Tabulation is a bottom-up approach in dynamic programming where we solve smaller subproblems first and store their results in a table (usually an array) to build up solutions to bigger problems.
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beginner
How does Tabulation differ from Memoization?
Tabulation solves problems iteratively from the smallest subproblem up, filling a table. Memoization solves problems recursively and stores results to avoid repeated work.
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beginner
In Tabulation, why do we start filling the table from the base cases?
Base cases are the simplest subproblems with known answers. Starting from them ensures that when solving bigger subproblems, the smaller required answers are already computed and available.
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intermediate
What is the time complexity advantage of using Tabulation?
Tabulation avoids repeated calculations by storing results in a table, so each subproblem is solved once. This usually reduces exponential time to polynomial time.
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beginner
Give an example problem where Tabulation Bottom Up DP is useful.
The Fibonacci sequence calculation is a classic example. Using tabulation, we fill an array from the first two Fibonacci numbers up to the desired number, avoiding repeated recursive calls.
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What does Tabulation in DP primarily use to store intermediate results?
AA queue
BAn array or table
CA stack
DA linked list
✗ Incorrect
Tabulation uses an array or table to store results of subproblems for bottom-up computation.
Which approach solves subproblems recursively and stores results to avoid recomputation?
AMemoization
BBrute force
CGreedy
DTabulation
✗ Incorrect
Memoization is the top-down recursive approach that caches results.
In Tabulation, what is the first step to solve a problem?
ACall the recursive function
BSolve the biggest subproblem first
CInitialize the table with base case values
DSort the input data
✗ Incorrect
Tabulation starts by initializing base cases in the table.
What is a key benefit of Tabulation over naive recursion?
ADoes not require base cases
BUses less memory
CRuns slower
DAvoids repeated calculations
✗ Incorrect
Tabulation avoids repeated calculations by storing subproblem results.
Which problem is commonly solved using Tabulation Bottom Up DP?
AFinding Fibonacci numbers
BSorting an array
CBinary search
DDepth-first search
✗ Incorrect
Fibonacci sequence calculation is a classic example for tabulation.
Explain how Tabulation Bottom Up DP works using the Fibonacci sequence as an example.
Think about how you can build Fibonacci numbers from the first two numbers upwards.
You got /4 concepts.
Describe the main differences between Tabulation and Memoization in dynamic programming.
Consider how each approach solves subproblems and stores answers.
You got /5 concepts.
Practice
(1/5)
1. What is the main idea behind Tabulation Bottom Up DP in dynamic programming?
easy
A. Build a table from the smallest subproblems up to the main problem
B. Solve the problem by recursion without storing results
C. Use random guesses to find the solution
D. Start solving from the biggest problem and break it down
Solution
Step 1: Understand the DP approach
Tabulation means filling a table starting from the smallest subproblems.
Step 2: Compare with other methods
Unlike recursion without storage, tabulation avoids repeated work by building up solutions.
Final Answer:
Build a table from the smallest subproblems up to the main problem -> Option A
Quick Check:
Bottom Up DP = Build table from small to big [OK]
Hint: Think: solve small parts first, then bigger ones [OK]
Common Mistakes:
Confusing tabulation with recursion without memoization
Thinking tabulation starts from the biggest problem
Assuming tabulation guesses solutions randomly
2. Which of the following is the correct way to declare a DP table for Fibonacci numbers using tabulation in C?
easy
A. int dp[] = {0};
B. int dp[100] = {0};
C. int dp = 100;
D. int dp(100);
Solution
Step 1: Check C array declaration syntax
In C, arrays are declared with size and type, e.g., int dp[100];
Step 2: Identify correct initialization
int dp[100] = {0}; declares an int array of size 100 initialized to zero, suitable for DP table.
Final Answer:
int dp[100] = {0}; -> Option B
Quick Check:
C arrays need size and type [OK]
Hint: Use int dp[size] = {0} for zero-initialized arrays [OK]
Common Mistakes:
Using parentheses instead of brackets for arrays
Not specifying array size
Assigning integer to array variable
3. What will be the output of the following C code using bottom-up DP to find Fibonacci number for n=5?
#include
int main() {
int n = 5;
int dp[6] = {0};
dp[0] = 0;
dp[1] = 1;
for(int i = 2; i <= n; i++) {
dp[i] = dp[i-1] + dp[i-2];
}
printf("%d", dp[n]);
return 0;
}
medium
A. 13
B. 8
C. 3
D. 5
Solution
Step 1: Trace DP table filling
dp[0]=0, dp[1]=1; then dp[2]=1, dp[3]=2, dp[4]=3, dp[5]=5.
4. Find the error in this bottom-up DP code snippet for Fibonacci numbers:
int fib(int n) {
int dp[n+1];
dp[0] = 0;
dp[1] = 1;
for(int i = 1; i <= n; i++) {
dp[i] = dp[i-1] + dp[i-2];
}
return dp[n];
}
medium
A. Array dp is not initialized to zero
B. Return statement should be dp[n-1]
C. Loop starts at 1 instead of 2 causing invalid access
D. Function should return void
Solution
Step 1: Check loop start index
Loop starts at i=1, but dp[i-2] for i=1 is dp[-1], invalid index.
Step 2: Correct loop start
Loop should start at i=2 to avoid negative index access.
Final Answer:
Loop starts at 1 instead of 2 causing invalid access -> Option C
Quick Check:
Loop must start at 2 to access dp[i-2] safely [OK]
Hint: Start loop at 2 for Fibonacci tabulation [OK]
Common Mistakes:
Starting loop at 1 causing negative index
Ignoring array bounds in DP
Returning wrong dp index
5. Given the problem to find the minimum number of coins to make amount 7 using coins {1, 3, 4} with bottom-up DP, what is the minimum number of coins needed?
Use this approach:
int coins[] = {1, 3, 4};
int amount = 7;
int dp[8];
dp[0] = 0;
for (int i = 1; i <= amount; i++) {
dp[i] = INT_MAX;
for (int j = 0; j < 3; j++) {
if (coins[j] <= i && dp[i - coins[j]] != INT_MAX) {
dp[i] = dp[i] < dp[i - coins[j]] + 1 ? dp[i] : dp[i - coins[j]] + 1;
}
}
}
printf("%d", dp[amount]);
hard
A. 2
B. 4
C. 3
D. 5
Solution
Step 1: Calculate dp values step-by-step
dp[0]=0
For i=1: dp[1]=1 (coin 1)
For i=2: dp[2]=2 (1+1)
For i=3: dp[3]=1 (coin 3)
For i=4: dp[4]=1 (coin 4)
For i=5: dp[5]=2 (4+1)
For i=6: dp[6]=2 (3+3)
For i=7: dp[7]=2 (3+4)
Step 2: Identify minimum coins for amount 7
Minimum coins needed for 7 is 2.
Final Answer:
2 -> Option A
Quick Check:
Minimum coins for 7 = 2 [OK]
Hint: Build dp from 0 to amount, pick min coins each step [OK]
Common Mistakes:
Not updating dp[i] with minimum value
Ignoring INT_MAX checks causing wrong results
Confusing coin values and indices
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