Why Binary Search on Answer Technique in DSA C#?

The Big Idea

What if you could find the perfect answer hidden in a huge range without checking every single option?

The Scenario

Imagine you want to find the smallest size of a box that can hold all your items, but you only know the total number of items and their sizes. You try different box sizes one by one, starting from very small to very large, checking each time if all items fit.

The Problem

This trial-and-error way is slow and tiring because you might check many sizes unnecessarily. It's easy to get stuck testing sizes that are too small or too big without a clear plan, wasting time and effort.

The Solution

The Binary Search on Answer technique helps by smartly guessing the box size. It picks a middle size, checks if it works, and then narrows down the search range by half each time. This way, you quickly zoom in on the smallest size that fits all items without testing every possibility.

Before vs After

✗ Before

int size = 1;
while (!CanFit(size)) {
    size++;
}
return size;

✓ After

int low = 1, high = maxPossibleSize;
while (low < high) {
    int mid = low + (high - low) / 2;
    if (CanFit(mid)) high = mid;
    else low = mid + 1;
}
return low;

What It Enables

This technique lets you solve problems that ask for the best or smallest solution efficiently, even when the answer is hidden in a large range of possibilities.

Real Life Example

Suppose you want to cut wood planks into pieces of equal length to get at least a certain number of pieces. Binary Search on Answer helps find the longest piece length possible without cutting too short or too long.

Key Takeaways

Manual checking of all answers is slow and inefficient.

Binary Search on Answer narrows down the search smartly by halving the range each time.

It is useful for optimization problems where the answer lies within a range.

Practice

1. What is the main idea behind the Binary Search on Answer technique?

easy

A. We sort the input array and then perform a binary search on the sorted array.

B. We guess an answer and check if it satisfies the problem, then adjust the guess using binary search.

C. We use binary search to find the maximum element in an unsorted array.

D. We apply binary search to find the first occurrence of a target value in a list.

Solution

1. Step 1: Understand the technique

   Binary Search on Answer guesses a possible solution and verifies if it meets the problem's conditions. If valid, adjust the guess (smaller/larger) using binary search to find the optimal answer.

2. Final Answer:

   We guess an answer and check if it satisfies the problem, then adjust the guess using binary search. -> Option B

3. Quick Check:

   Guess and verify with binary search = B [OK]

Hint: Guess answer, check condition, adjust guess with binary search [OK]

Common Mistakes:

• Confusing binary search on answer with normal binary search on array
• Thinking it only works on sorted arrays
• Not verifying the guessed answer properly

2. Which of the following is the correct C# syntax to start a binary search on answer between low and high?

easy

A. do { int mid = (low - high) / 2; } while (low < high);

B. for (int mid = low; mid <= high; mid++) { }

C. if (low < high) { int mid = low + high; }

D. while (low <= high) { int mid = (low + high) / 2; }

Solution

1. Step 1: Identify correct loop and mid calculation

   The binary search loop uses while (low <= high) and mid = (low + high) / 2 with integer division.

2. Final Answer:

   while (low <= high) { int mid = (low + high) / 2; } -> Option D

3. Quick Check:

   Correct binary search loop syntax = A [OK]

Hint: Use while(low <= high) and mid = (low + high) / 2 [OK]

Common Mistakes:

• Using for loop instead of while
• Incorrect mid calculation like (low - high)/2
• Using if instead of loop

3. Consider the following C# code snippet using binary search on answer to find minimum maximum load:

int low = 10, high = 50;
while (low <= high) {
  int mid = (low + high) / 2;
  if (IsPossible(mid))
    high = mid - 1;
  else
    low = mid + 1;
}
Console.WriteLine(low);

If IsPossible(30) returns true and IsPossible(20) returns false, what will be printed?

medium

A. 10

B. 30

C. 21

D. 20

Solution

1. Step 1: Trace binary search behavior

   IsPossible(mid) true means valid (try smaller, high=mid-1); false means invalid (low=mid+1). Given IsPossible(30)=true, IsPossible(20)=false, assuming monotonicity the search converges to smallest valid at 21.

2. Final Answer:

   21 -> Option C

3. Quick Check:

   Minimum valid answer after binary search = 21 [OK]

Hint: Answer is lowest valid mid after binary search ends [OK]

Common Mistakes:

• Printing high instead of low after loop
• Confusing true/false meaning of IsPossible
• Not updating low and high correctly

4. The following code tries to find the minimum maximum load using binary search on answer. What is the bug?

int low = 0, high = maxLoad;
while (low < high) {
  int mid = (low + high) / 2;
  if (IsPossible(mid))
    low = mid;
  else
    high = mid - 1;
}
Console.WriteLine(low);

medium

A. When IsPossible(mid) is true, 'low' should be set to 'mid + 1' instead of 'mid'.

B. When IsPossible(mid) is true, 'high' should be set to 'mid - 1' instead of 'low'.

C. The condition should be 'while (low <= high)' instead of 'while (low < high)'.

D. The mid calculation should be 'mid = low + (high - low) / 2' to avoid overflow.

Solution

1. Step 1: Identify incorrect update causing infinite loop

   When IsPossible(mid) true, low = mid risks no progress (infinite loop if low == mid); should set low = mid + 1 to advance.

2. Final Answer:

   When IsPossible(mid) is true, 'low' should be set to 'mid + 1' instead of 'mid'. -> Option A

3. Quick Check:

   Increment low by 1 to avoid infinite loop [OK]

Hint: Increment low by 1 when condition true to avoid infinite loop [OK]

Common Mistakes:

• Not incrementing low causing infinite loop
• Confusing when to move low or high
• Ignoring loop condition correctness

5. You want to split an array of weights into k contiguous subarrays so that the maximum sum among these subarrays is minimized. Which approach correctly uses binary search on answer to solve this?

hard

A. Binary search between max weight and sum of all weights; check if array can be split into ≤ k parts with max sum ≤ mid.

B. Sort the array and binary search for the kth largest weight.

C. Use binary search on the array indices to find the split points directly.

D. Apply binary search on the number of subarrays from 1 to k.

Solution

1. Step 1: Define search space and feasibility check

   Binary search from max weight (min possible max sum) to total sum; for mid, check if can split into ≤ k contiguous subarrays each with sum ≤ mid. If yes, try smaller mid; else larger.

2. Final Answer:

   Binary search between max weight and sum of all weights; check if array can be split into ≤ k parts with max sum ≤ mid. -> Option A

3. Quick Check:

   Search answer range and verify splits ≤ k [OK]

Hint: Search between max element and total sum, check splits ≤ k [OK]

Common Mistakes:

• Binary searching on indices instead of answer range
• Not checking contiguous subarray sums properly
• Sorting array unnecessarily