Jump Game Problem in DSA C - Time & Space Complexity

Time Complexity: Jump Game Problem

O(n)

Understanding Time Complexity

We want to know how the time needed to solve the Jump Game grows as the input array gets bigger.

Specifically, how many steps does the algorithm take to decide if we can reach the end?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

bool canJump(int* nums, int numsSize) {
    int maxReach = 0;
    for (int i = 0; i < numsSize; i++) {
        if (i > maxReach) return false;
        if (i + nums[i] > maxReach) {
            maxReach = i + nums[i];
        }
    }
    return true;
}
    

This code checks if you can jump from the start to the end of the array, where each number tells the max jump length from that position.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: A single loop that goes through the array once.
• How many times: The loop runs once for each element, so exactly n times where n is the array size.

How Execution Grows With Input

As the array size grows, the number of steps grows directly with it.

Input Size (n)	Approx. Operations
10	About 10 checks and updates
100	About 100 checks and updates
1000	About 1000 checks and updates

Pattern observation: The work grows evenly as the input grows; doubling the input doubles the work.

Final Time Complexity

Time Complexity: O(n)

This means the time to decide if you can reach the end grows in a straight line with the size of the input array.

Common Mistake

[X] Wrong: "Because there is a loop inside a condition, the time complexity is more than linear."

[OK] Correct: The loop runs only once through the array, and the condition inside does not cause extra loops; it just checks a value, so the overall work is still linear.

Interview Connect

Understanding this linear time solution shows you can analyze and optimize problems efficiently, a key skill in real coding challenges.

Self-Check

"What if we used recursion to try every jump path? How would the time complexity change?"

Practice

1. What is the main goal of the Jump Game problem?

easy

A. Calculate the minimum jump length required to reach the last index

B. Determine if you can reach the last index from the first index by jumping

C. Count the total number of jumps needed to reach the end

D. Find the maximum jump length from the first index

Solution

1. Step 1: Understand the problem statement

   The Jump Game problem asks if it is possible to move from the first index to the last index by jumping forward using the values at each index as maximum jump lengths.

2. Step 2: Identify the goal

   The goal is to check if the last index is reachable, not to count jumps or find maximum jump length.

3. Final Answer:

   Determine if you can reach the last index from the first index by jumping -> Option B

4. Quick Check:

   Goal = Reach last index [OK]

Hint: Focus on reachability, not jump counts or lengths [OK]

Common Mistakes:

• Confusing maximum jump length with reachability
• Trying to count jumps instead of checking possibility
• Assuming jumps can go backward

2. Which of the following is the correct syntax to declare an integer array nums of size 5 in C for the Jump Game problem?

easy

A. int[] nums = new int[5];

B. int nums = [5];

C. int nums(5);

D. int nums[5];

Solution

1. Step 1: Recall C array declaration syntax

   In C, arrays are declared by specifying the type, name, and size in square brackets, like int nums[5];.

2. Step 2: Check each option

   int nums[5]; matches correct C syntax. int nums = [5]; uses invalid assignment. int nums(5); uses parentheses which is incorrect. int[] nums = new int[5]; is Java syntax.

3. Final Answer:

   int nums[5]; -> Option D

4. Quick Check:

   C array syntax = int nums[5]; [OK]

Hint: Use type name[size] for arrays in C [OK]

Common Mistakes:

• Using Java or C++ style array declarations
• Using parentheses instead of square brackets
• Assigning array size with equals sign

3. What will be the output of the following C code snippet for the Jump Game problem?

int nums[] = {2, 3, 1, 1, 4};
int n = 5;
int maxReach = 0;
for (int i = 0; i < n; i++) {
    if (i > maxReach) {
        printf("false\n");
        return 0;
    }
    if (i + nums[i] > maxReach) {
        maxReach = i + nums[i];
    }
}
printf("true\n");

medium

A. true

B. false

C. Compilation error

D. Runtime error

Solution

1. Step 1: Trace the loop and maxReach updates

   Start with maxReach=0. At i=0, maxReach = max(0, 0+2)=2. i=1 ≤ 2, maxReach = max(2,1+3)=4. i=2 ≤ 4, maxReach = max(4,2+1)=4. i=3 ≤ 4, maxReach = max(4,3+1)=4. i=4 ≤ 4, maxReach = max(4,4+4)=8.

2. Step 2: Check if loop completes without returning false

   Since i never exceeds maxReach, loop completes and prints "true".

3. Final Answer:

   true -> Option A

4. Quick Check:

   maxReach covers all indices = true [OK]

Hint: Check if current index exceeds max reachable index [OK]

Common Mistakes:

• Stopping early without updating maxReach
• Confusing index with jump length
• Assuming false if maxReach equals index

4. Identify the bug in the following C code snippet for the Jump Game problem:

int canJump(int* nums, int n) {
    int maxReach = 0;
    for (int i = 0; i <= n; i++) {
        if (i > maxReach) return 0;
        if (i + nums[i] > maxReach) maxReach = i + nums[i];
    }
    return 1;
}

medium

A. Return values should be swapped (1 for false, 0 for true)

B. maxReach should be initialized to -1

C. Loop condition should be i < n, not i <= n

D. nums array should be declared inside the function

Solution

1. Step 1: Analyze the loop condition

   The loop runs from i=0 to i<=n, which means it accesses nums[n], an out-of-bounds index causing undefined behavior.

2. Step 2: Correct the loop condition

   The loop should run while i < n to avoid accessing beyond the array.

3. Final Answer:

   Loop condition should be i < n, not i <= n -> Option C

4. Quick Check:

   Array index in bounds = i < n [OK]

Hint: Loop up to n-1 to avoid out-of-bounds access [OK]

Common Mistakes:

• Using <= instead of < in loop condition
• Ignoring array boundary checks
• Incorrect return values for boolean

5. Given the array nums = {3, 2, 1, 0, 4}, why does the standard greedy Jump Game algorithm return false for reachability?

hard

A. Because index 3 has a jump length of 0, blocking further progress

B. Because the array length is less than 5

C. Because the first element is too large

D. Because the last element is unreachable due to negative jumps

Solution

1. Step 1: Trace jumps from start

   Start at index 0 with jump length 3, maxReach = 3. Indices 1, 2, 3 are reachable. At index 3, jump length is 0, so maxReach stays 3.

2. Step 2: Check if last index is reachable

   Last index is 4, which is beyond maxReach 3, so it is unreachable, causing the algorithm to return false.

3. Final Answer:

   Because index 3 has a jump length of 0, blocking further progress -> Option A

4. Quick Check:

   Zero jump blocks path = false [OK]

Hint: Zero jump at reachable index blocks reaching the end [OK]

Common Mistakes:

• Ignoring zero jump blocking
• Assuming array length affects reachability
• Thinking negative jumps exist in problem