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Path Sum Root to Leaf in Binary Tree in DSA C# - Time & Space Complexity

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Time Complexity: Path Sum Root to Leaf in Binary Tree
O(n)
Understanding Time Complexity

We want to know how the time needed to check if a path sum exists grows as the tree gets bigger.

How does the number of nodes affect the work done?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


public bool HasPathSum(TreeNode root, int targetSum) {
    if (root == null) return false;
    if (root.left == null && root.right == null) {
        return targetSum == root.val;
    }
    return HasPathSum(root.left, targetSum - root.val) || HasPathSum(root.right, targetSum - root.val);
}
    

This code checks if there is a root-to-leaf path where the sum of node values equals the target sum.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: Recursive calls visiting each node once.
  • How many times: Each node is visited once in the worst case.
How Execution Grows With Input

As the number of nodes grows, the function visits each node once, so work grows directly with the number of nodes.

Input Size (n)Approx. Operations
10About 10 visits
100About 100 visits
1000About 1000 visits

Pattern observation: The work grows linearly as the tree size increases.

Final Time Complexity

Time Complexity: O(n)

This means the time to check the path sum grows in direct proportion to the number of nodes in the tree.

Common Mistake

[X] Wrong: "The function only checks one path, so it runs in constant time."

[OK] Correct: The function explores all possible root-to-leaf paths, so it must visit every node to be sure.

Interview Connect

Understanding this helps you explain how recursive tree traversal works and why visiting all nodes is necessary to solve path sum problems.

Self-Check

"What if the tree was balanced versus very skewed? How would the time complexity change?"

Practice

(1/5)
1. What does the "Path Sum Root to Leaf" problem ask you to find in a binary tree?
easy
A. The total number of nodes in the binary tree
B. The maximum depth of the binary tree
C. If there exists a root-to-leaf path with a sum equal to a given target
D. The sum of all node values in the binary tree

Solution

  1. Step 1: Understand the problem statement

    The problem asks to check if any path from the root node down to any leaf node sums up exactly to a given target value.
  2. Step 2: Identify what is being checked

    We are not asked for maximum depth, total nodes, or sum of all nodes, but specifically for a path sum equal to the target.
  3. Final Answer:

    If there exists a root-to-leaf path with a sum equal to a given target -> Option C
  4. Quick Check:

    Path sum check = If there exists a root-to-leaf path with a sum equal to a given target [OK]
Hint: Look for a path from root to leaf matching target sum [OK]
Common Mistakes:
  • Confusing path sum with total tree sum
  • Checking any path, not just root-to-leaf
  • Looking for maximum depth instead
2. Which of the following C# method signatures correctly represents a function to check path sum in a binary tree node class?
easy
A. public bool HasPathSum(TreeNode root, int targetSum)
B. public int HasPathSum(TreeNode root, int targetSum)
C. public void HasPathSum(TreeNode root, int targetSum)
D. public string HasPathSum(TreeNode root, int targetSum)

Solution

  1. Step 1: Determine the return type for path sum check

    The function should return true or false indicating if such a path exists, so return type must be bool.
  2. Step 2: Check method signature correctness

    public bool HasPathSum(TreeNode root, int targetSum) returns bool and takes root node and target sum as parameters, matching the problem requirements.
  3. Final Answer:

    public bool HasPathSum(TreeNode root, int targetSum) -> Option A
  4. Quick Check:

    Return type bool for yes/no check = public bool HasPathSum(TreeNode root, int targetSum) [OK]
Hint: Return bool for yes/no path sum check [OK]
Common Mistakes:
  • Using int or void return type instead of bool
  • Returning string instead of boolean
  • Incorrect parameter types or order
3. Given the following binary tree and targetSum = 22, what will the method HasPathSum(root, 22) return?
    5
   / \
  4   8
 /   / \
11  13  4
/  \      
7    2      1
medium
A. Runtime error
B. true
C. null
D. false

Solution

  1. Step 1: Identify root-to-leaf paths and their sums

    Check paths: 5->4->11->7 = 27, 5->4->11->2 = 22, 5->8->13 = 26, 5->8->4->1 = 18.
  2. Step 2: Check if any path sum equals 22

    Path 5->4->11->2 sums to 22, so the method returns true.
  3. Final Answer:

    true -> Option B
  4. Quick Check:

    Path sum 22 exists = true [OK]
Hint: Sum each root-to-leaf path to find target [OK]
Common Mistakes:
  • Ignoring leaf node condition
  • Summing partial paths not ending at leaf
  • Miscomputing sums of nodes
4. The following C# code attempts to check path sum but has a bug. What is the error?
public bool HasPathSum(TreeNode root, int targetSum) {
    if (root == null) return false;
    if (root.left == null && root.right == null) return root.val == targetSum;
    return HasPathSum(root.left, targetSum - root.val) || HasPathSum(root.right, targetSum - root.val);
}
medium
A. No bug; code works correctly
B. Should check for null root after subtracting value
C. Incorrect base case for leaf node check
D. Missing return statement in recursive calls

Solution

  1. Step 1: Analyze base cases and recursion

    Code returns false if root is null, correctly handles leaf node by comparing value to targetSum, and recursively checks left and right subtrees with updated targetSum.
  2. Step 2: Confirm correctness of logic

    All conditions and recursive calls are correct and return statements are present.
  3. Final Answer:

    No bug; code works correctly -> Option A
  4. Quick Check:

    Code logic matches problem requirements = No bug; code works correctly [OK]
Hint: Check base cases and recursive returns carefully [OK]
Common Mistakes:
  • Forgetting to subtract node value from targetSum
  • Missing return keyword in recursion
  • Incorrect leaf node condition
5. You want to find all root-to-leaf paths in a binary tree where the sum of node values equals a target sum. Which approach best extends the path sum check to collect all such paths?
hard
A. Sum all nodes and compare to target sum once traversal ends
B. Use BFS and stop at first path matching the sum
C. Use recursion without tracking path, just return true/false
D. Use DFS with a list to track current path and add to result when sum matches at leaf

Solution

  1. Step 1: Understand the requirement to collect all paths

    We need to find all root-to-leaf paths with sum equal to target, so we must track the current path during traversal.
  2. Step 2: Choose the correct traversal and tracking method

    DFS with a list to store nodes along the current path allows backtracking and collecting all valid paths when leaf and sum conditions are met.
  3. Final Answer:

    Use DFS with a list to track current path and add to result when sum matches at leaf -> Option D
  4. Quick Check:

    Track paths with DFS and list = Use DFS with a list to track current path and add to result when sum matches at leaf [OK]
Hint: Track path nodes during DFS to collect all valid paths [OK]
Common Mistakes:
  • Using BFS which is less natural for path tracking
  • Not tracking path nodes, only sums
  • Stopping at first found path instead of all
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