Find the Only Non Repeating Element Using XOR in DSA C# - Time & Space Complexity
We want to know how fast we can find the single element that does not repeat in a list.
How does the time needed grow as the list gets bigger?
Analyze the time complexity of the following code snippet.
int FindUnique(int[] nums) {
int result = 0;
foreach (int num in nums) {
result ^= num;
}
return result;
}
This code finds the only number that appears once while all others appear twice, using XOR.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: One loop that goes through each number once.
- How many times: Exactly once for each element in the list.
As the list grows, the number of steps grows in a straight line with it.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 10 XOR operations |
| 100 | 100 XOR operations |
| 1000 | 1000 XOR operations |
Pattern observation: The work grows directly with the number of elements.
Time Complexity: O(n)
This means the time to find the unique number grows in direct proportion to the list size.
[X] Wrong: "Using XOR means checking pairs, so it takes more than one pass or more than linear time."
[OK] Correct: XOR combines all numbers in one pass, so it only needs to look at each number once, making it very fast.
Understanding this XOR trick shows you can solve problems efficiently by using simple operations smartly, a skill valued in coding interviews.
"What if the list had two unique numbers instead of one? How would the time complexity change?"
Practice
Solution
Step 1: Understand XOR behavior on identical bits
XOR returns 0 when both bits are the same (0 XOR 0 = 0, 1 XOR 1 = 0).Step 2: Apply XOR on identical numbers
Since all bits are identical, XOR of a number with itself results in 0.Final Answer:
It returns 0 -> Option DQuick Check:
5 XOR 5 = 0 [OK]
- Thinking XOR returns the number itself
- Confusing XOR with OR or AND
- Assuming XOR causes errors with identical inputs
result to zero in C#?Solution
Step 1: Recall C# variable initialization syntax
In C#, variables are initialized using single equals sign (=) for assignment.Step 2: Check each option
int result = 0; uses correct syntax:int result = 0;. Others use invalid operators.Final Answer:
int result = 0; -> Option CQuick Check:
Correct assignment uses = in C# [OK]
- Using double equals (==) for assignment
- Using := or => which are invalid here
- Missing semicolon at the end
int[] arr = {2, 3, 2, 4, 3};
int result = 0;
foreach (int num in arr) {
result ^= num;
}
Console.WriteLine(result);Solution
Step 1: XOR all elements in the array
Start with result = 0. XOR with 2 -> 0^2=2, then 3 -> 2^3=1, then 2 -> 1^2=3, then 4 -> 3^4=7, then 3 -> 7^3=4.Step 2: Final XOR result is the non-repeating element
The final result after XORing all elements is 4, which is the only non-repeating number.Final Answer:
4 -> Option AQuick Check:
Only 4 appears once, XOR result = 4 [OK]
- Not XORing all elements correctly
- Confusing XOR with addition
- Assuming first unique number is output
int[] arr = {1, 2, 1, 3, 2};
int result;
foreach (int num in arr) {
result ^= num;
}
Console.WriteLine(result);Solution
Step 1: Check variable initialization
The variable 'result' is declared but not initialized before using '^=' operator, which causes a compile-time error.Step 2: Correct initialization needed
Initialize 'result' to 0 before the loop to correctly accumulate XOR results.Final Answer:
Variable 'result' is not initialized before XOR operation -> Option AQuick Check:
Uninitialized variables cause errors in C# [OK]
- Forgetting to initialize variables
- Misunderstanding '^=' operator usage
- Assuming Console.WriteLine can't print ints
Solution
Step 1: Understand XOR single pass advantage
XOR operation can be done in one pass over the array without extra memory, as duplicates cancel out.Step 2: Avoid extra memory by not using sorting or dictionaries
Sorting or dictionaries use extra memory or time, which is inefficient for large arrays.Final Answer:
Use XOR in a single pass without extra memory -> Option BQuick Check:
XOR single pass = memory efficient [OK]
- Using extra data structures unnecessarily
- Sorting which costs extra time and memory
- Copying arrays wastes memory
Ready to prove it?
Pass the test and this pattern moves unknown
