Complete the code to initialize the result variable to zero.
int result = [1];We start with zero because XOR with zero leaves the number unchanged.
Complete the code to XOR each element in the array with the result.
foreach (int num in arr) { result = result [1] num; }
XOR operator (^) is used to find the unique element by cancelling out duplicates.
Fix the error in the return statement to return the unique element.
return [1];
The variable 'result' holds the unique non-repeating element after XOR operations.
Fill both blanks to complete the method signature and the loop over the array.
public static int FindUnique([1] arr) { int result = 0; foreach ([2] num in arr) { result ^= num; } return result; }
The method takes an array of integers (int[]) and iterates over each integer (int) in the array.
Fill all three blanks to complete the dictionary comprehension that counts occurrences and filters unique elements.
var counts = new Dictionary<int, int>(); foreach (var num in arr) { if (!counts.ContainsKey([1])) { counts[[2]] = 0; } counts[num] += 1; } var unique = counts.Where(kv => kv.Value == [3]).Select(kv => kv.Key).ToList();
We check if 'num' is in counts, initialize counts[num] to 0, then count occurrences. Unique elements have count 1 after initialization and increment.
