What is the main idea behind using a hash map to find subarrays with sum equals k?
We use a hash map to store the cumulative sums and their counts. This helps us quickly find if a previous cumulative sum exists such that the difference with the current sum is k, indicating a subarray with sum k.
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beginner
In the context of subarray sum equals k, what does the cumulative sum represent?
The cumulative sum at index i is the sum of all elements from the start of the array up to index i. It helps track sums of subarrays efficiently.
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intermediate
Why do we initialize the hash map with {0:1} before processing the array?
Initializing with {0:1} accounts for the case where a subarray starting from index 0 has a sum equal to k. It means the cumulative sum itself equals k without needing a previous sum.
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intermediate
What is the time complexity of the hash map approach for finding subarray sum equals k?
The time complexity is O(n), where n is the number of elements in the array, because we traverse the array once and perform constant-time hash map operations.
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advanced
How does the hash map help in counting multiple subarrays with sum k?
The hash map stores counts of cumulative sums. When the difference (current cumulative sum - k) appears multiple times, it means multiple subarrays ending at the current index have sum k, so we add all those counts.
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What does the hash map store in the subarray sum equals k problem?
ACumulative sums and their counts
BIndividual elements and their indices
CSubarray lengths
DSum of all elements
✗ Incorrect
The hash map stores cumulative sums as keys and their counts as values to quickly find subarrays with sum k.
Why do we check if (current_sum - k) exists in the hash map?
ATo count negative numbers
BTo find the maximum element
CTo find if a subarray ending at current index sums to k
DTo reset the cumulative sum
✗ Incorrect
If (current_sum - k) exists, it means a previous cumulative sum allows a subarray summing to k ending at current index.
What initial value do we put in the hash map before starting the iteration?
A{}
B{0:1}
C{k:1}
D{-k:1}
✗ Incorrect
We initialize with {0:1} to handle subarrays starting at index 0 that sum to k.
What is the time complexity of the hash map solution for subarray sum equals k?
AO(n^2)
BO(1)
CO(log n)
DO(n)
✗ Incorrect
The solution runs in O(n) time because it processes each element once with constant-time hash map operations.
If the array is [1, 2, 3] and k=3, how many subarrays sum to k?
A2
B1
C3
D0
✗ Incorrect
Subarrays [1, 2] and [3] both sum to 3, so the answer is 2.
Explain how a hash map helps find the number of subarrays with sum equal to k.
Think about how previous sums relate to current sums to find subarrays.
You got /4 concepts.
Describe the steps to implement the subarray sum equals k solution using a hash map.
Focus on how cumulative sums and hash map interact during iteration.
You got /4 concepts.
Practice
(1/5)
1. What is the main purpose of using a hash map in the Subarray Sum Equals K problem?
easy
A. To store the original array elements as keys
B. To sort the array elements before processing
C. To store cumulative sums and their frequencies for quick lookup
D. To keep track of the maximum subarray length
Solution
Step 1: Understand the problem goal
The problem requires finding subarrays whose sums equal a target value k.
Step 2: Role of hash map in solution
A hash map stores cumulative sums seen so far and their counts, enabling quick checks if a previous sum exists that forms a subarray summing to k.
Final Answer:
To store cumulative sums and their frequencies for quick lookup -> Option C
Quick Check:
Hash map = cumulative sums storage [OK]
Hint: Hash map tracks sums to find subarrays fast [OK]
Common Mistakes:
Thinking hash map stores array elements as keys
Assuming sorting is needed
Confusing hash map with array for sums
2. Which of the following Go code snippets correctly initializes a hash map to store integer keys and values for the subarray sum problem?
easy
A. m := make([]int, 0)
B. m := make(map[int]int)
C. m := map[int]string{}
D. m := map[string]int{}
Solution
Step 1: Identify correct map type for keys and values
We need a map with integer keys and integer values to store sums and counts.
Step 2: Check Go syntax for map initialization
make(map[int]int) correctly creates a map with int keys and int values.
Final Answer:
m := make(map[int]int) -> Option B
Quick Check:
map[int]int = correct map type [OK]
Hint: Use make(map[int]int) for int keys and values [OK]
Common Mistakes:
Using slice instead of map
Wrong key or value types in map
Using map with string keys incorrectly
3. What is the output of the following Go code snippet?
nums := []int{1, 2, 3}
k := 3
count := 0
sum := 0
m := make(map[int]int)
m[0] = 1
for _, v := range nums {
sum += v
if val, ok := m[sum-k]; ok {
count += val
}
m[sum]++
}
fmt.Println(count)
medium
A. 1
B. 0
C. 3
D. 2
Solution
Step 1: Trace cumulative sums and map updates
Iteration 1: sum=1, m[1]=1, sum-k=-2 not in map, count=0
Iteration 2: sum=3, sum-k=0 in map with count 1, count=1, m[3]=1
Iteration 3: sum=6, sum-k=3 in map with count 1, count=2, m[6]=1
Step 2: Final count after loop
Count is 2 because two subarrays sum to k=3: [1,2] and [3].
Final Answer:
2 -> Option D
Quick Check:
Subarrays summing to 3 = 2 [OK]
Hint: Count increments when (sum-k) found in map [OK]
Common Mistakes:
Not initializing m[0] = 1
Forgetting to increment map count
Miscounting subarrays
4. Identify the bug in the following Go code snippet for counting subarrays summing to k:
nums := []int{1, 1, 1}
k := 2
count := 0
sum := 0
m := make(map[int]int)
for _, v := range nums {
sum += v
if val, ok := m[sum-k]; ok {
count += val
}
m[sum]++
}
fmt.Println(count)
medium
A. Missing initialization m[0] = 1 before loop
B. Incorrect increment of count variable
C. Wrong loop variable used
D. Using map with wrong key type
Solution
Step 1: Check map initialization
The map m is used to store cumulative sums, but m[0] is not initialized to 1 before the loop.
Step 2: Effect of missing m[0] = 1
Without m[0] = 1, subarrays starting from index 0 that sum to k are not counted, causing incorrect count.
Final Answer:
Missing initialization m[0] = 1 before loop -> Option A
Quick Check:
Initialize m[0]=1 to count subarrays from start [OK]
Hint: Always set m[0] = 1 before loop [OK]
Common Mistakes:
Not initializing m[0]
Incrementing count incorrectly
Using wrong map key type
5. Given the array nums = []int{3, 4, 7, 2, -3, 1, 4, 2} and k = 7, how many subarrays sum to k? Use the hash map approach to find the count.
hard
A. 4
B. 3
C. 6
D. 5
Solution
Step 1: Calculate cumulative sums and track counts
Initialize m[0]=1, sum=0, count=0
Iterate nums:
- sum=3, sum-k=-4 not in m, m[3]=1
- sum=7, sum-k=0 in m=1, count=1, m[7]=1
- sum=14, sum-k=7 in m=1, count=2, m[14]=1
- sum=16, sum-k=9 not in m, m[16]=1
- sum=13, sum-k=6 not in m, m[13]=1
- sum=14, sum-k=7 in m=1, count=3, m[14]=2
- sum=18, sum-k=11 not in m, m[18]=1
- sum=20, sum-k=13 in m=1, count=4, m[20]=1
Step 2: Verify subarrays
The subarrays summing to 7 are: [3,4], [7], [7,2,-3,1], [1,4,2]. Total count = 4.
Final Answer:
4 -> Option A
Quick Check:
Count subarrays with sum k = 4 [OK]
Hint: Track cumulative sums and counts carefully [OK]
Common Mistakes:
Missing m[0] initialization
Miscounting overlapping subarrays
Not updating map counts correctly
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