Tree Traversal Postorder Left Right Root in DSA C# - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the order of visiting nodes in Postorder Tree Traversal?

In Postorder traversal, nodes are visited in this order: Left subtree, Right subtree, then Root node.

intermediate

Why is Postorder traversal useful in expression trees?

Postorder traversal visits children before the parent, which matches the order needed to evaluate expressions (operands before operators).

beginner

Given a binary tree, what will be the Postorder traversal output for this tree?
Root: 1
Left child: 2
Right child: 3

The Postorder traversal visits Left (2), Right (3), then Root (1). So the output is: 2 -> 3 -> 1 -> null

beginner

What is the base case in a recursive Postorder traversal function?

The base case is when the current node is null (no node), then return without doing anything.

beginner

How does Postorder traversal differ from Preorder traversal?

Postorder visits Left, Right, then Root. Preorder visits Root, Left, then Right. The root is visited last in Postorder but first in Preorder.

In Postorder traversal, which node is visited last?

A None

B Left child

C Root node

D Right child

Postorder visits Left, then Right, and finally the Root node.

What is the first step in Postorder traversal?

A Visit Root node

B Visit Left subtree

C Visit Right subtree

D Visit both subtrees simultaneously

Postorder traversal starts by visiting the Left subtree first.

Which traversal order is Postorder?

A Left, Right, Root

B Left, Root, Right

C Root, Left, Right

D Right, Left, Root

Postorder traversal visits Left subtree, then Right subtree, then Root.

In which scenario is Postorder traversal especially useful?

A Evaluating expression trees

B Printing nodes in ascending order

C Searching for a value quickly

D Building a linked list

Postorder traversal evaluates children before the parent, matching expression evaluation order.

What is the base case for the recursive Postorder traversal function?

A When node is root

B When node is a leaf

C When node has two children

D When node is null

The recursion stops when the current node is null (no node).

Explain the steps of Postorder traversal on a binary tree.

Think about visiting children before the parent.

Describe a real-life example where Postorder traversal is useful and why.

Consider how calculators or compilers process expressions.

Practice

1. What is the order of nodes visited in a postorder tree traversal?

easy

A. Left subtree, Right subtree, Root node

B. Root node, Left subtree, Right subtree

C. Root node, Right subtree, Left subtree

D. Right subtree, Left subtree, Root node

Solution

1. Step 1: Understand postorder traversal definition

   Postorder traversal visits the left subtree first, then the right subtree, and finally the root node.

2. Step 2: Confirm the visiting order

   This order ensures children nodes are processed before their parent node.

3. Final Answer:

   Left subtree, Right subtree, Root node -> Option A

4. Quick Check:

   Postorder = Left, Right, Root [OK]

Hint: Remember: postorder ends with the root node [OK]

Common Mistakes:

• Confusing postorder with preorder or inorder
• Visiting root node first instead of last
• Swapping left and right subtree order

2. Which of the following C# method signatures correctly represents a postorder traversal of a binary tree node named root?

easy

A. void PostorderTraversal(Node root) { PostorderTraversal(root.Right); PostorderTraversal(root.Left); Console.WriteLine(root.Value); }

B. void PostorderTraversal(Node root) { Console.WriteLine(root.Value); PostorderTraversal(root.Left); PostorderTraversal(root.Right); }

C. void PostorderTraversal(Node root) { PostorderTraversal(root.Left); PostorderTraversal(root.Right); Console.WriteLine(root.Value); }

D. void PostorderTraversal(Node root) { Console.WriteLine(root.Value); PostorderTraversal(root.Right); PostorderTraversal(root.Left); }

Solution

1. Step 1: Identify correct postorder call sequence

   Postorder traversal calls left subtree, then right subtree, then processes the root.

2. Step 2: Match method calls to postorder order

   void PostorderTraversal(Node root) { PostorderTraversal(root.Left); PostorderTraversal(root.Right); Console.WriteLine(root.Value); } calls left, then right, then prints root value, matching postorder traversal.

3. Final Answer:

   void PostorderTraversal(Node root) { PostorderTraversal(root.Left); PostorderTraversal(root.Right); Console.WriteLine(root.Value); } -> Option C

4. Quick Check:

   Left, Right, Root call order = void PostorderTraversal(Node root) { PostorderTraversal(root.Left); PostorderTraversal(root.Right); Console.WriteLine(root.Value); } [OK]

Hint: Postorder prints after left and right recursive calls [OK]

Common Mistakes:

• Printing root value before recursive calls
• Swapping left and right subtree calls
• Missing recursive calls for subtrees

3. Given the binary tree below, what is the output of a postorder traversal?

    1
   / \
  2   3
 / \
4   5

medium

A. [1, 2, 3, 4, 5]

B. [4, 5, 2, 3, 1]

C. [2, 4, 5, 3, 1]

D. [4, 2, 5, 3, 1]

Solution

1. Step 1: Traverse left subtree of root (1)

   Left subtree is rooted at 2, with children 4 and 5. Postorder visits 4, then 5, then 2.

2. Step 2: Traverse right subtree and root

   Right subtree is 3 (leaf), visited next. Finally, root 1 is visited last.

3. Final Answer:

   [4, 5, 2, 3, 1] -> Option B

4. Quick Check:

   Postorder = Left, Right, Root = [4,5,2,3,1] [OK]

Hint: Visit children fully before parent in postorder [OK]

Common Mistakes:

• Visiting root before children
• Swapping left and right subtree order
• Confusing preorder or inorder output

4. The following C# code attempts a postorder traversal but produces incorrect output. What is the error?

void Postorder(Node root) {
  if (root == null) return;
  Console.WriteLine(root.Value);
  Postorder(root.Left);
  Postorder(root.Right);
}

medium

A. The root value is printed before traversing subtrees

B. The base case for null root is missing

C. Left and right subtree calls are swapped

D. The method does not return any value

Solution

1. Step 1: Analyze the order of operations in code

   The code prints root value first, then traverses left and right subtrees.

2. Step 2: Compare with postorder traversal rules

   Postorder requires visiting left and right subtrees before printing root value.

3. Final Answer:

   Root value printed before subtrees traversal -> Option A

4. Quick Check:

   Postorder prints after children, not before [OK]

Hint: Print root after recursive calls for postorder [OK]

Common Mistakes:

• Printing root before recursive calls
• Ignoring null base case (though present here)
• Swapping left and right subtree calls

5. You want to collect all node values of a binary tree in postorder traversal into a list in C#. Which code snippet correctly implements this?

hard

A. void Postorder(Node root, List<int> result) { if(root == null) return; result.Add(root.Value); Postorder(root.Right, result); Postorder(root.Left, result); }

B. void Postorder(Node root, List<int> result) { if(root == null) return; result.Add(root.Value); Postorder(root.Left, result); Postorder(root.Right, result); }

C. void Postorder(Node root, List<int> result) { if(root == null) return; Postorder(root.Right, result); Postorder(root.Left, result); result.Add(root.Value); }

D. void Postorder(Node root, List<int> result) { if(root == null) return; Postorder(root.Left, result); Postorder(root.Right, result); result.Add(root.Value); }

Solution

1. Step 1: Confirm traversal order in code

   void Postorder(Node root, List<int> result) { if(root == null) return; Postorder(root.Left, result); Postorder(root.Right, result); result.Add(root.Value); } calls left subtree, then right subtree, then adds root value to list, matching postorder.

2. Step 2: Verify list collection logic

   Adding root value after recursive calls ensures correct postorder sequence in the list.

3. Final Answer:

   void Postorder(Node root, List<int> result) { if(root == null) return; Postorder(root.Left, result); Postorder(root.Right, result); result.Add(root.Value); } -> Option D

4. Quick Check:

   Left, Right, Root with Add after recursion [OK]

Hint: Add node value after left and right recursive calls [OK]

Common Mistakes:

• Adding root value before recursive calls
• Swapping left and right subtree calls
• Not handling null root properly