicates by separating leaves
Full Transcript
Boundary traversal of a binary tree collects nodes on the outer edge in anti-clockwise order. We start at the root, add it to the boundary list. Then we traverse the left boundary from top to bottom, adding only non-leaf nodes. Next, we add all leaf nodes from left subtree and right subtree in left to right order. Finally, we traverse the right boundary from bottom to top, adding non-leaf nodes. This order ensures the boundary is collected without duplicates and in correct anti-clockwise order. The execution table shows each step with nodes visited and how the boundary list grows. Key moments clarify why leaves are added separately and why right boundary is added bottom-up. The visual quiz tests understanding of these steps and the final boundary list.