What is the main idea behind the Counting Sort algorithm?
Counting Sort counts how many times each number appears, then uses these counts to place numbers in the right order without comparing them directly.
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beginner
What type of data is Counting Sort best suited for?
Counting Sort works best for sorting integers or objects that can be mapped to integers, especially when the range of input values is not much larger than the number of items.
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intermediate
Why does Counting Sort have a time complexity of O(n + k)?
Because it counts occurrences (k is the range of input values) and then places elements (n is the number of elements), so total work depends on both n and k.
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intermediate
What is a key limitation of Counting Sort?
It uses extra memory proportional to the range of input values, so it can be inefficient if the range is very large compared to the number of elements.
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advanced
How does Counting Sort maintain stability in sorting?
By placing elements into the output array in reverse order using the counts, it keeps elements with the same value in their original order.
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What does Counting Sort use to determine the position of each element?
AComparisons between elements
BA count array that stores the frequency of each value
CSwapping adjacent elements repeatedly
DRecursive division of the array
✗ Incorrect
Counting Sort uses a count array to store how many times each value appears, which helps to place elements directly without comparisons.
Which of these is a requirement for Counting Sort to work correctly?
AInput must be strings
BInput must be already sorted
CInput elements must be integers within a known range
DInput must be floating-point numbers
✗ Incorrect
Counting Sort requires input elements to be integers within a known range to create the count array.
What is the space complexity of Counting Sort relative to the input range?
AO(k)
BO(n)
CO(log n)
DO(1)
✗ Incorrect
Counting Sort uses extra space proportional to k, the range of input values.
How does Counting Sort handle duplicate values?
AIt ignores duplicates
BIt removes duplicates
CIt sorts duplicates randomly
DIt places duplicates next to each other preserving their original order
✗ Incorrect
Counting Sort is stable and places duplicates next to each other in the order they appeared.
Which scenario is Counting Sort NOT ideal for?
ASorting large range integers with few elements
BSorting integers with many duplicates
CSorting characters in a string
DSorting small range integers
✗ Incorrect
Counting Sort is inefficient when the range of input values is very large compared to the number of elements.
Explain how Counting Sort works step-by-step on an array of integers.
Think about counting first, then using counts to find positions.
You got /4 concepts.
Describe the advantages and disadvantages of Counting Sort compared to comparison-based sorts.
Consider speed and memory trade-offs.
You got /4 concepts.
Practice
(1/5)
1. What is the main idea behind the Counting Sort Algorithm?
easy
A. Count the occurrences of each element and use counts to place elements in order
B. Compare each element with every other element to sort
C. Divide the array into halves and sort recursively
D. Swap adjacent elements if they are in wrong order repeatedly
Solution
Step 1: Understand Counting Sort principle
Counting sort counts how many times each value appears in the input.
Step 2: Use counts to place elements
These counts help to directly place elements in the sorted output without comparisons.
Final Answer:
Count the occurrences of each element and use counts to place elements in order -> Option A
Quick Check:
Counting occurrences = A [OK]
Hint: Counting sort uses frequency counts, not comparisons [OK]
Common Mistakes:
Thinking counting sort compares elements
Confusing counting sort with merge sort
Assuming counting sort works on all data types
2. Which of the following is the correct way to declare the count array for counting sort in C# if the input range is from 0 to 9?
easy
A. int[] count = new int[0];
B. int[] count = new int[10];
C. int[] count = new int[11];
D. int count = new int[9];
Solution
Step 1: Determine size of count array
For range 0 to 9, we need 10 slots to count each number.
Step 2: Correct C# syntax for array declaration
Use int[] count = new int[10]; to create an array of size 10.
Final Answer:
int[] count = new int[10]; -> Option B
Quick Check:
Array size = max value + 1 = 10 [OK]
Hint: Count array size = max element value + 1 [OK]
Common Mistakes:
Using size less than max value + 1
Declaring count as single int instead of array
Using incorrect array size causing index errors
3. What will be the output of the following C# code snippet using counting sort on array int[] arr = {4, 2, 2, 8, 3, 3, 1}?
int max = 8;
int[] count = new int[max + 1];
int[] output = new int[arr.Length];
// Count occurrences
foreach (int num in arr) count[num]++;
// Modify count array
for (int i = 1; i <= max; i++) count[i] += count[i - 1];
// Build output
for (int i = arr.Length - 1; i >= 0; i--) {
output[count[arr[i]] - 1] = arr[i];
count[arr[i]]--;
}
// Print output
foreach (int num in output) Console.Write(num + " ");
medium
A. 1 2 2 3 3 4 8
B. 8 4 3 3 2 2 1
C. 1 3 2 2 3 4 8
D. 2 2 3 3 4 8 1
Solution
Step 1: Count occurrences of each number
Count array after counting: [0,1,2,2,1,0,0,0,1]
Step 2: Modify count array to cumulative counts
Cumulative count: [0,1,3,5,6,6,6,6,7]
Step 3: Place elements in output using counts
Placing elements from right to left gives sorted array: 1 2 2 3 3 4 8
Final Answer:
1 2 2 3 3 4 8 -> Option A
Quick Check:
Sorted array = 1 2 2 3 3 4 8 [OK]
Hint: Use cumulative counts to place elements from right [OK]
Common Mistakes:
Not using cumulative counts before placing elements
Placing elements from left to right causing wrong order
Off-by-one errors in indexing output
4. Identify the error in this counting sort code snippet and choose the correct fix:
int max = 5;
int[] count = new int[max];
int[] arr = {1, 4, 3, 2, 5};
foreach (int num in arr) {
count[num]++;
}
medium
A. Initialize count array with zeros explicitly
B. Change foreach loop to for loop
C. Change count array size to max + 1 to avoid index out of range
D. No error, code is correct
Solution
Step 1: Analyze count array size
Count array size is 5, but max value is 5, so index 5 is out of range.
Step 2: Fix by increasing count array size
Count array should be size max + 1 = 6 to include index 5 safely.
Final Answer:
Change count array size to max + 1 to avoid index out of range -> Option C
Quick Check:
Array size = max + 1 to cover all indices [OK]
Hint: Count array size must be max element + 1 [OK]
Common Mistakes:
Using count array size equal to max value only
Ignoring index out of range exceptions
Assuming default array size is enough
5. You have an array int[] arr = {5, 3, 0, 2, 3, 5, 1, 4} and want to sort it using counting sort. However, the array may contain negative numbers in future. How should you modify the counting sort algorithm to handle negative numbers correctly?
hard
A. Sort negative and positive numbers separately and then merge
B. Ignore negative numbers as counting sort only works for positive numbers
C. Use a dictionary instead of an array for counts
D. Shift all numbers by adding the absolute value of the minimum negative number before counting
Solution
Step 1: Identify problem with negative numbers
Counting sort uses array indices as counts, negative indices are invalid.
Step 2: Shift numbers to non-negative range
Add absolute value of minimum negative number to all elements to make them non-negative.
Step 3: Apply counting sort on shifted values
Sort shifted values, then shift back to original values after sorting.
Final Answer:
Shift all numbers by adding the absolute value of the minimum negative number before counting -> Option D
Quick Check:
Shift negatives to zero or above before counting [OK]
Hint: Shift negatives to zero or above before counting [OK]
Common Mistakes:
Trying to use negative indices in count array
Ignoring negative values in input
Using dictionary without sorting logic
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