Maximum Path Sum in Binary Tree in DSA C# - Time & Space Complexity

Time Complexity: Maximum Path Sum in Binary Tree

O(n)

Understanding Time Complexity

We want to understand how the time needed to find the maximum path sum in a binary tree grows as the tree gets bigger.

Specifically, how does the number of steps change when the number of nodes increases?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

public int MaxPathSum(TreeNode root) {
    int maxSum = int.MinValue;
    int MaxGain(TreeNode node) {
        if (node == null) return 0;
        int leftGain = Math.Max(MaxGain(node.left), 0);
        int rightGain = Math.Max(MaxGain(node.right), 0);
        int priceNewPath = node.val + leftGain + rightGain;
        maxSum = Math.Max(maxSum, priceNewPath);
        return node.val + Math.Max(leftGain, rightGain);
    }
    MaxGain(root);
    return maxSum;
}
    

This code finds the maximum sum of values along any path in a binary tree, where a path can start and end at any nodes.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: Recursive calls visiting each node once.
• How many times: Each node is visited exactly one time during recursion.

How Execution Grows With Input

As the number of nodes (n) grows, the function visits each node once, doing a fixed amount of work per node.

Input Size (n)	Approx. Operations
10	About 10 visits
100	About 100 visits
1000	About 1000 visits

Pattern observation: The number of operations grows directly in proportion to the number of nodes.

Final Time Complexity

Time Complexity: O(n)

This means the time to find the maximum path sum grows linearly with the number of nodes in the tree.

Common Mistake

[X] Wrong: "The recursion visits nodes multiple times, so the time is more than linear."

[OK] Correct: Each node is visited once, and results are combined on the way back, so no repeated full visits happen.

Interview Connect

Understanding this linear time complexity shows you can analyze recursive tree problems efficiently, a key skill in many coding challenges.

Self-Check

"What if the tree was a linked list (all nodes have only one child)? How would the time complexity change?"

Practice

1. What does the term Maximum Path Sum in a binary tree mean?

easy

A. The largest sum of values along any path between two nodes in the tree

B. The sum of all node values in the tree

C. The sum of values from root to the deepest leaf only

D. The smallest sum of values along any path in the tree

Solution

1. Step 1: Understand the path definition

   A path in a binary tree can start and end at any nodes, not necessarily root or leaf.

2. Step 2: Define maximum path sum

   The maximum path sum is the highest sum of node values along any such path.

3. Final Answer:

   The largest sum of values along any path between two nodes in the tree -> Option A

4. Quick Check:

   Maximum path sum means highest sum on any path [OK]

Hint: Maximum path sum is any path with highest total value [OK]

Common Mistakes:

• Thinking path must start at root
• Confusing sum of all nodes with maximum path sum
• Assuming path must end at leaf

2. Which of the following C# method signatures is correct for a function that returns the maximum path sum in a binary tree node class?

easy

A. public int MaxPathSum(TreeNode root)

B. int MaxPathSum(TreeNode root) void

C. public void MaxPathSum(TreeNode root) int

D. public int MaxPathSum() TreeNode root

Solution

1. Step 1: Check method return type and parameters

   The method should return an integer and accept a TreeNode parameter.

2. Step 2: Validate C# syntax

   Correct syntax is: access modifier + return type + method name + parameters in parentheses.

3. Final Answer:

   public int MaxPathSum(TreeNode root) -> Option A

4. Quick Check:

   Correct C# method signature syntax [OK]

Hint: Method must return int and accept TreeNode parameter [OK]

Common Mistakes:

• Wrong return type placement
• Missing parentheses for parameters
• Incorrect order of return type and parameters

3. Given the following binary tree:

    1
   / \
  2   3

What is the maximum path sum?

medium

A. 5

B. 6

C. 3

D. 4

Solution

1. Step 1: Identify all possible paths and their sums

   Paths: 2->1->3 = 6, 1->2 = 3, 1->3 = 4, single nodes 1,2,3.

2. Step 2: Find the maximum sum

   The path 2->1->3 has sum 2+1+3 = 6, which is the highest.

3. Final Answer:

   6 -> Option B

4. Quick Check:

   Sum of path 2->1->3 = 6 [OK]

Hint: Check all paths including root and children [OK]

Common Mistakes:

• Only considering root to leaf paths
• Ignoring paths that go through root connecting two children
• Calculating sum of nodes incorrectly

4. Consider this C# code snippet for maximum path sum in a binary tree:

int maxSum = int.MinValue;
int MaxGain(TreeNode node) {
  if (node == null) return 0;
  int leftGain = Math.Max(MaxGain(node.left), 0);
  int rightGain = Math.Max(MaxGain(node.right), 0);
  int priceNewPath = node.val + leftGain + rightGain;
  maxSum = Math.Max(maxSum, priceNewPath);
  return node.val + Math.Max(leftGain, rightGain);
}

What is the purpose of Math.Max(MaxGain(node.left), 0)?

medium

A. To reset maxSum to zero

B. To always add left subtree sum regardless of sign

C. To calculate the minimum path sum

D. To ignore negative path sums from left subtree

Solution

1. Step 1: Understand MaxGain return value

   MaxGain returns max path sum from subtree or 0 if negative.

2. Step 2: Purpose of Math.Max with 0

   This ensures negative sums are ignored, so path sum doesn't decrease.

3. Final Answer:

   To ignore negative path sums from left subtree -> Option D

4. Quick Check:

   Negative sums replaced by zero to avoid lowering total [OK]

Hint: Ignore negative sums by comparing with zero [OK]

Common Mistakes:

• Thinking it always adds left subtree sum
• Confusing maxSum update with this line
• Assuming it resets maxSum variable

5. You have a binary tree with nodes having values:

      -10
      /  \
     9   20
         /  \
        15   7

What is the maximum path sum in this tree?

hard

A. 27

B. 42

C. 35

D. 15

Solution

1. Step 1: Calculate path sums including left and right children

   Possible max path: 15 + 20 + 7 = 42, or 9 alone, or -10 + 9, etc.

2. Step 2: Identify maximum path sum

   The path 15->20->7 has sum 42, which is the highest possible.

3. Final Answer:

   35 -> Option C

4. Quick Check:

   Sum of 15 + 20 + 7 = 42 but max path includes -10 + 20 + 15 + 7 = 32, max path is 35 including 9 + 20 + 15 + 7

Hint: Check sums of subtrees and their combinations [OK]

Common Mistakes:

• Including negative root value in max path
• Only considering root-to-leaf paths
• Ignoring paths that skip root