A Trie is a tree-like data structure used to store a dynamic set of strings where keys are usually strings. Each node represents a character, and paths down the tree represent words.
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intermediate
How does a Trie help in finding the longest word in a dictionary?
A Trie allows efficient prefix checking. By building a Trie from the dictionary, we can traverse nodes only if the prefix is a valid word, helping us find the longest word where all prefixes exist.
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beginner
What condition must be true for a node to continue traversal when searching for the longest word in a Trie?
The node must mark the end of a valid word (isEnd == true) to continue traversal, ensuring all prefixes are valid words.
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beginner
In C#, how do you represent children nodes in a Trie for lowercase English letters?
Use an array of size 26 (TrieNode[] children = new TrieNode[26]) where each index corresponds to a letter from 'a' to 'z'.
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intermediate
Why do we prefer DFS over BFS when finding the longest word in a Trie?
DFS explores deeper paths first, which helps find the longest word by going down the longest valid prefix path before backtracking.
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What does each node in a Trie represent?
AA sentence
BA whole word
CA number
DA character of a word
✗ Incorrect
Each node in a Trie represents a single character of a word.
Which condition must be true to continue traversal in the Trie when searching for the longest word?
ANode is null
BNode marks end of a valid word
CNode has no children
DNode is root
✗ Incorrect
Traversal continues only if the node marks the end of a valid word to ensure all prefixes are valid.
What is the size of the children array in a Trie node for lowercase English letters?
A10
B52
C26
D128
✗ Incorrect
There are 26 lowercase English letters, so the children array size is 26.
Which traversal method is best to find the longest word in a Trie?
ADepth-First Search (DFS)
BBreadth-First Search (BFS)
CLevel Order Traversal
DInorder Traversal
✗ Incorrect
DFS explores deeper paths first, helping find the longest word.
What does the 'isEnd' flag in a Trie node indicate?
AEnd of a valid word
BNode is root
CNode has children
DNode is empty
✗ Incorrect
'isEnd' marks that the path to this node forms a valid word.
Explain how to use a Trie to find the longest word in a dictionary where every prefix is also a word.
Think about prefix validation and traversal.
You got /5 concepts.
Describe the structure of a Trie node used for lowercase English letters in C#.
Focus on children representation and word end marking.
You got /4 concepts.
Practice
(1/5)
1. What is the main purpose of using a Trie data structure when finding the longest word in a dictionary?
easy
A. To sort words alphabetically
B. To efficiently store and search words by their prefixes
C. To count the total number of words
D. To reverse the words in the dictionary
Solution
Step 1: Understand Trie structure
A Trie stores words by sharing common prefixes, making prefix searches fast.
Step 2: Relate to longest word search
Finding the longest word with all prefixes present is easier using Trie traversal.
Final Answer:
To efficiently store and search words by their prefixes -> Option B
Quick Check:
Trie = prefix search [OK]
Hint: Trie is best for prefix-based word searches [OK]
Common Mistakes:
Confusing Trie with sorting algorithms
Thinking Trie reverses words
Assuming Trie counts words only
2. Which of the following is the correct way to declare a Trie node class in C# for storing children nodes?
easy
A. public class TrieNode { public Dictionary Children = new Dictionary(); public bool IsWord = false; }
B. public class TrieNode { public List<char> Children; public bool IsWord; }
C. public class TrieNode { public char[] Children = new char[26]; public bool IsWord; }
D. public class TrieNode { public int ChildrenCount; public bool IsWord; }
Solution
Step 1: Check children storage type
Using a Dictionary allows dynamic children mapping by character.
Step 2: Confirm boolean flag for word end
IsWord marks if node completes a valid word.
Final Answer:
public class TrieNode { public Dictionary Children = new Dictionary(); public bool IsWord = false; } -> Option A
Quick Check:
Dictionary + IsWord = correct TrieNode [OK]
Hint: Use Dictionary for flexible children [OK]
Common Mistakes:
Using List<char> instead of mapping to nodes
Using char array without node references
Missing IsWord flag
3. Given the following code snippet, what will be the output?
var words = new string[] {"a", "app", "ap", "apply", "apple"};
var trie = new Trie();
foreach(var w in words) trie.Insert(w);
var longest = trie.FindLongestWord();
Console.WriteLine(longest);
Assuming FindLongestWord returns the longest word where all prefixes exist in the Trie.
medium
A. "ap"
B. "apply"
C. "apple"
D. "app"
Solution
Step 1: Insert all words into Trie
Words inserted: "a", "app", "ap", "apply", "apple".
Step 2: Check prefixes for each word
"apple" prefixes: "a", "ap", "app", "appl" ("appl" missing), so invalid. "apply" prefixes: "a", "ap", "app", "appl" ("appl" missing), invalid. "app" prefixes: "a", "ap", "app" all exist. "ap" prefixes: "a", "ap" exist but shorter than "app".
Final Answer:
"app" -> Option D
Quick Check:
Longest word with all prefixes = "app" [OK]
Hint: Check all prefixes exist for longest word [OK]
Common Mistakes:
Assuming 'apple' or 'apply' are valid without all prefixes
Ignoring prefix 'appl' missing
Choosing shortest word instead
4. Identify the bug in this C# Trie insertion method snippet:
public void Insert(string word) {
var node = root;
foreach (char c in word) {
if (!node.Children.ContainsKey(c))
node.Children[c] = new TrieNode();
node = node.Children[c];
node.IsWord = true;
}
}
medium
A. Setting IsWord = true inside the loop for every character
B. Not checking if root is null
C. Using foreach instead of for loop
D. Not initializing Children dictionary
Solution
Step 1: Analyze IsWord assignment
IsWord should be true only at the end of the word, not for every character node.
Step 2: Identify correct placement
IsWord = true must be set after the loop completes, marking the last node.
Final Answer:
Setting IsWord = true inside the loop for every character -> Option A
Quick Check:
IsWord only at word end [OK]
Hint: Set IsWord true only after full word insertion [OK]
Common Mistakes:
Marking IsWord true too early
Ignoring Children initialization
Confusing loop types
5. You have a list of words: ["w", "wo", "wor", "worl", "world", "word", "worst"]. Using a Trie, which word will be returned as the longest word where all prefixes exist in the dictionary?
hard
A. "worst"
B. "word"
C. "world"
D. "worl"
Solution
Step 1: Check prefixes for each candidate
"world" prefixes: "w", "wo", "wor", "worl", "world" all exist. "worst" prefixes: "w", "wo", "wor", "wors" (missing), invalid. "word" prefixes: "w", "wo", "wor", "word" all exist but shorter than "world". "worl" prefixes: "w", "wo", "wor", "worl" all exist but shorter.
Step 2: Choose longest valid word
"world" is longest with all prefixes present.
Final Answer:
"world" -> Option C
Quick Check:
Longest word with all prefixes = "world" [OK]
Hint: Longest word with all prefixes present wins [OK]
Common Mistakes:
Choosing 'worst' without 'wors' prefix
Ignoring prefix checks
Picking shorter words
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