What if you could find the odd one out instantly without checking every item?
Why Find the Only Non Repeating Element Using XOR in DSA C#?
Imagine you have a box of socks where every sock has a matching pair except one. You want to find that single sock without checking each pair one by one.
Checking each sock manually to find the one without a pair takes a lot of time and can easily lead to mistakes, especially if the box is large. You might lose track or accidentally count a sock twice.
Using XOR, you can quickly find the single sock without a pair by combining all socks in a way that pairs cancel out, leaving only the unique one. This method is fast and error-free.
int FindUnique(int[] socks) {
for (int i = 0; i < socks.Length; i++) {
int count = 0;
for (int j = 0; j < socks.Length; j++) {
if (socks[i] == socks[j]) count++;
}
if (count == 1) return socks[i];
}
return -1;
}int FindUnique(int[] socks) {
int uniqueSock = 0;
foreach (int sock in socks) {
uniqueSock ^= sock;
}
return uniqueSock;
}This technique lets you instantly find the one unique item in a group where all others repeat, saving time and effort.
Finding the only unpaired sock in a laundry basket full of pairs without sorting or comparing each sock manually.
Manual checking is slow and error-prone.
XOR cancels out pairs and reveals the unique element.
This method is efficient and simple to implement.
Practice
Solution
Step 1: Understand XOR behavior on identical bits
XOR returns 0 when both bits are the same (0 XOR 0 = 0, 1 XOR 1 = 0).Step 2: Apply XOR on identical numbers
Since all bits are identical, XOR of a number with itself results in 0.Final Answer:
It returns 0 -> Option DQuick Check:
5 XOR 5 = 0 [OK]
- Thinking XOR returns the number itself
- Confusing XOR with OR or AND
- Assuming XOR causes errors with identical inputs
result to zero in C#?Solution
Step 1: Recall C# variable initialization syntax
In C#, variables are initialized using single equals sign (=) for assignment.Step 2: Check each option
int result = 0; uses correct syntax:int result = 0;. Others use invalid operators.Final Answer:
int result = 0; -> Option CQuick Check:
Correct assignment uses = in C# [OK]
- Using double equals (==) for assignment
- Using := or => which are invalid here
- Missing semicolon at the end
int[] arr = {2, 3, 2, 4, 3};
int result = 0;
foreach (int num in arr) {
result ^= num;
}
Console.WriteLine(result);Solution
Step 1: XOR all elements in the array
Start with result = 0. XOR with 2 -> 0^2=2, then 3 -> 2^3=1, then 2 -> 1^2=3, then 4 -> 3^4=7, then 3 -> 7^3=4.Step 2: Final XOR result is the non-repeating element
The final result after XORing all elements is 4, which is the only non-repeating number.Final Answer:
4 -> Option AQuick Check:
Only 4 appears once, XOR result = 4 [OK]
- Not XORing all elements correctly
- Confusing XOR with addition
- Assuming first unique number is output
int[] arr = {1, 2, 1, 3, 2};
int result;
foreach (int num in arr) {
result ^= num;
}
Console.WriteLine(result);Solution
Step 1: Check variable initialization
The variable 'result' is declared but not initialized before using '^=' operator, which causes a compile-time error.Step 2: Correct initialization needed
Initialize 'result' to 0 before the loop to correctly accumulate XOR results.Final Answer:
Variable 'result' is not initialized before XOR operation -> Option AQuick Check:
Uninitialized variables cause errors in C# [OK]
- Forgetting to initialize variables
- Misunderstanding '^=' operator usage
- Assuming Console.WriteLine can't print ints
Solution
Step 1: Understand XOR single pass advantage
XOR operation can be done in one pass over the array without extra memory, as duplicates cancel out.Step 2: Avoid extra memory by not using sorting or dictionaries
Sorting or dictionaries use extra memory or time, which is inefficient for large arrays.Final Answer:
Use XOR in a single pass without extra memory -> Option BQuick Check:
XOR single pass = memory efficient [OK]
- Using extra data structures unnecessarily
- Sorting which costs extra time and memory
- Copying arrays wastes memory
Ready to prove it?
Pass the test and this pattern moves unknown
